Answered: Make use of Table 1.3 to express the…

Physics for Scientists and Engineers: Foundations and Connections

1st Edition

ISBN:9781133939146

Author:Katz, Debora M.

Publisher:Katz, Debora M.

Chapter1: Getting Started

Section: Chapter Questions

Problem 2PQ: If you live in the United States, you probably know your height in feet and inches. In other...

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Make use of Table 1.3 to express the following quantities in SI units: (a) 10.2 in./min (b) 4.81 slugs, (c) 3.02 lb, (d) 73.1 ft/s² (e) 0.0234 lb ∙ s/ft²

Table 1.3

Expert Solution

Step 1s

a) The relation used to convert in/min to SI unit (m/s) is given as,

1 in = 2.540 x 10^-2 m

1 min = 60 s

Therefore,

$v = 10.2 in / \min \times (\frac{2.54 \times 10^{- 2} m}{1 in}) \times (\frac{1 \min}{60 s}) v = 4.318 \times 10^{- 3} m / s$

Thus, the velocity in in/min to SI unit (m/s) is 4.318 x 10^-3 m/s.

Step 2

b) The relation used to convert slugs to SI unit (kg) is given as,

1 slug = 1.459 x 10¹ kg

Therefore,

$m = 4.81 slugs \times (\frac{1.459 \times 10^{1} kg}{1 slugs}) m = 70.2 kg$

Thus, the mass in slugs to SI unit (kg) is 70.2 kg.

c) The relation used to convert lb to SI unit (N) is given as,

1 lb = 4.448 N

Therefore,

$F = 3.02 lb \times (\frac{4.448 N}{1 lb}) F = 13.433 N$

Thus, the force in lb to SI unit (N) is 13.433 N.

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