Connect 1 Semester Access Card for General Chemistry: The Essential Concepts
Connect 1 Semester Access Card for General Chemistry: The Essential Concepts
7th Edition
ISBN: 9781259692543
Author: Raymond Chang Dr.; Kenneth Goldsby Professor
Publisher: McGraw-Hill Education
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Chapter 1, Problem 1.37QP

(a)

Interpretation Introduction

Interpretation:

Height and weight of the given person has to be calculated in meter and kilogram unit.

Concept Introduction:

General unit conversions

1 m=3.28ft1 lb=453.6g1000g=1kg

(a)

Expert Solution
Check Mark

Answer to Problem 1.37QP

  • Height of the person in meter unit is 1.8m
  • Weight of the given person in kilogram unit is 83.0kg

Explanation of Solution

Height of the person is 6.0 ft

Weight of the given person is 183lb

General unit conversions

1 m=3.28ft1 lb=453.6g1000g=1kg

Calculation of height in meter unit

6.0ft×1m3.28ft=1.8m

Calculation of weight in kilogram unit

183lb×453.6g1lb×1kg1000g=83.0088kg=83kg

  • Height of the person in meter unit is 1.8m
  • Weight of the given person in kilogram unit is 83.0kg

Height and weight of the given person was calculated in meter and kilogram unit by the use of given data and application of general unit conversions.

(b)

Interpretation Introduction

Interpretation:

Distance in miles that light would travel in 1 hour has to be calculated.

Concept Introduction:

By definition, 1milesperhour=1.60kilometerperhour

(b)

Expert Solution
Check Mark

Answer to Problem 1.37QP

Speed limit in kilometers per hour is 112kilometerperhour

Explanation of Solution

Given,

Speed of light =70milesperhour

By definition, 1milesperhour=1.60kilometerperhour

Converting miles per hour to kilometer per hour,

70milesperhour=70×1.60kilometerperhour=112kilometerperhour

(c)

Interpretation Introduction

Interpretation:

Distance in miles that light would travel in 1 hour has to be calculated.

Concept Introduction:

(c)

Expert Solution
Check Mark

Answer to Problem 1.37QP

Distance in miles is 1.7281019kilometer

Explanation of Solution

Given,

Speed of light =3×1010cm/s

Speed of light in 1 hour

=3×1010cm/s×3600s=1.08×1014cm

Converting cm to km,

1.08×1014cm×105cm1km=1.08×1019km

By definition, 1miles=1.60kilometer

Converting miles per hour to kilometer per hour,

1miles=1.08×1019×1.60kilometerperhour=1.7281019kilometer

(d)

Interpretation Introduction

Interpretation:

The amount of lead (Pb) present in grams has to be calculated in the given amount of blood.

Concept Introduction:

ppm=massofsolutemassofsolution×106

(d)

Expert Solution
Check Mark

Answer to Problem 1.37QP

The amount of lead (Pb) present in the given amount of blood is 3.7×10-3gramoflead

Explanation of Solution

The amount of blood is 6.0×103gram

Content of lead is 0.62ppm

Convert the unit of g blood into g lead

0.62ppm=0.62gramPb1×106gramblood

Calculation of lead content in gram unit

6.0×103gramblood×0.62gramPb1×106gramblood=3.72×10-3gramPb=3.7×10-3gPb

The amount of lead is 3.7×10-3gPb

The amount of lead present in the given amount of blood was calculated by the use of given data and unit conversion.

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Chapter 1 Solutions

Connect 1 Semester Access Card for General Chemistry: The Essential Concepts

Ch. 1.7 - Prob. 2PECh. 1.7 - Prob. 1RCCh. 1 - Prob. 1.1QPCh. 1 - Prob. 1.2QPCh. 1 - Prob. 1.3QPCh. 1 - Prob. 1.4QPCh. 1 - Prob. 1.5QPCh. 1 - Prob. 1.6QPCh. 1 - 1.7 Do these statements describe chemical or...Ch. 1 - 1.8 Does each of these describe a physical change...Ch. 1 - Prob. 1.9QPCh. 1 - Prob. 1.10QPCh. 1 - 1.11 Classify each of these substances as an...Ch. 1 - Prob. 1.12QPCh. 1 - Prob. 1.13QPCh. 1 - Prob. 1.14QPCh. 1 - Prob. 1.15QPCh. 1 - Prob. 1.16QPCh. 1 - Prob. 1.17QPCh. 1 - Prob. 1.18QPCh. 1 - Prob. 1.19QPCh. 1 - Prob. 1.20QPCh. 1 - Prob. 1.21QPCh. 1 - Prob. 1.22QPCh. 1 - Prob. 1.23QPCh. 1 - Prob. 1.24QPCh. 1 - Prob. 1.25QPCh. 1 - Prob. 1.26QPCh. 1 - Prob. 1.27QPCh. 1 - Prob. 1.28QPCh. 1 - Prob. 1.29QPCh. 1 - Prob. 1.30QPCh. 1 - Prob. 1.31QPCh. 1 - Prob. 1.32QPCh. 1 - 1.33 The price of gold on a certain day in 2009...Ch. 1 - Prob. 1.34QPCh. 1 - Prob. 1.35QPCh. 1 - Prob. 1.36QPCh. 1 - Prob. 1.37QPCh. 1 - Prob. 1.38QPCh. 1 - Prob. 1.39QPCh. 1 - Prob. 1.40QPCh. 1 - Prob. 1.41QPCh. 1 - Prob. 1.42QPCh. 1 - Prob. 1.43QPCh. 1 - Prob. 1.44QPCh. 1 - Prob. 1.45QPCh. 1 - Prob. 1.46QPCh. 1 - Prob. 1.47QPCh. 1 - Prob. 1.48QPCh. 1 - Prob. 1.49QPCh. 1 - Prob. 1.50QPCh. 1 - Prob. 1.51QPCh. 1 - Prob. 1.52QPCh. 1 - Prob. 1.53QPCh. 1 - Prob. 1.54QPCh. 1 - Prob. 1.55QPCh. 1 - Prob. 1.56QPCh. 1 - Prob. 1.57QPCh. 1 - Prob. 1.58QPCh. 1 - Prob. 1.59QPCh. 1 - Prob. 1.60QPCh. 1 - Prob. 1.61QPCh. 1 - Prob. 1.62QPCh. 1 - Prob. 1.63QPCh. 1 - Prob. 1.64QPCh. 1 - Prob. 1.65QPCh. 1 - 1.66 A sheet of aluminum (Al) foil has a total...Ch. 1 - Prob. 1.67QPCh. 1 - Prob. 1.68QPCh. 1 - Prob. 1.69QPCh. 1 - Prob. 1.70QPCh. 1 - Prob. 1.71QPCh. 1 - Prob. 1.73SPCh. 1 - Prob. 1.74SPCh. 1 - Prob. 1.75SPCh. 1 - Prob. 1.76SPCh. 1 - 1.77 A pycnometer is a device for measuring the...Ch. 1 - Prob. 1.78SPCh. 1 - Prob. 1.79SPCh. 1 - Prob. 1.80SPCh. 1 - Prob. 1.81SP
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