You have a aqueous solution of NaCl that has a freezing point of -6.55°C. Assuming a van't Hoff factor of 1.9 for NaCl, what is the mass percent of chloride ion in the solution? (Kf for water is 1.86°C･kg/mol).

When 225. of urea (CH,N,0) are dissolved in 1200. g Oof a certain mystery g liquid x, the freezing point of the solution is 8.4 °c lower than the freezing point of pure x. On the other hand, when 225. g of sodium chloride are dissolved in the same mass of x, the freezing point of the solution is 14.5 °C lower than the freezing point of pure x. olo Ar Calculate the van't Hoff factor for sodium chloride in x. Be sure your answer has a unit symbol, if necessary, and is rounded to the correct number of significant digits. i = |

The normal freezing point of a certain liquid X is 0.60°C, but when 0.14 kg of barium hydroxide (BaOH2) are dissolved in 900.g of X the solution freezes at −1.6°C instead. Use this information to calculate the molal freezing point depression constant Kf of X. Round your answer to 2 significant digits.

A pure solvent has a freezing point of −3.62°C. A solute is added to the solvent and the solution freezes at −7.81°C. If the solute is RbF what is the molality of the solution. kf,solvent = 3.68°C•kg/mol

18) A solution is made by dissolving 0.840 moles of sodium hydroxide in 300.0 g of water. If the van't Hoff factor, i, for this particular concentration is 1.70, what is the expected freezing point of this solution? Kf = 1.86 °C m-1. A) +0.80°C B)-2.66°C C) -9.97°C D) -8.85°C E) +3.06°C 18)

when 7.94 g of xylene was added to 132.5 g of cyclohexane, the freezing point of the solution was -4.9 C. what is the molar mass of xylene?

How many moles of C,H,0 were dissolved into 91.340 g of ethylene glycol, if the freezing point of the resulting ideal C,H,O-ethylene glycol solution was –15.1 °C? freezing point of ethylene glycol =-12.9 °C kf(ethylene glycol) = 3.11 °C/m

1.613 g sample of an unknown nonionizing molecular compound is added to 250.0 g of benzene(C6H6, MW = 78.11 g/mol). The normal freezing point of the solution is 0.17 C lower than the normalfreezing point of pure benzene. Based on this information, find the molecular weight of the unknowncompound. benzene =  Kf = 5.12 kg x Degrees C/mol.

Help with the following question

When 14.4 g14.4 g of an organic compound known to be 55.81% C55.81% C, 7.0% H7.0% H, and 37.17% O37.17% O by mass is dissolved in 825.8 g825.8 g of benzene, the freezing point is 4.80 ∘C4.80⁢ ∘C. The normal freezing point of benzene is 5.49 ∘C5.49⁢ ∘C. What is the molecular formula for the organic compound? Assume that the organic compound is a molecular solid and does not ionize in water. ?fKf values for various solvents are given in the colligative constants table. molecular formula: CHO