Advanced Placement Calculus Graphical Numerical Algebraic Sixth Edition High School Binding Copyright 2020
Advanced Placement Calculus Graphical Numerical Algebraic Sixth Edition High School Binding Copyright 2020
6th Edition
ISBN: 9781418300203
Author: Prentice Hall
Publisher: Prentice Hall
Question
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Chapter 10, Problem 9RE

a)

To determine

To find: The equation for the tangent to the curve x=12tant , y=12sect at the point corresponding to t=π3 .

a)

Expert Solution
Check Mark

Answer to Problem 9RE

The equation for the tangent to the curve x=12tant , y=12sect at the point corresponding to t=π3 is:

  y1=23x32 .

Explanation of Solution

Given information:

The parametric equation of the curve is: x=12tant , y=12sect and t=π3 .

Formula used:

Application of the Chain rule of Differentiation:

  dydt=dydxdxdtdydx=dydtdxdt

Tangents of Parametric curves:

When a curve is defined by parametric equations x=f(t) , y=f(t) , the slope dydx of the tangent to the curve is computed using the Chain Rule (since, the curve is not defined as a function of x):

  dydx=dydtdxdt

Point-slope form of a line:

The equation of a line whose slope is m and which passes through a point x1,y1 is given as: yy1=mxx1 .

Calculation:

The equation of the curve is:

  x=12tanty=12sect

Substitute t=π3 in the equations to obtain the point corresponding to t=π3 :

  x=12tanπ3x=123x=32y=12secπ3y=122y=1

The point corresponding to t=π3 is 32,1 .

Differentiate the equations of the curve with respect to t :

  x=12tantdxdt=ddt12tantdxdt=12ddttantdxdt=12sec2t

And,

  y=12sectdydt=ddt12sectdydt=12ddtsectdydt=12secttant

Substitute dxdt=12sec2t and dydt=12secttant inthe formula for the slope of the tangent to the curve x=12tant , y=12sect to obtain:

  dydx=dydtdxdtdydx=12secttant12sec2tdydx=tantsectdydx=sintcost1cost

Simplify further to obtain:

  dydx=sintcos2t

At the point corresponding to t=π3 , the slope of the tangent is given by:

  m=dydxπ3m==sinπ3cos2π3m=32122m=3214m=23

Substitute m=23 in the formula of a line in point-slope form to obtain the equation of the tangent to the curve x=12tant , y=12sect at the point 32,1:

  y1=23x32

Thus,

The equation for the tangent to the curve x=12tant , y=12sect at the point corresponding to t=π3 is: y1=23x32 .

b)

To determine

To find:The value of d2ydx2 at the point corresponding to t=π3 .

b)

Expert Solution
Check Mark

Answer to Problem 9RE

The value of d2ydx2 at the point corresponding to t=π3 is 7.

Explanation of Solution

Given information:

The parametric equation of the curve is: x=12tant , y=12sect and t=π3 .

Formula used:

Application of the Chain rule of Derivatives:

  dydt=dydxdxdtdydx=dydtdxdt

Chain Rule for Higher Derivatives:

For the second derivative, d2ydx2=ddxdydx=ddtdydxdxdt

Quotient rule of Derivatives:

  ddxuv=vdudxudvdxv2

Calculation:

The equation of the curve is:

  x=12tanty=12sect

Differentiate the equations of the curve with respect to t .

  x=12tantdxdt=ddt12tantdxdt=12ddttantdxdt=12sec2t

And,

  y=12sectdydt=ddt12sectdydt=12ddtsectdydt=12secttant

Apply the Chain rule of Differentiation to obtain:

  dydx=dydtdxdtdydx=12secttant12sec2tdydx=tantsectdydx=sintcost1cost

Simplify further to obtain:

  dydx=sintcos2t

Substitute dydx=sintcos2t and dxdt=12sec2t, and apply Chain rule for Higher Derivatives to obtain:

  d2ydx2=ddtsintcos2t12sec2t

Apply the Quotient rule of derivatives to compute the value of d2ydx2 :

  d2ydx2=cos2tddtsintsintddtcos2tcos2t212sec2td2ydx2=cos2tcostsint2costsintcos4t12cos2td2ydx2=cos3tsint2costsintcos4t12cos2td2ydx2=costcos2t+2sin2tcos4t2cos2t

