Schaum's Outline of College Physics, Twelfth Edition (Schaum's Outlines)
12th Edition
ISBN: 9781259587399
Author: Eugene Hecht
Publisher: McGraw-Hill Education
expand_more
expand_more
format_list_bulleted
Videos
Textbook Question
Chapter 10, Problem 44SP
A cord 3.0 m long is wrapped around the axle of a wheel. The cord is pulled with a constant force of 40 N, and the wheel revolves as a result. When the cord leaves the axle, the wheel is rotating at 2.0 rev/s. Determine the moment of inertia of the wheel and axle. Neglect friction. [Hint: The easiest solution is obtained via the energy method.]
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
The centrifuge rotor has a moment of inertia of 3.75 x 10 ^ -2 kg m2. How much energy is required to bring
it from rest to 8250 rev / min?
A 22.0 kg wheel, essentially a thin hoop with radius 1.70 m, is rotating at 297 rev/min. It must be brought to a stop in 28.0 s. (a) How much work must be done to stop it? (b) What is the required average power? Give absolute values for both parts.
A ceiling fan of moment of inertia 30 kg m'
rotates about its own axis at a speed of 120
r.p.m. under the action of an electric motor of
power 62.8 watt. If electric power is cut off,
how many rotations will it complete before
coming to rest?
Chapter 10 Solutions
Schaum's Outline of College Physics, Twelfth Edition (Schaum's Outlines)
Ch. 10 - 29. A homogeneous cylinder of radius R and mass m...Ch. 10 - 30. A uniform homogeneous solid disk lies in a...Ch. 10 - 31. A uniform homogeneous solid disk having a...Ch. 10 - 32. Picture a rigid rod of length L having...Ch. 10 - 33. Suppose we put a third tiny sphere of mass m...Ch. 10 - 34. Consider the arrangement in the previous...Ch. 10 - 10.35 [I] A flat uniform homogeneous disk is...Ch. 10 - 10.36 [II] A uniform homogeneous rod of length L...Ch. 10 - 10.37 [II] A uniform homogeneous rod of length L...Ch. 10 - Prob. 38SP
Ch. 10 - 10.39 [I] A force of 200 N acts tangentially on...Ch. 10 - 10.40 [I] An 8.0-kg wheel has a radius of gyration...Ch. 10 - 10.41 [II] Determine the constant torque that must...Ch. 10 - 10.42 [II] A 4.0-kg wheel of 20-cm radius of...Ch. 10 - 10.43 [II] Compute the rotational KE of a 25-kg...Ch. 10 - 10.44 [II] A cord 3.0 m long is wrapped around the...Ch. 10 - 45. A 500-g wheel that has a moment of inertia of...Ch. 10 - 46. When 100 J of work is done on a stationary...Ch. 10 - 47. A 5.0-kg wheel with a radius of gyration of 20...Ch. 10 - 48. An electric motor runs at 900 rpm and delivers...Ch. 10 - 49. The driving side of a belt has a tension of...Ch. 10 - 10.50 [III] A 25-kg wheel has a radius of 40 cm...Ch. 10 - 10.51 [III] A wheel and axle having a total moment...Ch. 10 - 52. A solid uniform homogeneous disk of radius r...Ch. 10 - 53. A 20-kg solid disk (I = Mr2) rolls on a...Ch. 10 - 10.54 [II] A 6.0-kg bowling ball starts from rest...Ch. 10 - 10.55 [II] A tiny solid ball rolls without...Ch. 10 - 10.56 [I] Compute the radius of gyration of a...Ch. 10 - 10.57 [I] Figure 10-13 shows four masses that are...Ch. 10 - 10.58 [I] Determine the moment of inertia (a) of a...Ch. 10 - 10.59 [II] Rod OA in Fig. 10-14 is a meterstick....Ch. 10 - Prob. 60SPCh. 10 - 10.61 [II] A large horizontal disk is rotating on...Ch. 10 - 10.63 [II] A 90-kg person stands at the edge of a...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- A uniform solid cylinder with a radius of 5 cm and a mass of 5.6 kg is rotating about its center with an angular speed of 35.2 rpm. What is its kinetic energy in J? Express the answer to 3 decimal places.arrow_forwardA wind turbine has a moment of inertia of 2.8*10^11 kg*m^2 . How much energy is required to speed it up from rest to 3 rpm?arrow_forwardA centrifuge rotor has a moment of inertia of 2.85×10−2 kg⋅m2 . How much energy is required to bring it from rest to 9280 rpm ?arrow_forward
