You are throwing a ball for the second time. If the ball leaves your hand with twice the velocity it had on your first throw, its horizontal range R (compared to your first serve) would be Hint: look at formula for horizontal Range and figure out how Range is related to initial velocity (A) 1.4 times as much B) half as much twice as much (D) four times as much
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- Professional golfers can drive the ball over 200 m. While air resistance is significant, its effects are nearly canceled because lift is gained from backspin on the ball, and so a reasonable description of the ball’s trajectory is obtained if air resistance is neglected. Suppose a golfer hits a ball 200 m on level ground, giving it an initial velocity at an angle of 45o. The duration of the impact of the club and ball has been measured to be 1.00 ms. c) Find the average force exerted by the club on the ball. d) Find the average shear deformation of the club's 0.800 m long and 1.00 cm diameter steel shaft.A projectile is fired at 30° above the horizontal at a speed of 200 m/s. a) Find the time of flight or “hang time.” (how long is it in the air?) (calculate in seconds) b) Find the range of the projectile. (calculate in M)Two carts have velocities vand v, respectively. At t = 0 the distance between the two carts were zero. A passenger in cart A wants to throw a ball to cart B. The ball's initial speed with respect to cart A is vo. (a) What angle should the projectile have to reach cart 2? (b) What will be the projectile's speed at maximum height with respect to cart A, cart B, and the ground respectively? A UA B VB
- Hello, Can someone please show how to solve problem 4? Thank you!For a projectile lunched with an initial velocity of v0 at an angle of θ (between 0 and 90o) , a) derive the general expression for maximum height hmax and the horizontal range R. b) For what value of θ gives the highest maximum height? Solution The components of v0 are expressed as follows: vinitial-x = v0cos(θ) vinitial-y = v0sin(θ)What is the unit of the range of the projectile? Select one: O Kg O m/s O Newton O meters O seconds Why do you need to put on goggles for this experiment? Select one: O To avoid eyes injury O To read the meter tape more accurately O None of them O To take accurate measurements O To adjust the angle easily
- Kindly fill in the blanks. For a projectile lunched with an initial velocity of v0 at an angle of θ (between 0 and 90o): a) Derive the general expression for maximum height hmax and the horizontal range R. b) For what value of θ gives the highest maximum height? The components of v0 are expressed as follows: vinitial-x = v0cos(θ) vinitial-y = v0sin(θ)Problem For a projectile lunched with an initial velocity of vo at an angle of 0 (between 0 and 90°), a) derive the general expression for maximum height hmax and the horizontal range R. b) For what value of e gives the highest maximum height? Solution The components of vo are expressed as follows: Vinitial-x = Vocos(0) Vinitial-y = Vosin(e) a) Let us first find the time it takes for the projectile to reach the maximum height. Using: Vfinal-y = Vinitial-y + ayt since the y-axis velocity of the projectile at the maximum height is Vfinal-y %3D Then, Vinitial-y + ayt Substituting the expression of vinitial-y and ay = -g, results to the following: t Thus, the time to reach the maximum height is tmax-height = We will use this time to the equation Yfinal - Yinitial = Vinitial-yt + (1/2)ayt if we use the time taken to reach the maximum height, therefore, the displacement will yield the maximum height, so hmax = Vinitial-yt + (1/2)ay? substituting, the vinitial-y expression above, results to…For the following exercises, use this scenario: A dart is thrown upward with an initial velocity of 65 mm per second at an angle of elevation of 52°. Consider the horizontal and vertical positions of the dart at any time t. Neglect air resistance. Graph and state the domain and range for each parametric equation. Plot the minimum and maximum heights of the dart. Plot the minimum and maximum horizontal positions of the d