Concept explainers
Y&F 27.51
You measure the charge-to-mass ratio q/m for a particle with positive charge in the following way: The particle starts from rest, is accelerated through a potential difference ΔV, and attains a velocity with magnitude v. It then enters a region of uniform magnetic field B=0.200 T that is directed perpendicular to the velocity; the particle moves in a path that is an arc of a circle of radius R. You measure R as a function of ΔV. You plot your data as R2 (in units of m^2) versus ΔV (in V) and find that the values lie close to a straight line that has slope 1.04×10−6 m2/V. What is the value of q/m for this particle?
Slop of graph = 1.04 × 10-6 m2/v
Magnetic field B = 0.2 T
Trending nowThis is a popular solution!
Step by stepSolved in 2 steps
- In the figure, an electron accelerated from rest through potential difference V1-1.26 kV enters the gap between two parallel plates having separation d = 19.6 mm and potential difference V2- 52.4 V. The lower plate is at the lower potential. Neglect fringing and assume that the electron's velocity vector is perpendicular to the electric field vector between the plates. In unit-vector notation, what uniform magnetic field allows the electron to travel in a straight line in the gap? Number ( o ĵ+ i R) Units mT 124.7arrow_forward(a) A velocity selector consists of electric and magnetic fields described by the expressions E = Ek and B = Bj, with B = 24.0 mT. Find the value of E (in kV/m) such that a 780 eV electron moving in the negative x-direction is undeflected. 3.97e24 How do you determine the speed of the electron if you know its kinetic energy? kV/m (b) What If? For the value of E found in part (a), what would the kinetic energy of a proton have to be (in MeV) for it to move undeflected in the negative x-direction? MeVarrow_forwardIn the figure, an electron accelerated from rest through potential difference V₁-1.03 kV enters the gap between two parallel plates having separation d-17.2 mm and potential difference V₂-108 V. The lower plate is at the lower potential. Neglect fringing and assume that the electron's velocity vector is perpendicular to the electric field vector between the plates. In unit- vector notation, what uniform magnetic field allows the electron to travel in a straight line in the gap? Number (0 7+0 3.30e-4 A) Units mTarrow_forward
- In the figure, an electron accelerated from rest through potential difference V₁-1.12 kV enters the gap between two parallel plates having separation d = 21.0 mm and potential difference V₂= 129 V. The lower plate is at the lower potential. Neglect fringing and assume that the electron's velocity vector is perpendicular to the electric field vector between the plates. In unit-vector notation, what uniform magnetic field allows the electron to travel in a straight line in the gap? Number ( i + k) Unitsarrow_forwardA pellet which holds a charge of 10 coulombs is moving upwards (+Y) and driven by an electric field in the same direction with a magnitude of 50 V/m. There is a magnetic field with a magnitude of 25 Tesla’s pointing downwards (-Y). How fast does the pellet need to be going for the magnetic force to cancel the electric force? Group of answer choices 0.5 m/s 2 m/s 4 m/s The forces will cancel out at any speed the pellet may be travelling In this case, the electric force cannot be canceled out by the magnetic forcearrow_forwardA beam of electrons with velocity vx = 5 x105 m/s is introduced into a uniform magnetic field Bz = 30 mTesla. An electric field Ey is applied perpendicular to both the initial velocity and the magnetic field. What value of electric field must be applied to leave the electron beam undeflected?arrow_forward
- If an electron that’s entering a magnetic field B=2.0 with a velocity of V =2.0x10^7 m/s parallel to B experiences a magnetic force F b= ????arrow_forwardAnswer?arrow_forwardThe Bainbridge spectrometer works by ionizing particles, sending them through a velocity selector, and then detecting a given charge-to-mass ratio based on its trajectory in a uniform magnetic field (See Ch 11.7 in your book). Suppose your spectrometer works by altering the electric field of the velocity selector to scan for ions. If a singly-charged ion of mass 140.9 amu required an electric field of 1.9 N/C, what electric field would be necessary to detect a doubly-charged ion of mass 161.9? Give your answer in units of N/C.arrow_forward
- An electron moves with velocity v =(5.0i−5.0j) ×104 m/s in a magnetic field B = (−0.73i+0.70j) T. Determine the z-component of the force on the electron. Express your answer using two significant figures.arrow_forwardAn electron of kinetic energy 41.5 keV moves in a circular orbit perpendicular to a magnetic field of 0.645 T. Find the radius of the orbit.Find the period of the motion.arrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON