COLLEGE PHYSICS-CONNECT ACCESS
COLLEGE PHYSICS-CONNECT ACCESS
5th Edition
ISBN: 9781260486834
Author: GIAMBATTISTA
Publisher: MCG
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Chapter 1, Problem 23P

(a)

To determine

The number of scientific figures in 0.00574kg, and the standard notation of the 0.00574kg.

(a)

Expert Solution
Check Mark

Answer to Problem 23P

The number of scientific figures in 0.00574kg is 3_, and the standard notation of the 0.00574kg is 5.74×103kg_.

Explanation of Solution

In scientific notation, any number is written as a number between one and ten times an integer power of ten. The significant figures are all the digits that are known accurately plus the one estimated digit.

The rules for identifying the significant figures are, the nonzero digits are always significant, final or ending zeros written to the right of the decimal point are significant, zeros written to the right of the decimal point for the purpose of spacing the decimal point are not significant, zeros written to the left of the decimal point may be significant, and zeros written between significant figures are significant.

According to the rule the first two zeros in 0.00574kg are not significant, so the significant number is three. To write the number in scientific notation, move the decimal point three places to the right, and compensate by multiplying by 103. That is 5.74×103kg.

Conclusion:

Therefore, the number of scientific figures in 0.00574kg is 3_, and the standard notation of the 0.00574kg is 5.74×103kg_.

(b)

To determine

The number of scientific figures in 2m, and the standard notation of the 2m.

(b)

Expert Solution
Check Mark

Answer to Problem 23P

The number of scientific figures in 2m is 1_, and the standard notation of the 2m is 2m_.

Explanation of Solution

According to the rule the number two is significant, so the significant number is one. The number in scientific notation is same as given. That is 2m.

Conclusion:

Therefore, the number of scientific figures in 2m is 1_, and the standard notation of the 2m is 2m_.

(c)

To determine

The number of scientific figures in 0.450×102m, and the standard notation of the 0.450×102m.

(c)

Expert Solution
Check Mark

Answer to Problem 23P

The number of scientific figures in 0.450×102m is 3_, and the standard notation of the 0.450×102m is 4.50×103m_.

Explanation of Solution

According to the rule the three zeros after the decimal point in 0.450×102m are significant, so the significant number is three. To write the number in scientific notation, move the decimal point one places to the right, and compensate by multiplying by 101. That is 4.50×103m.

Conclusion:

Therefore, the number of scientific figures in 0.450×102m is 3_, and the standard notation of the 0.450×102m is 4.50×103m_.

(d)

To determine

The number of scientific figures in 45.0kg, and the standard notation of the 45.0kg.

(d)

Expert Solution
Check Mark

Answer to Problem 23P

The number of scientific figures in 45.0kg is 3_, and the standard notation of the 45.0kg is 4.50×101kg_.

Explanation of Solution

According to the rule the two numbers after the decimal point in 45.0kg are significant, so the significant number is three. To write the number in scientific notation, move the decimal point one places to the left, and compensate by multiplying by 101. That is 4.50×101kg.

Conclusion:

Therefore, the number of scientific figures in 45.0kg is 3_, and the standard notation of the 45.0kg is 4.50×101kg_.

(e)

To determine

The number of scientific figures in 10.09×104s, and the standard notation of the 10.09×104s.

(e)

Expert Solution
Check Mark

Answer to Problem 23P

The number of scientific figures in 10.09×104s is 4_, and the standard notation of the 10.09×104s is 1.009×105s_.

Explanation of Solution

According to the rule the two numbers after the decimal point and before the decimal point in 10.09×104s are significant, so the significant number is four. To write the number in scientific notation, move the decimal point one places to the left, and compensate by multiplying by 101. That is 1.009×105s.

Conclusion:

Therefore, the number of scientific figures in 10.09×104s is 4_, and the standard notation of the 10.09×104s is 1.009×105s_.

(f)

To determine

The number of scientific figures in 0.09500×105mL, and the standard notation of the 0.09500×105mL.

(f)

Expert Solution
Check Mark

Answer to Problem 23P

The number of scientific figures in 0.09500×105mL is 4_, and the standard notation of the 0.09500×105mL is 9.500×103mL_.

Explanation of Solution

According to the rule the zero just after the decimal point in 0.09500×105mL is not significant, so the significant number is four. To write the number in scientific notation, move the decimal point two places to the right, and compensate by multiplying by 102. That is 9.500×103mL_.

Conclusion:

Therefore, the number of scientific figures in 0.09500×105mL is 4_, and the standard notation of the 0.09500×105mL is 9.500×103mL_.

