Chapter 1, Problem 1.38P

1-38 Make the following conversions (conversion factor are given in Table 1-3):

(a) 42.6 kg to lb

(b) 1.62 lb to g

(c) 34 in. to cm

(d) 37.2 km to mi

(e) 2.73 gal to L

(f) 62g to oz

(g) 33.61 qt to L

(h) 43.7 L to gal

(i) 1.1 mi to km

(j) 34.9 mL to fl oz

Interpretation Introduction

(a)

Interpretation:

Conversion of 42.6 kg to lb should be determined.

Concept Introduction:

Concept Introduction:

Mass can be converted from kg to lb using the following conversion factor.

$\begin{array}{l}1\text{kg}=2.205\text{lb}\\ \frac{\text{2}\text{.205}\text{lb}}{\text{1}\text{kg}}\end{array}$.

Answer to Problem 1.38P

Mass in lb = 93.9 lb.

Explanation of Solution

Converting 42.6kg to lb:

$42.6\text{ kg}\times \frac{\text{2}\text{.205 lb}}{\text{1 kg}}=93.9\text{ lb}$

Thus, mass in lb is equal to 93.9 lb.

Interpretation Introduction

(b)

Interpretation:

Conversion of 1.62 lb to g should be determined.

Concept Introduction:

Mass can be converted from lb to kg using the following conversion factor.

$\begin{array}{l}\text{1 }\text{lb=453}\text{.592 g}\\ \end{array}$.

Answer to Problem 1.38P

Mass in g = 734.81 g.

Explanation of Solution

Converting 1.62 lb to g,

$\text{1}\text{.62 }\text{lb}\times \text{453}\text{.592}=734.81\text{ g}$

Thus, mass in kg is equal to 734.81 g.

Interpretation Introduction

(c)

Interpretation:

Conversion of 34 in. to cm should be determined.

Concept Introduction:

Length can be converted from in. to cm using the conversion factor,

$\begin{array}{l}1\text{in}.=2.54\text{cm}\\ \frac{\text{2}\text{.54}\text{cm}}{\text{1}\text{in}\text{.}}\end{array}$.

Answer to Problem 1.38P

Length in cm = 86.36 cm.

Explanation of Solution

Converting 34 in. to cm:

$34\text{in}\text{.}\times \frac{\text{2}\text{.54}\text{ cm}}{\text{1}\text{ in}\text{.}}=86.36\text{cm}$

Thus, length in cm = 86.36 cm.

Interpretation Introduction

(d)

Interpretation:

Conversion of 37.2 km to mi should be determined.

Concept Introduction:

Length can be converted from km to mi using the following conversion factor.

$\begin{array}{l}\text{1}\text{ mi =1}\text{.609 }\text{km}\\ \frac{\text{1}\text{ mi}}{\text{1}\text{.609 }\text{km}}\end{array}$.

Answer to Problem 1.38P

Distance in miles = 23.1 miles.

Explanation of Solution

Converting 37.2 km to mi:

$\text{37}\text{.2}\text{ km}\times \frac{\text{1 }\text{mi}}{\text{1}\text{.609}\text{ km}}=23.1\text{ mi}$

Thus, distance in miles = 23.1 miles.

Interpretation Introduction

(e)

Interpretation:

Conversion of 2.73 gal to L should be determined.

Concept Introduction:

Volume can be converted from gal to L using the following conversion factor.

$\begin{array}{l}\text{1}\text{gal = 3}\text{.785}\text{L}\\ \frac{\text{3}\text{.785}\text{L}}{\text{1}\text{gal}}\end{array}$.

Answer to Problem 1.38P

Volume in liters = 10.3 L.

Explanation of Solution

Converting 2.73 gal to L:

$\text{2}\text{.73}\text{gal}\times \frac{\text{3}\text{.785}\text{L}}{\text{1}\text{gal}}=10.3\text{L}$

Thus, volume in liters = 10.3 L.

Interpretation Introduction

(f)

Interpretation:

Conversion of 62 g to oz should be determined.

Concept Introduction:

Mass can be converted from g to oz using the following conversion factor.

$\begin{array}{l}\text{1}\text{oz = 28}\text{.35}\text{g}\\ \frac{\text{28}\text{.35}\text{g}}{\text{1}\text{oz}}\end{array}$.

Answer to Problem 1.38P

The value in oz = 2.18 oz.

Explanation of Solution

Converting 62 g to oz:

$\text{62}\text{ g}\times \frac{\text{1}\text{ oz}}{\text{28}\text{.35 }\text{g}}=2.18\text{ oz}$

Thus, the value in oz = 2.18 oz.

Interpretation Introduction

(g)

Interpretation:

Conversion of 33.61 qt to L should be determined.

Concept Introduction:

Volume can be converted from qt to L using the following conversion factor.

$\begin{array}{l}\text{1}\text{qt = 0}\text{.946}\text{L}\\ \frac{\text{0}\text{.946}\text{L}}{\text{1}\text{qt}}\end{array}$.

Answer to Problem 1.38P

The value in liter = 31.8 L.

Explanation of Solution

Converting 33.61 qt to L:

$\text{33}\text{.61}\text{qt}\times \frac{0.946\text{L}}{\text{1}\text{qt}}=31.8\text{L}$

Thus, the value in liter = 31.8 L.

Interpretation Introduction

(h)

Interpretation:

Conversion of 43.7 L to gal should be determined.

Concept Introduction:

Volume can be converted from L to gal using the following conversion factor.

$\begin{array}{l}\text{1 }\text{gal = 3}\text{.785 }\text{L}\\ \frac{\text{1}\text{ gal}}{\text{3}\text{.785 }\text{L}}\end{array}$.

Answer to Problem 1.38P

The value in gal = 11.5 gal.

Explanation of Solution

Converting 43.7 L to gal:

$\text{43}\text{.7}\text{L}\times \frac{\text{1}\text{ gal}}{\text{3}\text{.785 }\text{L}}=11.5\text{gal}$

Thus, the value in gal = 11.5 gal.

Interpretation Introduction

(i)

Interpretation:

Conversion of 1.1 mi to km should be determined.

Concept Introduction:

Length can be converted from mi to km using the following conversion factor.

$\begin{array}{l}\text{1}\text{mile = 1}\text{.609}\text{km}\\ \frac{\text{1}\text{.609}\text{km}}{\text{1}\text{mile}}\end{array}$.

Answer to Problem 1.38P

The value in km = 1.76 km.

Explanation of Solution

Converting 1.1 mi to km:

$\text{1}\text{.1 mi}\times \frac{1.609\text{ km}}{1\text{ mi}}=1.76\text{ km}$

Thus, the value in km = 1.76 km.

Interpretation Introduction

(j)

Interpretation:

Conversion of 34.9 mL to fl oz should be determined.

Concept Introduction:

Volume can be converted from mL to fl oz using the following conversion factor.

$\begin{array}{l}\text{1}\text{fl oz = 29}\text{.57}\text{mL}\\ \frac{\text{1}\text{fl oz}}{29.57\text{mL}}\end{array}$.

Answer to Problem 1.38P

The value in fl oz =1.18 fl oz.

Explanation of Solution

Converting 34.9 mL to fl oz:

$34.9\text{mL}\times \frac{\text{1}\text{fl oz}}{29.57\text{mL}}=1.18\text{fl}\text{oz}$

Thus, the value in fl oz =1.18 fl oz.