Glencoe Chemistry: Matter and Change, Student Edition
Glencoe Chemistry: Matter and Change, Student Edition
1st Edition
ISBN: 9780076774609
Author: McGraw-Hill Education
Publisher: MCGRAW-HILL HIGHER EDUCATION
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Chapter 10, Problem 210A
Interpretation Introduction

Interpretation:

The formula and name of the compound formed by the combination of barium and chlorine should be determine.

Concept introduction:

The compounds which are formed between two elements are known as binary compounds and if one element is metal and another is non-metal, then the binary compound is made up of ions, known as binary ionic compounds.

The formation of ion takes place either by lose of electron(s) to make cations or by addition of electron(s) to make anions. Generally, the addition or loss of electron(s) takes place in an atom to have eight electrons in their valence shell said to be octet rule.

The formula of ionic compounds is determined by crisscross method. In this method:

  • The corresponding charges are assigned to the metal and non-metal.
  • The number of charges becomes the subscript of atom.
  • All ionic compounds are neutral.
  • The subscripts are written in the lowest possible ratio.

For naming the compound:

First, the name of the metal should be identified with the help of its symbol.

The name of the non-metal should be identified with the help of its symbol and it is modified to end in “−ide”

Expert Solution
Check Mark

Answer to Problem 210A

The formula and name of the compound formed by the combination of barium and chlorine is BaCl2 and barium chloride respectively.

Explanation of Solution

The electronic configuration of barium, Ba is [Xe]6s2 and of chlorine, Cl is [Ne]3s23p5. Thus, in order to attain the stability (nearest noble gas configuration) the Ba atom loses 2 electrons and forms Ba2+ ion whereas two Cl atoms accepts this electrons and forms 2 Cl ions. So, the formula of the compound is BaCl2.

Naming the compound:

Name of the metal Ba is barium.

Name of the non-metal Cl is chlorine.

Since, chlorine is a non-metal, therefore it is modified to end in “−ide”.

Thus, the name of the compound is barium chloride.

Interpretation Introduction

Interpretation:

The formula and name of the compound formed by the combination of aluminum and selenium should be determine.

Concept introduction:

The compounds which are formed between two elements are known as binary compounds and if one element is metal and another is non-metal, then the binary compound is made up of ions, known as binary ionic compounds.

The formation of ion takes place either by lose of electron(s) to make cations or by addition of electron(s) to make anions. Generally, the addition or loss of electron(s) takes place in an atom to have eight electrons in their valence shell said to be octet rule.

The formula of ionic compounds is determined by crisscross method. In this method:

  • The corresponding charges are assigned to the metal and non-metal.
  • The number of charges becomes the subscript of atom.
  • All ionic compounds are neutral.
  • The subscripts are written in the lowest possible ratio.

For naming the compound:

First, the name of the metal should be identified with the help of its symbol.

The name of the non-metal should be identified with the help of its symbol and it is modified to end in “−ide”

Expert Solution
Check Mark

Answer to Problem 210A

The formula and name of the compound formed by the combination of aluminum and selenium is Al2Se3 and aluminum selenide respectively.

Explanation of Solution

The electronic configuration of aluminum, Al is [Ne]3s23p1 and of selenium, Se is [Ar]3d104s24p4. Thus, in order to attain the stability (nearest noble gas configuration) the Al atom loses 3 electrons and forms Al3+ ion whereas Se atom accepts two electrons and forms Se2 ions. So, the formula of the electrically neutral compound is Al2Se3.

Naming the compound:

Name of the metal Al is aluminum.

Name of the non-metal Se is selenium.

Since, selenium is a non-metal, therefore it is modified to end in “−ide”.

Thus, the name of the compound is aluminum selenide.

Interpretation Introduction

Interpretation:

The formula and name of the compound formed by the combination of calcium and phosphorus should be determine.

Concept introduction:

The compounds which are formed between two elements are known as binary compounds and if one element is metal and another is non-metal, then the binary compound is made up of ions, known as binary ionic compounds.

The formation of ion takes place either by lose of electron(s) to make cations or by addition of electron(s) to make anions. Generally, the addition or loss of electron(s) takes place in an atom to have eight electrons in their valence shell said to be octet rule.

The formula of ionic compounds is determined by crisscross method. In this method:

  • The corresponding charges are assigned to the metal and non-metal.
  • The number of charges becomes the subscript of atom.
  • All ionic compounds are neutral.
  • The subscripts are written in the lowest possible ratio.

For naming the compound:

First, the name of the metal should be identified with the help of its symbol.

The name of the non-metal should be identified with the help of its symbol and it is modified to end in “−ide”

Expert Solution
Check Mark

Answer to Problem 210A

The formula and name of the compound formed by the combination of calcium and phosphorus is Ca3P2 and calcium phosphide respectively.

