Concept explainers
(a)
Interpretation:
Whether the given structure is a legitimate Lewis structure is to be determined.
Concept introduction:
For a valid Lewis structure of a molecule, the atoms must not exceed their normal valency. In general, this means atoms from the 2nd row onward, of the periodic table, must follow the octet rule. The exceptions to this rule are elements from the third row like S, P, etc., which are capable of expanding their octets to a maximum of twelve valence electrons. A hydrogen atom cannot have more than two valence electrons.
(b)
Interpretation:
Whether the given structure is a legitimate Lewis structure is to be determined.
Concept introduction:
For a valid Lewis structure of a molecule, the atoms must not exceed their normal valency. In general, this means atoms from the 2nd row onward of the periodic table must follow the octet rule. The exceptions to this rule are elements from the third row like S, P, etc., which are capable of expanding their octets to a maximum of twelve valence electrons. A hydrogen atom cannot have more than two valence electrons.
(c)
Interpretation:
Whether the given structure is a legitimate Lewis structure is to be determined.
Concept introduction:
For a valid Lewis structure of a molecule, the atoms must not exceed their normal valency. In general, this means atoms from the 2nd row onward of the periodic table must follow the octet rule. The exceptions to this rule are elements from the third row like S, P, etc., which are capable of expanding their octets to a maximum of twelve valence electrons. A hydrogen atom cannot have more than two valence electrons.
(d)
Interpretation:
Whether the given structure is a legitimate Lewis structure is to be determined.
Concept introduction:
For a valid Lewis structure of a molecule, the atoms must not exceed their normal valency. In general, this means atoms from the 2nd row onward of the periodic table must follow the octet rule. The exceptions to this rule are elements from the third row like S, P, etc., which are capable of expanding their octets to a maximum of twelve valence electrons. A hydrogen atom cannot have more than two valence electrons.
(e)
Interpretation:
Whether the given structure is a legitimate Lewis structure is to be determined.
Concept introduction:
For a valid Lewis structure of a molecule the atoms must not exceed their normal valency. In general, this means atoms from the 2nd row onward of the periodic table must follow the octet rule. The exceptions to this rule are elements from the third row like S, P, etc. which are capable of expanding their octets to a maximum of twelve valence electrons. A hydrogen atom cannot have more than two valence electrons.
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Chapter 1 Solutions
Get Ready for Organic Chemistry
- Problem Name each of the following anions and give the name and formula of the acid derived from it: (a) Br-; (b) IO3 -; (c) CN-; (d) SO4 2-; (e) NO2 -.arrow_forwardConsider compounds A–D, which contain both a heteroatom and a double bond. (a) For which compounds are no additional Lewis structures possible? (b) When two or more Lewis structures can be drawn, draw all additional resonance structures.arrow_forwardProblem (#2.) For each ion below, draw all reasonable resonance structures (linked by resonance arrows “↔”). Include curved arrows that indicate the movement of electrons between each resonance structure. Assign non-zero formal charges to each atom for each resonance structure. (a.) NO3– (nitrate) (b.) CH3COO– (acetate) (c.) N3– (azide) (d.) NCO– (isocyanate) Problem (#3.) For each ion in question 2, draw a resonance hybrid, assigning non-zero formal and/or partial charges (δ+, δ–) as needed. Problem (#4.) For each skeletal structure below, satisfy the valences (or octets) of all of the atoms by filling in double and triple bonds as well as unshared electron pairs. Assign non-zero formal charges and show the overall charge if the structure is an ion. See photo attached for Problem number 4. Problem (#5.) For each structure in question 4, draw a resonance hybrid (if it has one) and assign non-zero formal and/or partial charges as needed.arrow_forward
- Compute the formal charge (FC) on each atom in the following structures. (b) The hydronium ion, H3O+arrow_forwardCompute the formal charge (FC) on each atom in the following structures.(a) Methane (CH4)arrow_forwardI am wondering why there is a need for resoance structures if the molecule already has a neutral charge. Wouldn't these all be insignificant resonance structures (as there is unnecessary charge separation)? Perhaps they are only depicting these structures for the purpose of showing high/low electron density (which was what the question was asking for)? 1 picture shows answer, another shows problem (it is (b)).arrow_forward
- Problem What amount (mol) of each ion is in each solution?(a) 5.0 mol of ammonium sulfate dissolved in water(b) 78.5 g of cesium bromide dissolved in water(c) 7.42×1022 formula units of copper(II) nitrate dissolved in water(d) 35 mL of 0.84 M zinc chloridePlan We write an equation that shows 1 mol of compound dissociating into ions. (a) We multiply the number of moles of ions by 5.0. (b) We first convert grams to moles. (c) We first convert formula units to moles. (d) We first convert molarity and volume to moles.arrow_forwardThe curved arrow notation introduced in Section 1.6 is a powerful method used by organic chemists to show the movement of electrons not only in resonance structures, but also in chemical reactions. Since each curved arrow shows the movement of two electrons, following the curved arrows illustrates what bonds are broken and formed in a reaction. Consider the following three-step process. (a) Add curved arrows in Step [1] to show the movement of electrons. (b) Use the curved arrows drawn in Step [2] to identify the structure of X. X is converted in Step [3] to phenol and HCl.arrow_forwardThe curved arrow notation introduced in Section 1.6 is a powerful method used by organic chemists to show the movement of electrons not only in resonance structures, but also in chemical reactions. Since each curved arrow shows the movement of two electrons, following the curved arrows illustrates what bonds are broken and formed in a reaction. Consider the following three-step process. (a) Add curved arrows in Step [1] to show the movement of electrons. (b) Use the curved arrows drawn in Step [2] to identify the structure of X. X is converted in Step [3] to phenol and HCl.arrow_forward
- The curved arrow notation introduced in Section 1.6B is a powerfulmethod used by organic chemists to show the movement of electronsnot only in resonance structures, but also in chemical reactions.Because each curved arrow shows the movement of two electrons,following the curved arrows illustrates what bonds are broken andformed in a reaction. Consider the following three-step process. (a) Addcurved arrows in Step [1] to show the movement of electrons. (b) Use thecurved arrows drawn in Step [2] to identify the structure of X. X isconverted in Step [3] to phenol and HCl.arrow_forwardWhat is the relationship between the following two molecules? Problem viewing the image. Click Here O They are the same compound. O They are structural isomers. O They are stereoisomers. O They are completely different compound and not isomers O They are isotopes.arrow_forwardDraw the resonance structure that results from the following electron flow arrows. Note: Include formal charges and lone pairs where applicable.arrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning