Algebra 2
Algebra 2
1st Edition
ISBN: 9780078884825
Author: McGraw-Hill/Glencoe
Publisher: Glencoe/McGraw-Hill School Pub Co
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 0.5, Problem 20E
To determine

the ways can they choose the new singers.

Expert Solution & Answer
Check Mark

Answer to Problem 20E

The numbers of possibilities are 816possibilities .

Explanation of Solution

Given information :

It is given that a band is choosing 3 new backup singers from a group of 18 who try out.

In the given event, arrangement does not matter so it is combination.

The number of possibilities is given by,

  C183=18!15!×3!=18×17×16×15×14×13×12×11×10×9×8×7×6×5×4×3×215×14×13×12×11×10×9×8×7×6×5×4×3×2×3×2possibilities=18×17×163×2possibilities=3×17×16possibilities=816possibilities

So, the numbers of possibilities are 816possibilities .

Chapter 0 Solutions

Algebra 2

Ch. 0.1 - Prob. 11ECh. 0.1 - Prob. 12ECh. 0.2 - Prob. 1ECh. 0.2 - Prob. 2ECh. 0.2 - Prob. 3ECh. 0.2 - Prob. 4ECh. 0.2 - Prob. 5ECh. 0.2 - Prob. 6ECh. 0.2 - Prob. 7ECh. 0.2 - Prob. 8ECh. 0.2 - Prob. 9ECh. 0.2 - Prob. 10ECh. 0.2 - Prob. 11ECh. 0.2 - Prob. 12ECh. 0.2 - Prob. 13ECh. 0.2 - Prob. 14ECh. 0.2 - Prob. 15ECh. 0.2 - Prob. 16ECh. 0.2 - Prob. 17ECh. 0.2 - Prob. 18ECh. 0.3 - Prob. 1ECh. 0.3 - Prob. 2ECh. 0.3 - Prob. 3ECh. 0.3 - Prob. 4ECh. 0.3 - Prob. 5ECh. 0.3 - Prob. 6ECh. 0.3 - Prob. 7ECh. 0.3 - Prob. 8ECh. 0.3 - Prob. 9ECh. 0.3 - Prob. 10ECh. 0.3 - Prob. 11ECh. 0.3 - Prob. 12ECh. 0.3 - Prob. 13ECh. 0.3 - Prob. 14ECh. 0.3 - Prob. 15ECh. 0.3 - Prob. 16ECh. 0.3 - Prob. 17ECh. 0.3 - Prob. 18ECh. 0.3 - Prob. 19ECh. 0.3 - Prob. 20ECh. 0.3 - Prob. 21ECh. 0.3 - Prob. 22ECh. 0.3 - Prob. 23ECh. 0.3 - Prob. 24ECh. 0.4 - Prob. 1ECh. 0.4 - Prob. 2ECh. 0.4 - Prob. 3ECh. 0.4 - Prob. 4ECh. 0.4 - Prob. 5ECh. 0.4 - Prob. 6ECh. 0.4 - Prob. 7ECh. 0.4 - Prob. 8ECh. 0.4 - Prob. 9ECh. 0.4 - Prob. 10ECh. 0.4 - Prob. 11ECh. 0.4 - Prob. 12ECh. 0.4 - Prob. 13ECh. 0.4 - Prob. 14ECh. 0.4 - Prob. 15ECh. 0.4 - Prob. 16ECh. 0.5 - Prob. 1ECh. 0.5 - Prob. 2ECh. 0.5 - Prob. 3ECh. 0.5 - Prob. 4ECh. 0.5 - Prob. 5ECh. 0.5 - Prob. 6ECh. 0.5 - Prob. 7ECh. 0.5 - Prob. 8ECh. 0.5 - Prob. 9ECh. 0.5 - Prob. 10ECh. 0.5 - Prob. 11ECh. 0.5 - Prob. 12ECh. 0.5 - Prob. 13ECh. 0.5 - Prob. 14ECh. 0.5 - Prob. 15ECh. 0.5 - Prob. 16ECh. 0.5 - Prob. 17ECh. 0.5 - Prob. 18ECh. 0.5 - Prob. 19ECh. 0.5 - Prob. 20ECh. 0.6 - Prob. 1ECh. 0.6 - Prob. 2ECh. 0.6 - Prob. 3ECh. 0.6 - Prob. 4ECh. 0.6 - Prob. 5ECh. 0.6 - Prob. 6ECh. 0.6 - Prob. 7ECh. 0.6 - Prob. 8ECh. 0.6 - Prob. 9ECh. 0.6 - Prob. 10ECh. 0.6 - Prob. 11ECh. 0.6 - Prob. 12ECh. 0.7 - Prob. 1ECh. 0.7 - Prob. 2ECh. 0.7 - Prob. 3ECh. 0.7 - Prob. 4ECh. 0.7 - Prob. 5ECh. 0.7 - Prob. 6ECh. 0.7 - Prob. 7ECh. 0.7 - Prob. 8ECh. 0.7 - Prob. 9ECh. 0.7 - Prob. 10ECh. 0.7 - Prob. 11ECh. 0.7 - Prob. 12ECh. 0.7 - Prob. 13ECh. 0.7 - Prob. 14ECh. 0.7 - Prob. 15ECh. 0.7 - Prob. 16ECh. 0.7 - Prob. 17ECh. 0 - Prob. 1PRCh. 0 - Prob. 