- A rigid body with a cylindrical cross-section is released from the top of a 31° incline. It rolls 13.0 m to the bottom in 3.13 s. Find the moment of inertia of the body in terms of its mass m and radius r. (Assume I is in kg · m2, m is in kilograms, and r is in meters. Do not include units in your answer.)arrow_forwardTwo masses, mA = 34.0 kg and mB = 38.0 kg , are connected by a rope that hangs over a pulley (as in the figure). The pulley is a uniform cylinder of radius 0.381 m and mass 3.1 kg. Initially mA is on the ground and mB rests 2.4 m above the ground. If the system is released, use conservation of energy to determine the speed of mB just before it strikes the ground. Assume the pulley bearing is frictionless.arrow_forwardA metal can containing condensed mushroom soup has mass 230 g, height 10.6 cm and diameter 6.38 cm. It is placed at rest on its side at the top of a 3.00-m-long incline that is at 26.0° to the horizontal and is then released to roll straight down. It reaches the bottom of the incline after 1.50 s. (a) Assuming mechanical energy conservation, calculate the moment of inertia of the can. I = kg m m² · (b) Which pieces of data, if any, are unnecessary for calculating the solution? (Select all that apply.) the mass of the can the height of the can the angle of the incline the time the can takes to reach the bottom none of these 1 (c) Why can't the moment of inertia be calculated from I = 2 mr² mr2 for the cylindrical can?arrow_forward
- A certain centrifuge has a rotational inertia of 5.00 kg*m². It is rotating at 2200 RPM when the power is turned off. the centrifuge is then brought to rest by axle friction while it turns through 4800 revolutions. The magnitude of the axle friction torque is 8.80 m*N O 5040 m*N O 10.9 m*N O 4.40 m*N O0.700 m*Narrow_forwardA wheel with rotational inertia 46 kg.m2 is mounted on a fixed, frictionless axle. The angular speed of the wheel is increased from zero to 43 rad/s in 19-s. What is the AVERAGE power input to the wheel during this time interval?arrow_forwardA block of mass 0.74 kg is suspended by a string which is wrapped so that it is at a radius of 0.069 m from the center of a pulley. The moment of inertia of the pulley is 4.90×10-3 kg·m2. There is friction as the pulley turns. The block starts from rest, and its speed after it has traveled downwards a distance of D= 0.77 m, is 2.133 m/s. Calculate the amount of energy dissipated up to that point.arrow_forward
- A rotating flywheel can be used to store energy. If it is required to store 1.00 × 10^5 J of energy when rotating at 400 rad/s, what is the moment of inertial of the wheel in kg∙m2?arrow_forwardA metal can containing condensed mushroom soup has mass 230 g, height 11.0 cm and diameter 6.38 cm. It is placed at rest on its side at the top of a 3.00-m-long incline that is at 28.0° to the horizontal and is then released to roll straight down. It reaches the bottom of the incline after 1.50 s. (a) Assuming mechanical energy conservation, calculate the moment of inertia of the can. I = kg • m2 (b) Which pieces of data, if any, are unnecessary for calculating the solution? (Select all that apply.) O the mass of the can V the height of the can O the angle of the incline O the time the can takes to reach the bottom O none of these (c) Why can't the moment of inertia be calculated from I = for the cylindrical can?arrow_forwardA metal can containing condensed mushroom soup has mass 220 g, height 10.0 cm and diameter 6.38 cm. It is placed at rest on its side at the top of a 3.00-m-long incline that is at 26.0° to the horizontal and is then released to roll straight down. It reaches the bottom of the incline after 1.50 s. (a) Assuming mechanical energy conservation, calculate the moment of inertia of the can. I = Your response differs from the correct answer by more than 10%. Double check your calculations. kg · m2 (b) Which pieces of data, if any, are unnecessary for calculating the solution? (Select all that apply.) O the mass of the can O the height of the can O the angle of the incline O the time the can takes to reach the bottom O none of these (c) Why can't the moment of inertia be calculated from I = -mr? for the cylindrical can? This answer has not been graded yet. Need Help? Read Itarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
Rotational Kinetic Energy; Author: AK LECTURES;https://www.youtube.com/watch?v=s5P3DGdyimI;License: Standard YouTube License, CC-BY