Explanation of Solution

The electronic configuration of calcium, Ca is [Ar]4s2 and of phosphorus, P is [Ne]3s23p3. Thus, in order to attain the stability (nearest noble gas configuration) the Ca atom loses 2 electrons and forms Ca2+ ion whereas P atom accepts three electrons and forms P3 ions. So, the formula of the electrically neutral compound is Ca3P2.

Naming the compound:

Name of the metal Ca is calcium.

Name of the non-metal P is phosphorus.

Since, phosphorus is a non-metal, therefore it is modified to end in “−ide”.

Thus, the name of the compound is calcium phosphide.

Chapter 10 Solutions

Glencoe Chemistry: Matter and Change, Student Edition

Ch. 10.1 - Prob. 11SSCCh. 10.1 - Prob. 12SSCCh. 10.1 - Prob. 13SSCCh. 10.1 - Prob. 14SSCCh. 10.2 - Prob. 15PPCh. 10.2 - Prob. 16PPCh. 10.2 - Prob. 17PPCh. 10.2 - Prob. 18PPCh. 10.2 - Prob. 19PPCh. 10.2 - Prob. 20PPCh. 10.2 - Prob. 21PPCh. 10.2 - Prob. 22SSCCh. 10.2 - Prob. 23SSCCh. 10.2 - Prob. 24SSCCh. 10.2 - Prob. 25SSCCh. 10.2 - Prob. 26SSCCh. 10.2 - Prob. 27SSCCh. 10.2 - Prob. 28SSCCh. 10.3 - Prob. 29PPCh. 10.3 - Prob. 30PPCh. 10.3 - Prob. 31PPCh. 10.3 - Prob. 32PPCh. 10.3 - Prob. 33PPCh. 10.3 - Prob. 34PPCh. 10.3 - Prob. 35PPCh. 10.3 - Prob. 36PPCh. 10.3 - Prob. 37PPCh. 10.3 - Prob. 38PPCh. 10.3 - Prob. 39PPCh. 10.3 - Prob. 40PPCh. 10.3 - Prob. 41PPCh. 10.3 - Prob. 42PPCh. 10.3 - Prob. 43PPCh. 10.3 - Prob. 44PPCh. 10.3 - Prob. 45PPCh. 10.3 - Prob. 46PPCh. 10.3 - Prob. 47SSCCh. 10.3 - Prob. 48SSCCh. 10.3 - Prob. 49SSCCh. 10.3 - Prob. 50SSCCh. 10.3 - Prob. 51SSCCh. 10.3 - Prob. 52SSCCh. 10.3 - Prob. 53SSCCh. 10.4 - Prob. 54PPCh. 10.4 - Prob. 55PPCh. 10.4 - Prob. 56PPCh. 10.4 - Prob. 57PPCh. 10.4 - Prob. 58PPCh. 10.4 - Prob. 59PPCh. 10.4 - Prob. 60PPCh. 10.4 - Prob. 61PPCh. 10.4 - Prob. 62PPCh. 10.4 - Prob. 63PPCh. 10.4 - Prob. 64PPCh. 10.4 - Prob. 65PPCh. 10.4 - Prob. 66PPCh. 10.4 - Prob. 67SSCCh. 10.4 - Prob. 68SSCCh. 10.4 - Prob. 69SSCCh. 10.4 - Prob. 70SSCCh. 10.4 - Prob. 71SSCCh. 10.4 - Prob. 72SSCCh. 10.4 - Prob. 73SSCCh. 10.5 - Prob. 74PPCh. 10.5 - Prob. 75PPCh. 10.5 - Prob. 76SSCCh. 10.5 - Prob. 77SSCCh. 10.5 - Prob. 78SSCCh. 10.5 - Prob. 79SSCCh. 10.5 - Prob. 80SSCCh. 10.5 - Prob. 81SSCCh. 10.5 - Prob. 82SSCCh. 10 - Prob. 83ACh. 10 - Prob. 84ACh. 10 - Prob. 85ACh. 10 - Prob. 86ACh. 10 - Prob. 87ACh. 10 - Prob. 88ACh. 10 - Prob. 89ACh. 10 - Determine the number of representative particles...Ch. 10 - Determine the number of representative particles...Ch. 10 - Prob. 92ACh. 10 - Determine the number of moles in each substance....Ch. 10 - Prob. 94ACh. 10 - Prob. 95ACh. 10 - RDA of Selenium The recommended daily allowance...Ch. 10 - Prob. 97ACh. 10 - Prob. 98ACh. 10 - Prob. 99ACh. 10 - Prob. 100ACh. 10 - Prob. 101ACh. 10 - Prob. 102ACh. 10 - Prob. 103ACh. 10 - Prob. 104ACh. 10 - Prob. 105ACh. 10 - Prob. 106ACh. 10 - Prob. 107ACh. 10 - Calculate the mass of each element. a. 5.22 mol of...Ch. 10 - Perform the following conversions. a. 3.50 mol