BIOLOGY:CONCEPTS+APPL.(LOOSELEAF)
10th Edition
ISBN: 9781305967359
Author: STARR
Publisher: CENGAGE L
expand_more
expand_more
format_list_bulleted
Textbook Question
Chapter 10, Problem 4CT
The photos below show flowers from two Arabidopsis plants. One plant is wild-type (unmutated); the other carries a mutation in one of its ABC floral identity genes. This mutation causes sepals and petals to form instead of stamens and carpels. Refer to Figure 10.7 to decide which gene (A, B, or C) has been inactivated by the mutation.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
You conduct an experiment to study the expression of the S protein through the
tissues of your favorite plant (Arabidopsis thaliana). The morning of the experiment
you inject in the leaves a messenger RNA that codes for the synthesis of a single
protein made of two parts that are attached to each other: the functional S protein
and a red fluorescent protein tag (RFP). You perform two cross sections of the same
root, one section at the start of the experiment (time = Oh; corresponding to the time
of injection) and one section in the afternoon (time = 8h). Through fluorescent
microscopy you observe a change in the coloration inside the cells of the root's
central tissues (as indicated by the arrows): from no coloration (time = Oh) to red
(time = 8h).
• The cells of the central tissues in the roots do not have nuclei or ribosomes.
How can you explain this change of coloration? Please provide a cellular
feature that can lead to this.
• What is one advantage of using an RFP-tag in an mRNA?…
Can you answer part a-c if its true or false
a) the AP3 and PI show auto- and cross-regulatory interactions, as well as they form obligate heterodimers to carry out the B class gene function. Therefore, if there is no PI expression, AP3 expression alone is not sufficient for establishing the petal and stamen identities.
b) Angiosperm is a group of plants whose seeds are borne within a mature ovary (fruit).
c) The organ in different organisms under every variety of forms and functions due to evolutionary development from the same or a corresponding part in a common ancestor is homologous.
You are a developmental geneticist studying flowering time variation in Arabidopsis. You perform a
mutagenesis screen to identify mutants in the photoperiod pathway. You conduct the screen and
find two different plants that show the same mutant phenotype. You then use a complementation
test. What is the predicted outcome of this test if both phenotypes are caused by mutations in
separate genes?
recover the wild type phenotype
overexpress the gene
O recover the mutant phenotype
Chapter 10 Solutions
BIOLOGY:CONCEPTS+APPL.(LOOSELEAF)
Ch. 10 - Gene expression does not vary by ________. a. cell...Ch. 10 - Binding of _______ to _______ in DNA can increase...Ch. 10 - Prob. 3SACh. 10 - Mechanisms that govern gene expression do not...Ch. 10 - Muscle cells differ from bone cells because they...Ch. 10 - Prob. 6SACh. 10 - Prob. 7SACh. 10 - Prob. 8SACh. 10 - Which of the following includes all of the others?...Ch. 10 - Prob. 10SA
Ch. 10 - Prob. 11SACh. 10 - Prob. 12SACh. 10 - Prob. 13SACh. 10 - True or false? Gene expression patterns can be...Ch. 10 - Match the terms with the most suitable...Ch. 10 - Why are some genes expressed and some not?Ch. 10 - Do the same mechanism of governing gene expression...Ch. 10 - Prob. 3CTCh. 10 - The photos below show flowers from two Arabidopsis...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- In Figure 6-1,a. what do the yellow stars represent?b. explain in your own words why the heterozygote isfunctionally wild typearrow_forwardIn roses, the synthesis of red pigment is produced by two steps in a pathway. gene O magenta intermediate - gene P colorless intermediate- red pigment What would the phenotype be of a plant homozygous for a null mutation of gene P? What would the phenotype be of a plant homozygous for a null mutation of gene Q? What would the phenotype be of a plant homozygous for null mutations of genes P and Q? magenta red Match a genotype to each strain. colorless Strain P locus Q locus homozygous null mutation of gene P homozygous null mutation of gene Q homozygous null mutations of genes P and Q Answer Bank plp PIP What F2 ratio is expected from crossing a plant that is homozygous for a null mutation of gene P with a plant that is homozygous for a null mutation of gene Q? Assume independent assortment. 9 colorless : 4 magenta : 3 red 9 red : 4 colorless : 3 magenta O 9 red : 4 magenta : 3 colorlessarrow_forwardTrace the genetic steps in the development of a peanut plant that isresistant to insect larvae (table given). (Hint: You need to useAgrobacterium.)arrow_forward
