Principles of Chemistry: A Molecular Approach (3rd Edition)
Principles of Chemistry: A Molecular Approach (3rd Edition)
3rd Edition
ISBN: 9780321971944
Author: Nivaldo J. Tro
Publisher: PEARSON
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Chapter 10, Problem 10.1P
Interpretation Introduction

Interpretation: The molecular geometry of the given compound is to be identified.

Concept introduction: VSEPR theory predicts the geometry of the molecule using its electron pair surrounding the central atom.

Expert Solution & Answer
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Answer to Problem 10.1P

Solution: The molecular geometry of CCl4is tetrahedral.

Explanation of Solution

The molecular geometry of the molecule is determined by the number of electron groups bonded to the central atom.

The atomic number of C is 6 .

The electronic configuration of C is,

1s22s22p2

The number of valence electrons of Cis 4 .

The atomic number of Cl is 17 .

The electronic configuration of Clis,

[Ne]3s23p5

The number of valence electrons of Cl is 7 .

The total number of valence electrons of CCl4is,

4+4×7=32

Therefore, the Lewis structure of CCl4is,

Principles of Chemistry: A Molecular Approach (3rd Edition), Chapter 10, Problem 10.1P , additional homework tip  1

Figure 1

From the figure 1, it is concluded that in the structure of CCl4 , there are four bonding domains, therefore, the hybridization of CCl4is sp3 .

Hence, the molecular geometry of CCl4is tetrahedral.

The molecular geometry of CCl4is,

Principles of Chemistry: A Molecular Approach (3rd Edition), Chapter 10, Problem 10.1P , additional homework tip  2

Figure 2

Conclusion

The molecular geometry of CCl4is tetrahedral.

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Chapter 10 Solutions

Principles of Chemistry: A Molecular Approach (3rd Edition)

Ch. 10 - Prob. 10.10PCh. 10 - Prob. 10.10MPCh. 10 - Prob. 1SAQCh. 10 - Prob. 2SAQCh. 10 - Predict the relative bond angles in BF3 and SO2....Ch. 10 - Prob. 4SAQCh. 10 - Prob. 5SAQCh. 10 - Prob. 6SAQCh. 10 - Prob. 7SAQCh. 10 - Prob. 8SAQCh. 10 - Prob. 9SAQCh. 10 - Prob. 10SAQCh. 10 - Prob. 11SAQCh. 10 - Prob. 12SAQCh. 10 - Prob. 13SAQCh. 10 - Prob. 14SAQCh. 10 - Prob. 15SAQCh. 10 - Prob. 1ECh. 10 - Prob. 2ECh. 10 - Prob. 3ECh. 10 - Prob. 4ECh. 10 - Prob. 5ECh. 10 - Prob. 6ECh. 10 - Prob. 7ECh. 10 - Prob. 8ECh. 10 - Prob. 9ECh. 10 - Prob. 10ECh. 10 - Prob. 11ECh. 10 - Prob. 12ECh. 10 - Prob. 13ECh. 10 - Prob. 14ECh. 10 - Prob. 15ECh. 10 - Prob. 16ECh. 10 - Prob. 17ECh. 10 - Prob. 18ECh. 10 - Prob. 19ECh. 10 - Prob. 20ECh. 10 - Prob. 21ECh. 10 - Prob. 22ECh. 10 - Prob. 23ECh. 10 - Prob. 24ECh. 10 - Prob. 25ECh. 10 - Prob. 26ECh. 10 - Prob. 27ECh. 10 - Prob. 28ECh. 10 - Prob. 29ECh. 10 - Prob. 30ECh. 10 - Prob. 31ECh. 10 - Prob. 32ECh. 10 - 33.Write a hybridization and bonding scheme for...Ch. 10 - Write a hybridization and bonding scheme for each...Ch. 10 - Prob. 35ECh. 10 - Prob. 36ECh. 10 - Prob. 37ECh. 10 - Prob. 38ECh. 10 - Prob. 39ECh. 10 - Prob. 40ECh. 10 - Prob. 41ECh. 10 - Prob. 42ECh. 10 - Prob. 43ECh. 10 - Prob. 44ECh. 10 - Prob. 45ECh. 10 - Prob. 46ECh. 10 - Prob. 47ECh. 10 - Prob. 48ECh. 10 - Prob. 49ECh. 10 - Prob. 50ECh. 10 - Prob. 51ECh. 10 - Prob. 52ECh. 10 - Prob. 53ECh. 10 - The genetic code is based on four different bases...Ch. 10 - Prob. 55ECh. 10 - Prob. 56ECh. 10 - Prob. 57ECh. 10 - Prob. 58ECh. 10 - Prob. 59ECh. 10 - Prob. 60ECh. 10 - Prob. 61ECh. 10 - Prob. 62ECh. 10 - Prob. 63ECh. 10 - The molecule cis-2-butene isomerizes to trans-2-b...Ch. 10 - Prob. 65ECh. 10 - Prob. 66ECh. 10 - Prob. 67ECh. 10 - Prob. 68ECh. 10 - Pick the statement that best captures the...Ch. 10 - Prob. 70ECh. 10 - Prob. 71ECh. 10 - Prob. 72E
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