Explanation Given: The probability density function is f ( x ) = 1 28 ( 2 x + 3 ) over [ 0 , 4 ] . Concept used: A probability density function of a random variable X in an interval I has the properties as it is a nonnegative function and the total area of the region under the graph of f is equal to 1. Calculation: The given probability density function is f ( x ) = 1 28 ( 2 x + 3 ) over [ 0 , 4 ] . Since 1 28 and ( 2 x + 3 ) are both nonnegative on the interval [ 0 , 4 ] so the function f ( x ) is greater than or equal to 0 . Thus, the function f ( x ) is a nonnegative function

Applied Calculus for the Managerial, Life, and Social Sciences (MindTap Course List)

10th Edition

ISBN: 9781305657861

Author: Soo T. Tan

Publisher: Cengage Learning

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Chapter 10, Problem 1RE

To determine

To show: The function f(x)=128(2x+3) is a probability density function on the interval [0,4].

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Chapter 10, Problem 8CRQ

Chapter 10, Problem 2RE

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Chapter 10 Solutions

Applied Calculus for the Managerial, Life, and Social Sciences (MindTap Course List)

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Knowledge Booster

The function f ( x ) = 1 28 ( 2 x + 3 ) is a probability density function on the interval [ 0 , 4 ] .

Solution Summary: The author explains the probability density function of a random variable X in an interval I has the properties as it is nonnegative.

To show: The function f(x)=128(2x+3) is a probability density function on the interval [0,4].

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Chapter 10 Solutions