Chapter 10, Problem 61AP

с. d. СнЗ Сизена=-4=4 Cla H Eget3 над f. e. H-C=C-CH3 + 285 → H-C=C-CH3+2не H-C=C-CH3 + Nanta» g+ CH₂ CH₂-G = G-C₁₂-G=CH₂ + 2HI→ H H H AL

The IR (infrared) spectra of two pure compounds (0.010 M compound A in solvent and 0.010 M compound B in solvent) are given. The pathlength of the cell is 1.00 cm. The y-axis in the spectra is transmittance rather than absorption, so that the wavenumbers at which there is a dip in the curve correspond to absorption peaks. A mixture of A and B in unknown concentrations gave a percent transmittance of 49.8% at 2976 cm¹ and 44.9% at 3030 cm-1 Wavenumber 0.010 M A 0.010 M B Unknown 3030 cm-1 35.0% 93.0% 44.9% 2976 cm-¹ 76.0% 42.0% 49.8% What are the concentrations of A and B in the unknown sample? Transmittance (%) 100 90 80 70 60 50 40 2976 cm-1 30 3030 cm-1 20 Pure A 10 Pure B 0 3040 2990 Wavenumber (cm-1) 2940 2890

synthesize 1-propyne starting with propane.