PEARSON ETEXT ENGINEERING MECH & STATS
15th Edition
ISBN: 9780137514724
Author: HIBBELER
Publisher: PEARSON
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Chapter 10, Problem 106P
To determine
The moment of inertia of the assembly about an axis that is perpendicular to the page and passing through the center of mass
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Chapter 10 Solutions
PEARSON ETEXT ENGINEERING MECH & STATS
Ch. 10 - Determine the moment of inertia of the shaded area...Ch. 10 - Determine the moment of inertia of the shaded area...Ch. 10 - Determine the moment of inertia of the shaded area...Ch. 10 - Determine the moment of inertia of the shaded area...Ch. 10 - Determine the moment of inertia of tire area about...Ch. 10 - Prob. 13PCh. 10 - Prob. 21PCh. 10 - Determine the moment of inertia of the beams...Ch. 10 - Prob. 6FPCh. 10 - Prob. 7FP
Ch. 10 - Prob. 8FPCh. 10 - Determine the moment of inertia of the composite...Ch. 10 - Determine the moment of inertia of the composite...Ch. 10 - Prob. 29PCh. 10 - Determine the moment of inertia for the beams...Ch. 10 - Determine the moment of inertia for the beams...Ch. 10 - Prob. 36PCh. 10 - Prob. 42PCh. 10 - Prob. 43PCh. 10 - Prob. 44PCh. 10 - Prob. 45PCh. 10 - Prob. 50PCh. 10 - Determine the moment of inertia for the beams...Ch. 10 - Prob. 52PCh. 10 - Prob. 53PCh. 10 - Prob. 54PCh. 10 - Prob. 57PCh. 10 - Prob. 58PCh. 10 - Prob. 66PCh. 10 - Prob. 67PCh. 10 - Prob. 84PCh. 10 - Prob. 85PCh. 10 - Prob. 87PCh. 10 - Determine the moment of inertia of the homogenous...Ch. 10 - Determine the moment of inertia of the...Ch. 10 - Prob. 90PCh. 10 - The concrete shape is formed by rotating the...Ch. 10 - The right circular cone is formed by revolving the...Ch. 10 - The pendulum consists of a 8-kg circular disk A, a...Ch. 10 - Determine the moment of inertia Ix of the frustum...Ch. 10 - Prob. 100PCh. 10 - Prob. 101PCh. 10 - Prob. 103PCh. 10 - Prob. 104PCh. 10 - Prob. 105PCh. 10 - Prob. 106PCh. 10 - Prob. 107PCh. 10 - Prob. 108PCh. 10 - Prob. 109PCh. 10 - Prob. 5RP
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- Determine the moment of inertial about an axis perpendicular to the page and passing through the pin at O. The thin plate has a hole in its center. Its thickness is 50 mm and the material has a density of ρ = 50 kg/m^3arrow_forwardThe slender bar lies in the x-y plane. Its mass is 6 kg and the material is homogeneous. Use integration to determine its moment of inertia about the z-axisarrow_forwardThe homogeneous thin plate has mass m = 12Kg and dimensions b=2m and h=1m. Determine the moments of inertia of the plate about the x and y axes.arrow_forward
- The paraboloid is formed by revolving the shaded area around the x axis. The material has a constant density ρ. Determine the moment of inertia about the x axis and express the result in terms of the total mass m of the paraboloid.arrow_forwardDetermine the moment of inertia of the wheel about an axis which is perpendicular to the page and passes through point O. The material has a specific weight of 90 lb/ft3.arrow_forwardThe molded plastic block has a density of 1300 kg/m³. Calculate its moment of inertia about the y-y axis. What percentage error e is introduced by using the approximate relation 1/3 ml² for lxx? Answers: lyy e = = 200 y 495 200 Dimensions in millimeters textes kg m² % 60 60arrow_forward
- Determine the mass moment of inertia of the figure shown about the x,y, and z axis. The materials weighs 60 kN/m³. 0.10m AY 0.30m 0.10m 0.60m 0.05m 0.20m Z. 0.10 0.40marrow_forwardThe uniform rod of length 4b and mass m is bent into the shape shown. The diameter of the rod is small compared with its length. Determine the moments of inertia of the rod about the three coordinate axes. Use the values m = 7.9 kg and b = 485 mm. Answers: 1xxx = i lyy= i Izz = i kg.m² kg-m² kg-m²arrow_forwardDetermine the moment of inertia with respect to the line y = 2 for the area enclosed by the ellipse whose equation is (x^2/16)+(y^2/4)=1.arrow_forward
- The uniform rod of length 4b and mass m is bent into the shape shown. The diameter of the rod is small compared with its length. Determine the moments of inertia of the rod about the three coordinate axes. Use the values m = 9.7 kg and b = 650 mm. Answers: Ixx = i lyy= Izz i i kg-m² kg.m² kg.m²arrow_forwardFormulas Moments of Inertia x= [y²d ly = fx²dA Theorem of Parallel Axis Ixr = 1 + d² A * axis going through the centroid x' axis parallel to x going through the point of interest d minimal distance (perpendicular) between x and x' ly₁ = 15+d²A ỹ axis going through the centroid y' axis parallel to y going through the point of interest d minimal distance (perpendicular) between y and y' Composite Bodies 1=Σ 4 All the moments of inertia should be about the same axis. Radius of Gyration k=arrow_forwardDetermine the moment of inertia about an axis perpendicular to the screen and passing through the center of mass G of the assembly. The block has a mass of 3.5 kg and the semicylinder has a mass of 8.5 kg. y 400 mm G 200 mm 300 mmarrow_forward
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moment of inertia; Author: NCERT OFFICIAL;https://www.youtube.com/watch?v=A4KhJYrt4-s;License: Standard YouTube License, CC-BY