EBK NUMERICAL METHODS FOR ENGINEERS
EBK NUMERICAL METHODS FOR ENGINEERS
7th Edition
ISBN: 9780100254145
Author: Chapra
Publisher: YUZU
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Chapter 1, Problem 24P

As depicted in Fig. P1.24, the downward deflection y   ( m ) of a cantilever beam with a uniform load w (kg/m) can be computed as

y = w 24 E I ( x 4 4 L x 3 + 6 L 2 x 2 )

where x = distance ( m ) , E = the modulus of elasticity = 2 × 10 11 Pa, I = moment of inertia = 3.25 × 10 4  m 4 , w = 10 , 000 N/m, and

L = length = 4 m. This equation can be differentiated to yield the slope of the downward deflection as a function of x:

d y d x = w 24 E I ( 4 x 3 12 L x 2 + 12 L 2 x )

If y = 0 at x = 0 , use this equation with Euler's method ( Δ x = 0.125  m ) to compute the deflection from x = 0 to L. Develop a plot of your results along with the analytical solution computed with the first equation.

Chapter 1, Problem 24P, As depicted in Fig. P1.24, the downward deflection y(m) of a cantilever beam with a uniform load w

FIGURE P1.24

A cantilever beam.

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When a beam section is subjected to a shear load, a shear stress distribution is developed on the section. The distribution of the shear stress is not linear. Elasticity theory can be used to calculate the shear stress at any point. However, a simpler method can be used to calculate the average shear stress across the width of the section, a distance y above or below the neutral axis. The average VQ shear stress is given by T = Here V is the shear It force on the section, I is the moment of inertia of the entire section about the neutral axis, and t is the width of the section at the distance y where the shear stress is being calculated. Q is the product of the area of the section above (or below) y and the distance from the neutral axis to the centroid of that area (Figure 1). In short, Q is the moment of the area about the neutral axis. I Figure 1 of 1 An I-beam has a flange width b = 250 mm, height h = 250 mm, web thickness tw = 9 mm, and flange thickness tf = 14 mm. Use the…
The figure below (for illustrative purposes) shows a perfectly rigid (non-deformable) beam which is perfectly rigidly supported at points P and R by two force measurement scales, 1 and 2. PQ is 65 cm and PR is 150 cm. The beam is horizontal when each of scales 1 and 2 gives a reading of zero. Acceleration due to gravity is 9.81 ms-2. Scale 1 Point P Point Q Point R Scale 2 Choose one of the following options that will give the correct readings of scales 1 and 2 when a mass of 30 kg acts vertically downwards at point Q. (The scales are not loaded to you will have to calculate the answer) O A Reading of Scale 1 = 150 kg; Reading of scale 2 = 65 kg O B. Reading of Scale 1 = 166.77 kg; Reading of scale 2 = 127.53 kg O C. Reading of Scale 1 = 150 Newton; Reading of scale 2 = 65 kg O D. Reading of Scale 1 = 166.77 Newton; Reading of scale 2 = 127.53 Newton
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EBK NUMERICAL METHODS FOR ENGINEERS

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