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Chapter 1 Solutions

COLLEGE PHYSICS-CONNECT ACCESS

Ch. 1.6 - Prob. 1.8PPCh. 1.6 - Prob. 1.9PPCh. 1.6 - Prob. 1.6CPCh. 1.8 - Prob. 1.10PPCh. 1.9 - Prob. 1.11PPCh. 1.9 - What value of k would you calculate by using only...Ch. 1 - Prob. 1CQCh. 1 - Why must words be carefully defined for scientific...Ch. 1 - Prob. 3CQCh. 1 - Prob. 4CQCh. 1 - Prob. 5CQCh. 1 - Prob. 6CQCh. 1 - Prob. 7CQCh. 1 - Prob. 8CQCh. 1 - Prob. 9CQCh. 1 - Prob. 10CQCh. 1 - Prob. 11CQCh. 1 - Prob. 12CQCh. 1 - Prob. 13CQCh. 1 - Prob. 14CQCh. 1 - Prob. 1MCQCh. 1 - Prob. 2MCQCh. 1 - Prob. 3MCQCh. 1 - Prob. 4MCQCh. 1 - Prob. 5MCQCh. 1 - Prob. 6MCQCh. 1 - Prob. 7MCQCh. 1 - Prob. 8MCQCh. 1 - Prob. 9MCQCh. 1 - Prob. 10MCQCh. 1 - Prob. 1PCh. 1 - Prob. 2PCh. 1 - Prob. 3PCh. 1 - Prob. 4PCh. 1 - Prob. 5PCh. 1 - On Monday, a stock market index goes up 5.00%. On...Ch. 1 - Prob. 7PCh. 1 - Prob. 8PCh. 1 - Prob. 9PCh. 1 - Prob. 10PCh. 1 - Prob. 11PCh. 1 - Prob. 12PCh. 1 - Prob. 13PCh. 1 - Prob. 14PCh. 1 - Prob. 15PCh. 1 - Prob. 16PCh. 1 - Prob. 17PCh. 1 - Prob. 18PCh. 1 - Prob. 19PCh. 1 - Prob. 20PCh. 1 - Prob. 21PCh. 1 - Prob. 22PCh. 1 - Prob. 23PCh. 1 - Prob. 24PCh. 1 - Prob. 25PCh. 1 - Prob. 26PCh. 1 - Prob. 27PCh. 1 - Prob. 28PCh. 1 - Prob. 29PCh. 1 - Prob. 30PCh. 1 - Prob. 31PCh. 1 - Prob. 32PCh. 1 - Prob. 33PCh. 1 - Prob. 34PCh. 1 - Prob. 35PCh. 1 - Prob. 36PCh. 1 - Prob. 37PCh. 1 - Prob. 38PCh. 1 - Prob. 39PCh. 1 - Prob. 40PCh. 1 - Prob. 41PCh. 1 - Prob. 42PCh. 1 - Prob. 43PCh. 1 - Prob. 44PCh. 1 - Prob. 45PCh. 1 - Prob. 46PCh. 1 - Prob. 47PCh. 1 - Prob. 48PCh. 1 - Prob. 49PCh. 1 - Prob. 50PCh. 1 - Prob. 51PCh. 1 - Prob. 52PCh. 1 - Prob. 53PCh. 1 - Prob. 55PCh. 1 - Prob. 56PCh. 1 - Prob. 57PCh. 1 - Prob. 58PCh. 1 - Prob. 59PCh. 1 - Prob. 60PCh. 1 - Prob. 61PCh. 1 - Prob. 62PCh. 1 - Prob. 63PCh. 1 - Prob. 64PCh. 1 - Prob. 65PCh. 1 - Prob. 68PCh. 1 - Prob. 69PCh. 1 - Prob. 70PCh. 1 - Prob. 71PCh. 1 - Prob. 72PCh. 1 - Prob. 73PCh. 1 - Prob. 74PCh. 1 - Prob. 75PCh. 1 - Prob. 76PCh. 1 - Prob. 77PCh. 1 - Prob. 78PCh. 1 - Prob. 79PCh. 1 - Prob. 80PCh. 1 - Prob. 81PCh. 1 - Prob. 82PCh. 1 - Prob. 83PCh. 1 - Prob. 84PCh. 1 - Prob. 85PCh. 1 - Prob. 86PCh. 1 - Prob. 87PCh. 1 - Prob. 88PCh. 1 - Prob. 89PCh. 1 - Prob. 90PCh. 1 - Prob. 91PCh. 1 - Prob. 92PCh. 1 - Prob. 93PCh. 1 - Prob. 94PCh. 1 - Prob. 95PCh. 1 - Prob. 96PCh. 1 - Prob. 97P
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