Why is it difficult to detect planets orbiting other star

napnwea.org 100% Normal text Times New. 12 В I U | 1 2 II| 4 5. After you have checked your answer at the Data Checker Station, fill in the correct letter for each solar system planet. Мегcury Venus Earth Mars TEBO Mars Jupiter Saturn Uranus Neptune

Consider a cool Jupiter with a temperature of 1183 K and a hot Jupiter with a temperature of 3180 K are orbiting the star Vega what is the ratio of the hot Jupiters power per square meter to a cool jupiters power per square meter

What is the time taken by a planet to sweep an area of 2 million square km if the time taken by the same planet to cover an area of 1 million square km is 36 hours? 18 hours 36 hours 72 hours 144 hours

Please answer the question and subquestions completely! This is one whole question which has subquestions! According to the official Bartleby guidelines, each question can have up to two subquestions! Thank you!   1) The mass of Planet W is 1/100 that of Earth and its radius is 1/4 that of Earth. If the weight of an object is 600 N on Earth, what would it weigh on Planet W?     24 N     48 N     96 N     192 N     600 N A) The weight of an object at the surface of Earth is 90 N. What is its weight at a distance 2R from the surface of Earth?     10 N     30 N     90 N     270 N     810 N B) A 9.0 x 10 3 kg satellite orbits the Earth at the distance of 2.56 x 10 7 m from Earth’s surface. What is its period?     1.1 x 10 4 s     4.1 x 10 4 s     5.7 x 10 4 s     1.5 x 10 5 s

The planets move around the sun in elliptical orbitswith the sun at one focus. The positions of a planet thatare closest to and farthest from the sun are called itsperihelion and aphelion, respectively. Use Exercise 23(a)to show that the perihelion distance from a planet to thesun is a(1 - e) and the aphelion distance is 1(a+e)

Assuming it were possible, how long would it take a car traveling at 60 miles per hour to leave the solar system?

Kepler’s First Law: Elliptical Planetary Orbits:     The solar system major planet in the most elliptical solar orbit is little Mercury, which is the closest planet to the Sun. At Perihelion, Mercury’s distance from the Sun (Rp) is 0.31 AU. At Aphelion, Mercury’s distance from the Sun (Ra) is 0.47 AU.             The intensity of Sunlight (I) that a planet receives from the Sun is inversely proportional to the square of that planet’s distance from the Sun (R). in other words,                                             I  = Constant / R2.   Calculate how much more intense the Sunlight received by Mercury is at perihelion (p)  than at aphelion (a):   Rp2 =                          Ra2    =                 Ip / Ia =  Ra2 / Rp2 =

There are two parts to this question. I need to know how many times fainter Venus is from a distance of 6 pc and what the apparent magnitude would be as well! Thank you!!

A planet was recently discovered orbiting the star Proxima Centauri, with an orbital radius of 0.05 AU. As seen from Earth, what is the maximum angular separation between this planet and Proxima Centauri, in arcseconds? The distance to Proxima Centauri is 4.24 light-years.