you will be given some values for a vector and will need to determine the missing values. Then, you will test your answers using one of the force tables. All angles need to be in the range from 0 to 360°, where 0° points along the positive x-axis, 90° points along the positive y-axis, 180° points along the negative x-axis, and 270° points along the negative y-axis. For the vector-A, the negative of a vector is antiparallel to the vector itself. Ay Set la 1b 1c 1d 2a 7h Ax 30 37 -45 -50 32 -42 -25 48 Magnitude of A 43.86 ✓ X 45.97 200 134 Angle of A 46.85 311.38 347⁰ Angle of -A ✔ 226.85 ✔° 131.38 D 0 0 ..... 0
you will be given some values for a vector and will need to determine the missing values. Then, you will test your answers using one of the force tables. All angles need to be in the range from 0 to 360°, where 0° points along the positive x-axis, 90° points along the positive y-axis, 180° points along the negative x-axis, and 270° points along the negative y-axis. For the vector-A, the negative of a vector is antiparallel to the vector itself. Ay Set la 1b 1c 1d 2a 7h Ax 30 37 -45 -50 32 -42 -25 48 Magnitude of A 43.86 ✓ X 45.97 200 134 Angle of A 46.85 311.38 347⁰ Angle of -A ✔ 226.85 ✔° 131.38 D 0 0 ..... 0
Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter1: Introduction And Vectors
Section: Chapter Questions
Problem 14OQ: A vector points from the origin into the second quadrant of the xy plane. What can you conclude...
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Magnitude of
Angle of A =
Angle of -A =
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