Simplify further:

  d2ydx2=2cos2t+2sin2tcostd2ydx2=2cos2t+sin2t+sin2tcost

Apply the Trigonometric Identity cos2θ+sin2θ=1 :

  d2ydx2=21+sin2tcost

The value of d2ydx2 at the point corresponding to t=π3 is:

  d2ydx2π3=21+sin2π3cosπ3d2ydx2π3=21+32212d2ydx2π3=21+3412d2ydx2π3=4×74d2ydx2π3=7

Thus, the value of d2ydx2 at the point corresponding to t=π3 is 7 .

Chapter 10 Solutions

Advanced Placement Calculus Graphical Numerical Algebraic Sixth Edition High School Binding Copyright 2020

Ch. 10.1 - Prob. 1ECh. 10.1 - Prob. 2ECh. 10.1 - Prob. 3ECh. 10.1 - Prob. 4ECh. 10.1 - Prob. 5ECh. 10.1 - Prob. 6ECh. 10.1 - Prob. 7ECh. 10.1 - Prob. 8ECh. 10.1 - Prob. 9ECh. 10.1 - Prob. 10ECh. 10.1 - Prob. 11ECh. 10.1 - Prob. 12ECh. 10.1 - Prob. 13ECh. 10.1 - Prob. 14ECh. 10.1 - Prob. 15ECh. 10.1 - Prob. 16ECh. 10.1 - Prob. 17ECh. 10.1 - Prob. 18ECh. 10.1 - Prob. 19ECh. 10.1 - Prob. 20ECh. 10.1 - Prob. 21ECh. 10.1 - Prob. 22ECh. 10.1 - Prob. 23ECh. 10.1 - Prob. 24ECh. 10.1 - Prob. 25ECh. 10.1 - Prob. 26ECh. 10.1 - Prob. 27ECh. 10.1 - Prob. 28ECh. 10.1 - Prob. 29ECh. 10.1 - Prob. 30ECh. 10.1 - Prob. 31ECh. 10.1 - Prob. 32ECh. 10.1 - Prob. 33ECh. 10.1 - Prob. 34ECh. 10.1 - Prob. 35ECh. 10.1 - Prob. 36ECh. 10.1 - Prob. 37ECh. 10.1 - Prob. 38ECh. 10.1 - Prob. 39ECh. 10.1 - Prob. 40ECh. 10.1 - Prob. 41ECh. 10.1 - Prob. 42ECh. 10.1 - Prob. 43ECh. 10.1 - Prob. 44ECh. 10.1 - Prob. 45ECh. 10.1 - Prob. 46ECh. 10.1 - Prob. 47ECh. 10.1 - Prob. 48ECh. 10.1 - Prob. 49ECh. 10.1 - Prob. 50ECh. 10.1 - Prob. 51ECh. 10.1 - Prob. 52ECh. 10.1 - Prob. 53ECh. 10.1 - Prob. 54ECh. 10.1 - Prob. 55ECh. 10.1 - Prob. 56ECh. 10.1 - Prob. 57ECh. 10.1 - Prob. 58ECh. 10.1 - Prob. 59ECh. 10.1 - Prob. 60ECh. 10.2 - Prob. 1QRCh. 10.2 - Prob. 2QRCh. 10.2 - Prob. 3QRCh. 10.2 - Prob. 4QRCh. 10.2 - Prob. 5QRCh. 10.2 - Prob. 6QRCh. 10.2 - Prob. 7QRCh. 10.2 - Prob. 8QRCh. 10.2 - Prob. 9QRCh. 10.2 - Prob. 10QRCh. 10.2 - Prob. 1ECh. 10.2 - Prob. 2ECh. 10.2 - Prob. 3ECh. 10.2 - Prob. 4ECh. 10.2 - Prob. 5ECh. 10.2 - Prob. 6ECh. 10.2 - Prob. 7ECh. 10.2 - Prob. 8ECh. 10.2 - Prob. 9ECh. 10.2 - Prob. 10ECh. 10.2 - Prob. 11ECh. 