Physics: Principles with Applications
Physics: Principles with Applications
6th Edition
ISBN: 9780130606204
Author: Douglas C. Giancoli
Publisher: Prentice Hall
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Chapter 1, Problem 43GP
To determine

To Find: The diameter of a 1 − ton rock.

Expert Solution & Answer
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Answer to Problem 43GP

  d=2.74 ft

Explanation of Solution

Given info:

Density of rock, ρr=3ρW=3×62 lb/ft3

Mass of the rock, M=1 ton

Formula used:

  ρr=MV                  ...............(i)

Where,

  ρr= Density of rock.

  M= Mass of rock.

  V= Volume of rock.

Volume of spherical rock:

  V=43π(d2)3              .............(ii)

Where,

  d= diameter of spherical rock.

Calculation:

  1 ton=2000 lb

Therefor, volume of rock can be calculated from equation (i),

i.e.

  V=Mρr

Plugging in the given values:

  V=1 ton3×62 lb/ft3=2000 lb3×62 lb/ft3=10.75 ft3

The diameter of the rock can be calculated from equation (ii),

i.e.

  V=43π×d38d3=6Vπd=(6Vπ)13

Plugging in the given values:

  d=(6×10.75 ft33.14)13=2.74 ft

Conclusion:

Hence, the diameter of the rock: 2.74 ft

Chapter 1 Solutions

Physics: Principles with Applications

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