Chemistry
10th Edition
ISBN: 9781305957404
Author: Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Lead ions can be precipitated from solution with KClKCl according to the following reaction:
Pb2+(aq)+2KCl(aq)→PbCl2(s)+2K+(aq)Pb2+(aq)+2KCl(aq)→PbCl2(s)+2K+(aq)
When 28.8 gg KClKCl is added to a solution containing 25.8 gg Pb2+Pb2+, a PbCl2PbCl2 precipitate forms. The precipitate is filtered and dried and found to have a mass of 29.3 gg .
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