
Concept explainers
Find the time taken for the population to triple.

Answer to Problem 11CT
7.92 hours , or 7 hours 55 minutes 12 seconds.
Explanation of Solution
Given:
The population of a certain colony of bacteria doubles every 5 hours.
Calcultion:
Let
b0 = count of bacteria at 0 hours , or , initially
bt = count of bacteria at t hours
y% = rate of growth of bacteria , which is constant
t = time in hours for the population to get triple
So, count of bacteria after 5 hours is double :
b5=2b0⇒b5=b0(1+y100)5=2b0⇒2=(1+y100)5
Find y :
2=(1+y100)5⇒5√2=1+y100...................[take roots]⇒y=100(5√2−1)
Now , find the time t when the count of bacteria is 3b0 :
bt=3b0⇒bt=b0(1+y100)t=3b0⇒3=(1+100(5√2−1)100)t⇒log3=log(1+5√2−1)t..................[take log10 each side]⇒log3=log(2)t5⇒t5log2=log3...............................[logab=bloga]⇒t5=log3log2.....................................[divide each side by log2]⇒t=5log3log2...................................[multiply each side by 5]⇒t=5(0.477)0.301⇒t≈7.92
So, the time is approximately 7.92 hours , or 7 hours 55 minutes 12 seconds. [1 hour = 60 minutes and 1 minute = 60 seconds]
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