Chapter 0, Problem 4P

To determine

To find: the surface area of middle sized canvas

Answer to Problem 4P

Thus, the surface area of middle sized canvas is, $283.5\text{sq}.\text{ in}\text{. }$

Explanation of Solution

Given:

Store sells 5 different sized canvases.

The middle-size canvas area is 3.5 times larger than the extra-small canvas area

The surface area of the extra-small canvas is 81 square inches.

Calculation:

Consider that there are 5 different sized canvases.

Size of middle one $=3.5\times$ size of extra-small canvas

As, size of extra small canvas $=81$ sq. in

Size of middle one $=3.5\times 81$

Now, for decimal multiplication, proceed like normal multiplication.

But, first count digits after decimal in both entries and then place decimal points after that many digits from right in product.

  $\begin{array}{r}\hfill 81\\ \hfill \underset{\_}{\times 3.5}\\ \hfill 40.5\\ \hfill \underset{\_}{+243.0}\\ \hfill 283.5\end{array}$

Thus, the surface area of middle sized canvas is, $283.5\text{sq}.\text{ in}\text{. }$

Conclusion:

Thus, the surface area of middle sized canvas is, $283.5\text{sq}.\text{ in}\text{. }$