10.2 - Prob. 12ECh. 10.2 - Prob. 13ECh. 10.2 - Prob. 14ECh. 10.2 - Prob. 15ECh. 10.2 - Prob. 16ECh. 10.2 - Prob. 17ECh. 10.2 - Prob. 18ECh. 10.2 - Prob. 19ECh. 10.2 - Prob. 20ECh. 10.2 - Prob. 21ECh. 10.2 - Prob. 22ECh. 10.2 - Prob. 23ECh. 10.2 - Prob. 24ECh. 10.2 - Prob. 25ECh. 10.2 - Prob. 26ECh. 10.2 - Prob. 27ECh. 10.2 - Prob. 28ECh. 10.2 - Prob. 29ECh. 10.2 - Prob. 30ECh. 10.2 - Prob. 31ECh. 10.2 - Prob. 32ECh. 10.2 - Prob. 33ECh. 10.2 - Prob. 34ECh. 10.2 - Prob. 35ECh. 10.2 - Prob. 36ECh. 10.2 - Prob. 37ECh. 10.2 - Prob. 38ECh. 10.2 - Prob. 39ECh. 10.2 - Prob. 40ECh. 10.2 - Prob. 41ECh. 10.2 - Prob. 42ECh. 10.2 - Prob. 43ECh. 10.2 - Prob. 44ECh. 10.2 - Prob. 45ECh. 10.2 - Prob. 46ECh. 10.2 - Prob. 47ECh. 10.2 - Prob. 48ECh. 10.2 - Prob. 49ECh. 10.2 - Prob. 50ECh. 10.2 - Prob. 51ECh. 10.2 - Prob. 52ECh. 10.2 - Prob. 53ECh. 10.2 - Prob. 54ECh. 10.2 - Prob. 55ECh. 10.2 - Prob. 56ECh. 10.2 - Prob. 57ECh. 10.2 - Prob. 58ECh. 10.2 - Prob. 59ECh. 10.2 - Prob. 60ECh. 10.2 - Prob. 61ECh. 10.2 - Prob. 62ECh. 10.2 - Prob. 63ECh. 10.2 - Prob. 64ECh. 10.2 - Prob. 65ECh. 10.3 - Prob. 1QRCh. 10.3 - Prob. 2QRCh. 10.3 - Prob. 3QRCh. 10.3 - Prob. 4QRCh. 10.3 - Prob. 5QRCh. 10.3 - Prob. 6QRCh. 10.3 - Prob. 7QRCh. 10.3 - Prob. 8QRCh. 10.3 - Prob. 9QRCh. 10.3 - Prob. 10QRCh. 10.3 - Prob. 1ECh. 10.3 - Prob. 2ECh. 10.3 - Prob. 3ECh. 10.3 - Prob. 4ECh. 10.3 - Prob. 5ECh. 10.3 - Prob. 6ECh. 10.3 - Prob. 7ECh. 10.3 - Prob. 8ECh. 10.3 - Prob. 9ECh. 10.3 - Prob. 10ECh. 10.3 - Prob. 11ECh. 10.3 - Prob. 12ECh. 10.3 - Prob. 13ECh. 10.3 - Prob. 14ECh. 10.3 - Prob. 15ECh. 10.3 - Prob. 16ECh. 10.3 - Prob. 17ECh. 10.3 - Prob. 18ECh. 10.3 - Prob. 19ECh. 10.3 - Prob. 20ECh. 10.3 - Prob. 21ECh. 10.3 - Prob. 22ECh. 10.3 - Prob. 23ECh. 10.3 - Prob. 24ECh. 10.3 - Prob. 25ECh. 10.3 - Prob. 26ECh. 10.3 - Prob. 27ECh. 10.3 - Prob. 28ECh. 10.3 - Prob. 29ECh. 10.3 - Prob. 30ECh. 10.3 - Prob. 31ECh. 10.3 - Prob. 32ECh. 10.3 - Prob. 33ECh. 10.3 - Prob. 34ECh. 10.3 - Prob. 35ECh. 10.3 - Prob. 36ECh. 10.3 - Prob. 37ECh. 10.3 - Prob. 38ECh. 10.3 - Prob. 39ECh. 10.3 - Prob. 40ECh. 10.3 - Prob. 41ECh. 10.3 - Prob. 