of...Ch. 10 - Determine the mass in grams of each element....Ch. 10 - Complete Table 10.3.Ch. 10 - Convert each to mass in grams. a. 4.221015 atoms c...Ch. 10 - Prob. 113ACh. 10 - Prob. 114ACh. 10 - Prob. 115ACh. 10 - Prob. 116ACh. 10 - Prob. 117ACh. 10 - Prob. 118ACh. 10 - Prob. 119ACh. 10 - Prob. 120ACh. 10 - Prob. 121ACh. 10 - Prob. 122ACh. 10 - Prob. 123ACh. 10 - Prob. 124ACh. 10 - Prob. 125ACh. 10 - Prob. 126ACh. 10 - Prob. 127ACh. 10 - Prob. 128ACh. 10 - Prob. 129ACh. 10 - Prob. 130ACh. 10 - Prob. 131ACh. 10 - Prob. 132ACh. 10 - Prob. 133ACh. 10 - Prob. 134ACh. 10 - Prob. 135ACh. 10 - Prob. 136ACh. 10 - Prob. 137ACh. 10 - Prob. 138ACh. 10 - Prob. 139ACh. 10 - Prob. 140ACh. 10 - Prob. 141ACh. 10 - Prob. 142ACh. 10 - Prob. 143ACh. 10 - Prob. 144ACh. 10 - Prob. 145ACh. 10 - Prob. 146ACh. 10 - Prob. 147ACh. 10 - Pain Relief Acetaminophen, a common aspirin...Ch. 10 - Prob. 149ACh. 10 - Prob. 150ACh. 10 - Prob. 151ACh. 10 - Prob. 152ACh. 10 - Prob. 153ACh. 10 - Prob. 154ACh. 10 - Prob. 155ACh. 10 - Prob. 156ACh. 10 - Prob. 157ACh. 10 - Prob. 158ACh. 10 - Prob. 159ACh. 10 - Prob. 160ACh. 10 - Prob. 161ACh. 10 - Prob. 162ACh. 10 - Express the composition of each compound as the...Ch. 10 - VitaminD3 Your body's ability to absorb calcium is...Ch. 10 - Prob. 165ACh. 10 - Cholesterol Heart disease is linked to high blood...Ch. 10 - Prob. 167ACh. 10 - Prob. 168ACh. 10 - Prob. 169ACh. 10 - Prob. 170ACh. 10 - Prob. 171ACh. 10 - Prob. 172ACh. 10 - Prob. 173ACh. 10 - Prob. 174ACh. 10 - Prob. 175ACh. 10 - Prob. 176ACh. 10 - Prob. 177ACh. 10 - Prob. 178ACh. 10 - Prob. 179ACh. 10 - Determine the mass percent of anhydrous sodium...Ch. 10 - Table 4 shows data from an experiment to determine...Ch. 10 - Chromium(lll) nitrate forms a hydrate that is...Ch. 10 - Determine the percent composition of MgCO35H2O and...Ch. 10 - What is the formula and name of a hydrate that is...Ch. 10 - Gypsum is hydrated calcium sulfate. A 4.89-g...Ch. 10 - A 1.628-g sample of a hydrate of magnesium iodide...Ch. 10 - Borax Hydrated sodiumtetraborate (Na2B4O7xH2O) is...Ch. 10 - Prob. 188ACh. 10 - Prob. 189ACh. 10 - Prob. 190ACh. 10 - Prob. 191ACh. 10 - Prob. 192ACh. 10 - Prob. 193ACh. 10 - Prob. 194ACh. 10 - Prob. 195ACh. 10 - Prob. 196ACh. 10 - Prob. 197ACh. 10 - Prob. 198ACh. 10 - Prob. 199ACh. 10 - Prob. 200ACh. 10 - Prob. 201ACh. 10 - Prob. 202ACh. 10 - Prob. 203ACh. 10 - Prob. 204ACh. 10 - Prob. 205ACh. 10 - Prob. 206ACh. 10 - Prob. 207ACh. 10 - Prob. 208ACh. 10 - Prob. 209ACh. 10 - Prob. 210ACh. 10 - Prob. 211ACh. 10 - Prob. 212ACh. 10 - Prob. 213ACh. 10 - Prob. 214ACh. 10 - Prob. 215ACh. 10 - Prob. 216ACh. 10 - Prob. 1STPCh. 10 - Prob. 2STPCh. 10 - Prob. 3STPCh. 10 - Prob. 4STPCh. 10 - Prob. 5STPCh. 10 - Prob. 6STPCh. 10 - Prob. 7STPCh. 10 - Prob. 8STPCh. 10 - Prob. 9STPCh. 10 - Prob. 10STPCh. 10 - Prob. 11STPCh. 10 - Prob. 13STPCh. 10 - Prob. 14STPCh. 10 - Prob. 15STPCh. 10 - Prob. 16STP
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