Explanation Given Information: The provided expression is 2 1 3 2 − 1 2 2 3 2 − 1 3 . Formula used: For any real number a . a m a n = a m + n Negative exponent identity, p − n = 1 p n Where p is any real number other than 0. Calculation: Consider the provided expression 2 1 3 2 − 1 2 2 3 2 − 1 3 . This can be rearranged as, ( 2 1 3 2 − 1 3 ) ⋅ ( 2 − 1 2 2 3 ) Now use the identity a m a n = a m + n , to simplify further

7th Edition

ISBN: 9781337291248

Author: Waner, Stefan.

Publisher: Cengage Learning,

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Chapter 0.2, Problem 100E

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To calculate: The simplified form of expression 2132−12232−13.

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Chapter 0.2, Problem 99E

Chapter 0.2, Problem 101E

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Chapter 0 Solutions

Applied Calculus

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Ch. 0.1 - Prob. 11E Ch. 0.1 - Prob. 12E Ch. 0.1 - Prob. 13E Ch. 0.1 - Calculate each expression in Exercises 124, giving...Ch. 0.1 - Prob. 15E Ch. 0.1 - Prob. 16E Ch. 0.1 - Calculate each expression in Exercises 124, giving...Ch. 0.1 - Prob. 18E Ch. 0.1 - Prob. 19E Ch. 0.1 - Prob. 20E Ch. 0.1 - Prob. 21E Ch. 0.1 - Prob. 22E Ch. 0.1 - Prob. 23E Ch. 0.1 - Prob. 24E Ch. 0.1 - Prob. 25E Ch. 0.1 - Prob. 26E Ch. 0.1 - Prob. 27E Ch. 0.1 - Prob. 28E Ch. 0.1 - Prob. 29E Ch. 0.1 - Prob. 30E Ch. 0.1 - Prob. 31E Ch. 0.1 - Prob. 32E Ch. 0.1 - Prob. 33E Ch. 0.1 - Prob. 34E Ch. 0.1 - Prob. 35E Ch. 0.1 - Prob. 36E Ch. 0.1 - Convert each expression in Exercises 25-50 into...Ch. 0.1 - Prob. 38E Ch. 0.1 - Prob. 39E Ch. 0.1 - Prob. 40E Ch. 0.1 - Prob. 41E Ch. 0.1 - Prob. 42E Ch. 0.1 - Prob. 43E Ch. 0.1 - Prob. 44E Ch. 0.1 - Prob. 45E Ch. 0.1 - Prob. 46E Ch. 0.1 - Prob. 47E Ch. 0.1 - Prob. 48E Ch. 0.1 - Prob. 49E Ch. 0.1 - Prob. 50E Ch. 0.2 - Evaluate the expression sin Exercises 116. 33 Ch. 0.2 - Prob. 2E Ch. 0.2 - Evaluate the expression sin Exercises 116. 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The simplified form of expression 2 1 3 2 − 1 2 2 3 2 − 1 3 .

Solution Summary: The author explains the simplified form of the provided expression 2raisebox1ex1!

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To calculate: The simplified form of expression 2132−12232−13.

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Chapter 0 Solutions