2PRCh. 0 - Prob. 3PRCh. 0 - Prob. 4PRCh. 0 - Prob. 5PRCh. 0 - Prob. 6PRCh. 0 - Prob. 7PRCh. 0 - Prob. 8PRCh. 0 - Prob. 9PRCh. 0 - Prob. 10PRCh. 0 - Prob. 11PRCh. 0 - Prob. 12PRCh. 0 - Prob. 13PRCh. 0 - Prob. 14PRCh. 0 - Prob. 15PRCh. 0 - Prob. 16PRCh. 0 - Prob. 17PRCh. 0 - Prob. 18PRCh. 0 - Prob. 19PRCh. 0 - Prob. 20PRCh. 0 - Prob. 21PRCh. 0 - Prob. 22PRCh. 0 - Prob. 23PRCh. 0 - Prob. 24PRCh. 0 - Prob. 25PRCh. 0 - Prob. 26PRCh. 0 - Prob. 27PRCh. 0 - Prob. 28PRCh. 0 - Prob. 29PRCh. 0 - Prob. 30PRCh. 0 - Prob. 31PRCh. 0 - Prob. 32PRCh. 0 - Prob. 33PRCh. 0 - Prob. 34PRCh. 0 - Prob. 1POCh. 0 - Prob. 2POCh. 0 - Prob. 3POCh. 0 - Prob. 4POCh. 0 - Prob. 5POCh. 0 - Prob. 6POCh. 0 - Prob. 7POCh. 0 - Prob. 8POCh. 0 - Prob. 9POCh. 0 - Prob. 10POCh. 0 - Prob. 11POCh. 0 - Prob. 12POCh. 0 - Prob. 13POCh. 0 - Prob. 14POCh. 0 - Prob. 15POCh. 0 - Prob. 16POCh. 0 - Prob. 17POCh. 0 - Prob. 18POCh. 0 - Prob. 19POCh. 0 - Prob. 20POCh. 0 - Prob. 21POCh. 0 - Prob. 22POCh. 0 - Prob. 23POCh. 0 - Prob. 24POCh. 0 - Prob. 25POCh. 0 - Prob. 26POCh. 0 - Prob. 27POCh. 0 - Prob. 28POCh. 0 - Prob. 29POCh. 0 - Prob. 30POCh. 0 - Prob. 31POCh. 0 - Prob. 32POCh. 0 - Prob. 33POCh. 0 - Prob. 34PO
Knowledge Booster
Background pattern image
Algebra
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, algebra and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Algebra and Trigonometry (6th Edition)
Algebra
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:PEARSON
Text book image
Contemporary Abstract Algebra
Algebra
ISBN:9781305657960
Author:Joseph Gallian
Publisher:Cengage Learning
Text book image
Linear Algebra: A Modern Introduction
Algebra
ISBN:9781285463247
Author:David Poole
Publisher:Cengage Learning
Text book image
Algebra And Trigonometry (11th Edition)
Algebra
ISBN:9780135163078
Author:Michael Sullivan
Publisher:PEARSON
Text book image
Introduction to Linear Algebra, Fifth Edition
Algebra
ISBN:9780980232776
Author:Gilbert Strang
Publisher:Wellesley-Cambridge Press
Text book image
College Algebra (Collegiate Math)
Algebra
ISBN:9780077836344
Author:Julie Miller, Donna Gerken
Publisher:McGraw-Hill Education
Find number of persons in a part with 66 handshakes Combinations; Author: Anil Kumar;https://www.youtube.com/watch?v=33TgLi-wp3E;License: Standard YouTube License, CC-BY
Discrete Math 6.3.1 Permutations and Combinations; Author: Kimberly Brehm;https://www.youtube.com/watch?v=J1m9sB5XZQc;License: Standard YouTube License, CC-BY
How to use permutations and combinations; Author: Mario's Math Tutoring;https://www.youtube.com/watch?v=NEGxh_D7yKU;License: Standard YouTube License, CC-BY
Permutations and Combinations | Counting | Don't Memorise; Author: Don't Memorise;https://www.youtube.com/watch?v=0NAASclUm4k;License: Standard Youtube License
Permutations and Combinations Tutorial; Author: The Organic Chemistry Tutor;https://www.youtube.com/watch?v=XJnIdRXUi7A;License: Standard YouTube License, CC-BY