- You are a developmental geneticist studying flowering time variation in Arabidopsis. You perform a mutagenesis screen to identify mutants in the photoperiod pathway. Given what you know about photoperiodism in Arabidopsis, what phenotype are you looking for and under what photoperiodic conditions would you perform the experiment? delayed flowering in long days delayed flowering in short days same flowering in short days early flowering in short days same flowering in long days early flowering in long daysarrow_forwardCx is a member of the family of connexin genes that encode the proteins of gap junction intercellular channels. Cx proteins in one cell form hemi-channels in the plasma membrane. Hemi-channels in adjacent cells dock to form complete intercellular channels through which ions and small molecules diffuse from cell to cell. Distinct Cx mutations were identified in three different families, F1, F2 and F3, affected by the same disease. To study their functional properties, normal (wild type, wt) and mutant (m) Cx proteins were expressed in cultured cells. Translation of the proteins was checked (Fig. 3). A extracellular EC 1 SM TM 1 membrane 2 3 4 F10 intracellular N F2 EC 2 F3 oricand c B 42 kDa C 42 kDa 35 kDa Control wt m-F1 m-F2 PM C PM C PM C PM C Western blot anti-Cx Control wt PM C m-F1 PM C PM C = Metabolically labelled m-F2 PM C m-F3 PM C m-F3 PM C WSEY Fig. 3 mont (A). Membrane topology of Cx protein indicating positions of mutations. Cx is an integral membrane protein with 4…arrow_forwardYou are studying a plant with tissue comprising both green and white sectors. You wish to decide whether this phenomenon is due (1) to a chloroplast mutation of the type considered in this chapter or (2) to a dominant nuclear mutation that inhibits chlorophyll production and is present only in certain tissue layers of the plant as a mosaic. Outline the experimental approach that you would use to resolve this problem.arrow_forward
- Three haploid fungal mutants that require compound W for growth were isolated. Each mutant contains a recessive allele in a single gene. Three compounds (A, B and C) in the biosynthetic pathway to W are known, but their order in the pathway is unknown. Each compound is tested for its ability to support the growth of each of the three mutants. Phenotypes of all of the three mutants are shown in the following table (“+" indicates growth, "-" indicates no growth). A C W Mutant 1 Mutant 2 Mutant 3 What would be the phenotype of a haploid mutant that contains both mutant alleles in mutant 2 and 3? Phenotype refers to growth or absence of growth on compounds A, B, C and WN. O Like mutant 1 O Like mutant 2 Like mutant 3 O Like wild typearrow_forwardBased on Figure 17-35, write a sentence stating howtranslocation can lead to cancer. Can you think of another genetic cause of cancer?arrow_forwardWhen considering the cause of the disease in a patient who is the child of an inbred couple, it was found that 4 enzymes in the lysosome were inactivated. When comparing the amino acid sequences of these four enzymes with the wild-type enzyme, no difference was found in the number and arrangement of amino acids. Given mutations that may be the cause of the patient's disease above.arrow_forward
- Yeast cells are grown with galactose as the sole carbon source and ATP levels are abundant. Describe and diagram how GAL1 gene expression will be changed (or unchanged) in 1) a ΔGal3 mutant and 2) a ΔGal4 mutant in comparison to WT. (Δ is a symbol for deletion.) WT: ΔGal3: ΔGal4:arrow_forwardThe genetic alteration responsible for sickle-cell anemia in humans involves: a transition mutation from A to G, substituting glutamic acid for valine in a-globin a transversion mutation from T to A, substituting valine for glutamic acid in b-globin a transition mutation from T to C, substituting valine for glutamic acid in b-globin a transversion mutation from G to C, substituting glutamic acid for valine in a-globin a frameshift mutation of one ATC codon, removing glutamic acid from b-globinarrow_forwardFor a haploid fungus, the starting point in the biosynthesis of the amino acid arginine is Compound X, which is always present in and absorbed from the environment. The arginine biosynthetic pathway is: Enzyme A Enzyme B Enzyme Ç Compound X It is know that genes encoding enzymes A and C are on two different chromosomes. Compound Y Compound Z- Arginine A mutant strain of genotype a (lacking only enzyme A) is crossed to a mutant strain of genotype c (lacking only enzyme C) to generate a diploid strain. Sporulation (i.e. meiosis) is subsequently induced in the resulting diploid strain. What proportion of the spores (haploids formed by sporulation) is expected to grow on medium without arginine but supplemented with Compound Y? O 100% 50% 0% 25%arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Biology: The Dynamic Science (MindTap Course List)BiologyISBN:9781305389892Author:Peter J. Russell, Paul E. Hertz, Beverly McMillanPublisher:Cengage Learning
Biology: The Dynamic Science (MindTap Course List)
Biology
ISBN:9781305389892
Author:Peter J. Russell, Paul E. Hertz, Beverly McMillan
Publisher:Cengage Learning
Embryology | Fertilization, Cleavage, Blastulation; Author: Ninja Nerd;https://www.youtube.com/watch?v=8-KF0rnhKTU;License: Standard YouTube License, CC-BY