In the figure, an electron accelerated from rest through potential difference V₁-1.03 kV enters the gap between two parallel plates having separation d-17.2 mm and potential difference V₂-108 V. The lower plate is at the lower potential. Neglect fringing and assume that the electron's velocity vector is perpendicular to the electric field vector between the plates. In unit- vector notation, what uniform magnetic field allows the electron to travel in a straight line in the gap?

A charged particle is entering a squared region of space with a uniform magnetic field. The sides of the region are 6 m wide. The particle enters the region exactly in the middle of one of the sides in a direction perpendicular to it, as in the Figure below. The charge of the particle is q = 20.0μC, its mass is m = 6.0 × 10-¹6 kg, and the velocity of the particle is |v| = 5 × 10³ m/s. How strong is the magnetic field so that the particle escapes such region in a direction perpendicular to the one it entered? See Figure for more details. XX XXXXXX :XXXXXXX XX XXX:

An electron in the beam of a cathod-ray tube is accelerated by a potential difference of 2.14 kV . Then it passes through a region of transverse magnetic field, where it moves in a circular arc with a radius of 0.190 m . What is the magnitude of the field?

An electron initially at rest is accelerated through a potential difference of 3 kV in the positive x- direction. It enters a region where a uniform magnetic field of 5.0-mT is in a positive y-direction (perpendicular to the velocity of the electron). Calculate the radius of the path this electron will follow in the magnetic field. (e = 1.60 × 10-19 c, m electron = 9.11 × 10¯31 kg)

Aircraft sometimes acquire small static charges. Suppose a supersonic jet has a 0.35 μC charge and flies due west at a speed of 640 m/s over the Earth’s south magnetic pole, where the 8.00 × 10-5 T magnetic field points straight up. v = 640 m/sq = 0.35 μC What is the magnitude of the magnetic force on the plane, in newtons?

An electron that has velocity т i = (2.0 x 106)i+ (3.0 × 106 10", %3D moves through the uniform magnetic field B = (0.030 T)î – (0.15T)f. (a) Find the force on the electron due to the magnetic field. (b) Repeat your calculation for a proton having the same velocity.

Answer?

An electron is accelerated through 2500 V from rest and then enters a region where there is a uniform 1.60 T magnetic field. What are the maximum and minimum magnitudes of the magnetic force acting on this electron?

A oxygen ion with a -2 charge is traveling in the +z direction. It enters a region of uniform magnetic field that points to the -y direction. When the ion enters this region, which direction will it be deflected?