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To find:
The total pressure of the gases released by the reaction of H2O2 and N2H4 by using the reaction stoichiometry.
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Answer to Problem 10.128QA
Solution:
Total pressure of the gases released by the reaction is 0.567 atm.
Explanation of Solution
1) Concept:
To calculate the total pressure exerted by the gases released in the reaction, we can use gaseous stoichiometry. We calculate the moles of the H2O2 and N2H4 from the mass of the liquid and the molar masses. From the moles of the reactant, we calculate the limiting reactant by using the reaction stoichiometry. We will calculate the moles of the gases product from the limiting reactant and then calculate the total pressure by using the ideal gas equation.
2) Formula:
i) PV=nRT
ii) Molar mass=massmol
iii) Ptotal= PH2O2+ PN2H4
3) Given:
i) Mass of H2O2 = 8.50 g
ii) Mass of N2H4 = 4.00 g
iii) Volume of the reaction vessel V=125 L
iv)T=1110 ℃=1110+273.15=1383.15 K
v) R=0.08206 L. atmmol. K
4) Calculations:
i) The balanced chemical reaction is
2 H2O2 (l) +N2H4 (l) → N2(g)+4 H2O (g)
Calculating moles of the H2O2 and N2H4 using their molar masses as
8.50 g H2O2 × 1 mol34.01 g H2O2=0.2499 mol H2O2
4.00 g N2H4 × 1 mol32.04 g N2H4 =0.1248 mol N2H4
Calculatingthe limiting reactant as
0.2499 mol H2O2 × 1 mol N2 2 mol H2O2=0.12495 mol N2
0.1248 mol N2H4 × 1 mol N2 1 mol N2H4=0.1248 mol N2
So, the limiting reactant is N2H4.
ii) Calculatingthe moles of the gases product from the moles of the N2H4
0.1248 mol N2H4 × 1 mol N2 1 mol N2H4=0.1248 mol N2
0.1248 mol N2H4 × 4 mol H2O 1 mol N2H4=0.4992 mol H2O
iii) Calculatingthe partial pressure of H2O2 and N2H4 by using ideal gas equation
PV=nRT
PN2=nRTV= 0.1248 mol×0.08206 L. atmmol. K× 1383.15 K 125 L=0.1133 atm
PH2O=nRTV= 0.4992 mol×0.08206 L. atmmol. K× 1383.15 K 125 L=0.4533 atm
Pt= PH2O2+ PN2H4=0.1133 atm+0.4533 atm=0.567 atm
The total pressure of the gases released by the reaction is 0.567 atm.
Conclusion:
The total pressure of the gas released from the reaction is calculated from the mass of the reactant and the reaction stoichiometry by using the ideal gas equation to calculate the partial pressure.
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