ORGANIC CHEM. VOL.1+2-W/WILEYPLUS
ORGANIC CHEM. VOL.1+2-W/WILEYPLUS
12th Edition
ISBN: 9781119304241
Author: Solomons
Publisher: WILEY C
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Chapter 10, Problem 1PP
Interpretation Introduction

Interpretation:

The radicals, in order of theirs decreasing stability, are to be listed.

Concept introduction:

A molecule that contains at least one unpaired electron is known as a radical.

The relative stability of radicals is the same as that of carbocations.

The stability of radicals is as follows:

3°>2°>1°>methyl

Expert Solution & Answer
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Answer to Problem 1PP

Solution:

ORGANIC CHEM. VOL.1+2-W/WILEYPLUS, Chapter 10, Problem 1PP , additional homework tip  1

Explanation of Solution

ORGANIC CHEM. VOL.1+2-W/WILEYPLUS, Chapter 10, Problem 1PP , additional homework tip  2

The radical is a methyl radical. So, it is the least stable.

The radical is given as follows:

ORGANIC CHEM. VOL.1+2-W/WILEYPLUS, Chapter 10, Problem 1PP , additional homework tip  3

The carbon containing the unpaired electron is primary. Thus, the radical is a primary radical.

The radical is given as follows:

ORGANIC CHEM. VOL.1+2-W/WILEYPLUS, Chapter 10, Problem 1PP , additional homework tip  4

The carbon containing the unpaired electron is tertiary. Thus, the radical is a tertiary radical.

The radical is given as follows:

ORGANIC CHEM. VOL.1+2-W/WILEYPLUS, Chapter 10, Problem 1PP , additional homework tip  5

The carbon containing the unpaired electron is secondary. Thus, the radical is a secondary radical.

Therefore, the tertiary radical is the most stable and the methyl radical is the least stable.

Hence, the decreasing order of the stability of the radical is as follows:

ORGANIC CHEM. VOL.1+2-W/WILEYPLUS, Chapter 10, Problem 1PP , additional homework tip  6

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