You titrate a 25.00 mL solution of hydrochloric acid, HCl, with a 0.2015 M sodium hydroxide, NaOH, solution. The titration required 39.73 mL of the sodium hydroxide to reach the endpoint. What is the concentration (molarity) of the hydrochloric acid? HCI + NaOH →NaCl + H₂O Student work: 39.73 mL NaOH 25.00 mL HCI 1 L 1000 mL 1000 mL HCI 1 L HCI 0.0080055 mol HCI 0.02500 L HCI = 0.2015 mol NaOH 1 L NaOH 0.02500 mol 0.3202 M HCI 0.0080055 mol Read the feedback statements below and chose all that are applicable to the work shown. Choose one or more: The unit cancellation is not correct. The conversions to from mL to L do not need to be shown since they cancel out. The final answer has an incorrect number of s.f. (it should have 4 s.f.) The final answer has an incorrect number of s.f. (it should have 3 s.f.) Units do not cancel properly. The stoichiometry step to convert mol NaOH to mol HCI is not shown. All data collected, work shown, and final answer are recorded and shown correctly.

Classify each chemical reaction: 16K (s) + Sg (s)→ 8K₂S (s) HBr(aq) + NaOH(aq) → NaBr(aq) + H,O() CuSO (aq) + Zn CrO (aq) → ZnSO₂ (aq) + CuCro(s) KBr(aq) + AgNO3(aq) → KNO₂ (aq) + AgBr(s) Explanation reaction P TH F2 Check 80 F3 TAAR 4 888 F4 % 45 type of reaction (check all that apply) combination single replacement double replacement decomposition combination single replacement double replacement decomposition combination single replacement double replacement decomposition combination single replacement double replacement decomposition 42 A X 6 1 Oprecipitation combustion acid-base MacBook Air FÖ precipitation combustion acid-base precipitation combustion acid-base Oprecipitation combustion acid-base | 20 7 分 F7 8 DII F8 2023 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility 9 F9 0 A F10 A S ? F11 olo 18 Ar F12

What is the minimum volume of 2.47 mol L−1 HCl(aq) required to dissolve 12.3 g Mn metal? The atomic weight of Mn is 54.94 g mol−1. Mn(s) + HCl(aq) ⟶ MnCl2(aq) + H2(g)

When the following molecular equation is balanced using the smallest possible integer coefficients, the values of these coefficients are: HgO (s) →→→ Hg (1) + 0₂ (g)

Part 3: What mass of tin was used to make the tin solution? In a similar experiment, a sample of tin metal was dissolved in nitric acid to produce 28.00 mL of solution containing Sn²+. Titration analysis resulted in the calculation that the concentration of Sn²+ in this solution was 0.65 mol/L. b. What mass of tin was used to make the tin solution? Find the mass of the Sn(s) in g: (give your answer to 2 decimal places) Your Answer: Answer

A food chemist determines the concentration of acetic acid in a sample of apple cider vinegar by acid- base titration. The density of the sample is 1.01 g/mL. The titrant is 1.002 M NaOH. The average volume of titrant required to titrate 25.00 mL aliquots of the vinegar is 20.78 mL. What is the concentration of acetic acid in the vinegar? Express your answer the way a food chemist probably would: as a percent by mass.