Chapter 1, Problem 1.37UKC

(a)

Interpretation Introduction

Interpretation:

An illustration that shows $\text{50}\text{mL}$ of hexane, whose density is $\text{0}\text{.65}\text{g/mL}$ is added to a beaker containing $\text{100 mL}$ of water has to be drawn.

Concept Introduction:

Density:  Density is the relationship between the mass of a substance to its volume.  Density is represented in grams per milliliter $\left(\text{g/mL}\right)$ or grams per cubic centimeter $\left(\text{g/cc}\right)\text{.}$  The formula is,

  $\text{Density=}\frac{\text{Mass}\left(\text{g}\right)}{\text{Volume}\left(\text{mL}\text{or}\text{cc}\right)}$

(b)

Interpretation Introduction

Interpretation:

An illustration that shows $\text{50}\text{mL}$ of dichloromethane, whose density is $\text{1}\text{.33}\text{g/mL}$ is added to a beaker containing $\text{100 mL}$ of water has to be drawn.

Concept Introduction:

Refer to part (a).