you will be given some values for a vector and will need to determine the missing values. Then, you will test your answers using one of the force tables. All angles need to be in the range from 0 to 360°, where 0° points along the positive x-axis, 90° points along the positive y-axis, 180° points along the negative x-axis, and 270° points along the negative y-axis. For the vector-A, the negative of a vector is antiparallel to the vector itself. Ay Set la 1b 1c 1d 2a 7h Ax 30 37 -45 -50 32 -42 -25 48 Magnitude of A 43.86 ✓ X 45.97 200 134 Angle of A 46.85 311.38 347⁰ Angle of -A ✔ 226.85 ✔° 131.38 D 0 0 ..... 0

Principles of Physics: A Calculus-Based Text
5th Edition
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
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Chapter1: Introduction And Vectors
Section: Chapter Questions
Problem 14OQ: A vector points from the origin into the second quadrant of the xy plane. What can you conclude...
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In this lab you will be given some values for a vector and will need to determine the missing values. Then, you will test your answers using one of the force tables. All angles need to be in the range from 0 to 360°, where 0° points along the positive x-axis,
90° points along the positive y-axis, 180° points along the negative x-axis, and 270° points along the negative y-axis. For the vector -A, the negative of a vector is antiparallel to the vector itself.
Ay
Set
1a
1b.
1c
1d
2a
2b
2c
2d
Sa
3a
3b
30
3c
3d
4a
4b
4c
4d
Ax
30
37
-45
-50
85
100
-54
-90
32
-42
-25
48
-95
98
-74
83
Magnitude of A
43.86
45.97
200
124
121
139
✔
X
Angle of A
46.85
311.38
347⁰
84⁰
157⁰
212°
212
25°
2
283⁰
cae
AVV
139⁰
262⁰
EVE
265⁰
70°
324⁰
103⁰
Angle of -A
✓ 。 226.85
✔° 131.38
0
0
✔
✔
0
0
a
o
B
2
P
0
O
0
0
0
Ⓒ
O
0
0
rinn: therefore there are two possibilities. In these
Transcribed Image Text:In this lab you will be given some values for a vector and will need to determine the missing values. Then, you will test your answers using one of the force tables. All angles need to be in the range from 0 to 360°, where 0° points along the positive x-axis, 90° points along the positive y-axis, 180° points along the negative x-axis, and 270° points along the negative y-axis. For the vector -A, the negative of a vector is antiparallel to the vector itself. Ay Set 1a 1b. 1c 1d 2a 2b 2c 2d Sa 3a 3b 30 3c 3d 4a 4b 4c 4d Ax 30 37 -45 -50 85 100 -54 -90 32 -42 -25 48 -95 98 -74 83 Magnitude of A 43.86 45.97 200 124 121 139 ✔ X Angle of A 46.85 311.38 347⁰ 84⁰ 157⁰ 212° 212 25° 2 283⁰ cae AVV 139⁰ 262⁰ EVE 265⁰ 70° 324⁰ 103⁰ Angle of -A ✓ 。 226.85 ✔° 131.38 0 0 ✔ ✔ 0 0 a o B 2 P 0 O 0 0 0 Ⓒ O 0 0 rinn: therefore there are two possibilities. In these
Expert Solution
Step 1

As per guidelines, only 3 subparts are solved here.

Magnitude of A =Ax2+Ay2

Angle of A = tan-1(AyAx)

Angle of -A = 180°+angle of A

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