42ECh. 10.3 - Prob. 43ECh. 10.3 - Prob. 44ECh. 10.3 - Prob. 45ECh. 10.3 - Prob. 46ECh. 10.3 - Prob. 47ECh. 10.3 - Prob. 48ECh. 10.3 - Prob. 49ECh. 10.3 - Prob. 50ECh. 10.3 - Prob. 51ECh. 10.3 - Prob. 52ECh. 10.3 - Prob. 53ECh. 10.3 - Prob. 54ECh. 10.3 - Prob. 55ECh. 10.3 - Prob. 56ECh. 10.3 - Prob. 57ECh. 10.3 - Prob. 58ECh. 10.3 - Prob. 59ECh. 10.3 - Prob. 60ECh. 10.3 - Prob. 61ECh. 10.3 - Prob. 62ECh. 10.3 - Prob. 63ECh. 10.3 - Prob. 64ECh. 10.3 - Prob. 65ECh. 10.3 - Prob. 66ECh. 10.3 - Prob. 67ECh. 10.3 - Prob. 68ECh. 10.3 - Prob. 69ECh. 10.3 - Prob. 70ECh. 10.3 - Prob. 71ECh. 10.3 - Prob. 72ECh. 10.3 - Prob. 73ECh. 10.3 - Prob. 74ECh. 10.3 - Prob. 75ECh. 10.3 - Prob. 76ECh. 10.3 - Prob. 77ECh. 10.3 - Prob. 78ECh. 10.3 - Prob. 79ECh. 10.3 - Prob. 80ECh. 10.3 - Prob. 1QQCh. 10.3 - Prob. 2QQCh. 10.3 - Prob. 3QQCh. 10.3 - Prob. 4QQCh. 10 - Prob. 1RWDTCh. 10 - Prob. 2RWDTCh. 10 - Prob. 3RWDTCh. 10 - Prob. 4RWDTCh. 10 - Prob. 5RWDTCh. 10 - Prob. 6RWDTCh. 10 - Prob. 7RWDTCh. 10 - Prob. 8RWDTCh. 10 - Prob. 9RWDTCh. 10 - Prob. 10RWDTCh. 10 - Prob. 1RECh. 10 - Prob. 2RECh. 10 - Prob. 3RECh. 10 - Prob. 4RECh. 10 - Prob. 5RECh. 10 - Prob. 6RECh. 10 - Prob. 7RECh. 10 - Prob. 8RECh. 10 - Prob. 9RECh. 10 - Prob. 10RECh. 10 - Prob. 11RECh. 10 - Prob. 12RECh. 10 - Prob. 13RECh. 10 - Prob. 14RECh. 10 - Prob. 15RECh. 10 - Prob. 16RECh. 10 - Prob. 17RECh. 10 - Prob. 18RECh. 10 - Prob. 19RECh. 10 - Prob. 20RECh. 10 - Prob. 21RECh. 10 - Prob. 22RECh. 10 - Prob. 23RECh. 10 - Prob. 24RECh. 10 - Prob. 25RECh. 10 - Prob. 26RECh. 10 - Prob. 27RECh. 10 - Prob. 28RECh. 10 - Prob. 29RECh. 10 - Prob. 30RECh. 10 - Prob. 31RECh. 10 - Prob. 32RECh. 10 - Prob. 33RECh. 10 - Prob. 34RECh. 10 - Prob. 35RECh. 10 - Prob. 36RECh. 10 - Prob. 37RECh. 10 - Prob. 38RECh. 10 - Prob. 39RECh. 10 - Prob. 40RECh. 10 - Prob. 41RECh. 10 - Prob. 42RECh. 10 - Prob. 43RECh. 10 - Prob. 44RECh. 10 - Prob. 45RECh. 10 - Prob. 46RECh. 10 - Prob. 47RECh. 10 - Prob. 48RECh. 10 - Prob. 49RECh. 10 - Prob. 50RECh. 10 - Prob. 51EPCh. 10 - Prob. 52EPCh. 10 - Prob. 53EP
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