MATLAB: An Introduction with Applications
6th Edition
ISBN: 9781119256830
Author: Amos Gilat
Publisher: John Wiley & Sons Inc
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The standard error for is equal to 0.113. The test statistic for the hypothesis test specified in question 9 is equal to:
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- Perform the test of hypothesis on the following scenarios. A brand of powdered milk is advertised as having a net weight of 250 grams. A curious consumer obtained the net weight of 10 randomly selected cans. The values obtained are 256, 248, 242, 245, 246, 248, 250, 255, 243, and 249 grams. Is there reason to believe that the average net weight of the powdered milk cans is less than 250 grams at 10% level of significance? Assume the net weight is normally distributed with unknown population variance. Note: pls follow the given steps in the photo attachedarrow_forwardUse the six steps of hypothesis testing to answer the following question. Remember to determine if the problem is a Z test or T test as that will influence your critical value. You work at a cereal plant and believe the machines are under filling the boxes. All boxes should contain 20 ounces of cereal. You draw a sample of 70 boxes and find an average of 18.6 ounces with a standard deviation of 2.8. Are the boxes being under filled?arrow_forwardA company which designs sports shoes has made an improvement to their popular running shoe. They hope that athletes wearing the new running shoe will be able to run faster over short distances. They will use a paired sample to determine whether the mean time to run 100 meters for sprinters wearing the new running shoe is less than the mean time to run the 100 meters for sprinters wearing the old running shoe. Determine the null and alternative hypotheses for the proposed hypothesis test. O A. Let u, denote the mean time to run 100 meters for sprinters wearing the new running shoe and let u, denote the mean time to run 100 meters for sprinters wearing the old running shoe. The null and alternative hypotheses are Ho: H1 H2 O B. Let u, denote the mean time to run 100 meters for sprinters wearing the new running shoe and let u, denote the mean time to run 100 meters for sprinters wearing the old running shoe. The null and alternative hypotheses are ZH> '1:H pue Zz :°H OC. Let u, denote…arrow_forward
- In a two- tailed hypothesis test the test statistic is determined to be Z = - 2.4 . The p- value for this test is A. 0.0164 B. -1.250 C. 0.0062 D. 0.0124arrow_forwardA two-proportions z-test is to be performed using the P-value approach. Use the given sample data to find the P-value for the hypothesis test. x₁ = 11, n₁ =200, x₂ = 8, n₂ = 100; Ho: P₁ = P₂, H₂: P₁ P₂, α=0.01 O A. 0.1011 B. 0.3844 C. 0.4010 O D. 0.2005arrow_forwardConsider the hypothesis test below. Ho P1 Ha P₁ The following results are for independent samples taken from the two populations. Sample 1 n1 = 100 P₁ = 0.28 P2 ≤ 0 P20 Use pooled estimator of p. a. What is the p-value (to 4 decimals)? Use Table 1 from Appendix B. 0 Sample 2 7₂ = 300 P2 = 0.15arrow_forward
- Suppose that in a random selection of 100 colored candies, 25% of them are blue. The candy company claims that the percentage of blue candies is equal to 26%. Use a 0.01 significance level to test that claim. Identify the null and alternative hypotheses for this test. Choose the correct answer below. O A. Ho: p=0.26 H₁: p0.26 O C. Ho: p=0.26 H₁: p=0.26 O D. Ho: p=0.26 H₁: p=0.26 Identify the test statistic for this hypothesis test. The test statistic for this hypothesis test is (Round to two decimal places as needed.) Identify the P-value for this hypothesis test. The P-value for this hypothesis test is (Round to three decimal places as needed.) Identify the conclusion for this hypothesis test. O A. Reject Ho. There is sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 26% B. Reject Ho. There is not sufficient evidence to warrant rejection of the claim that the percentage of blue candies is equal to 26% C. Fail to reject Hỏ. There is…arrow_forwardConsider the following hypothesis test. H0: ? = 100 Ha: ? ≠ 100 A sample of 65 is used. Identify the p-value and state your conclusion for each of the following sample results. Use ? = 0.05. (a) x = 104 and s = 11.5 Find the value of the test statistic. (Round your answer to three decimal places.) Find the p-value. (Round your answer to four decimal places.) State your conclusion. Reject H0. There is sufficient evidence to conclude that ? ≠ 100.Do not reject H0. There is insufficient evidence to conclude that ? ≠ 100. Do not reject H0. There is sufficient evidence to conclude that ? ≠ 100.Reject H0. There is insufficient evidence to conclude that ? ≠ 100. (b) x = 96.5 and s = 11.0 Find the value of the test statistic. (Round your answer to three decimal places.) Find the p-value. (Round your answer to four decimal places.) p-value = State your conclusion. Reject H0. There is sufficient evidence to conclude that ? ≠ 100.Do not reject H0. There is insufficient…arrow_forwardThe one-sample ?‑statistic for a test of ?0:?=0 versus ?1:?≠0 based on ?=15 observations has the value ?=−2.138, where ?0 and ?1 are the null and alternative hypotheses, respectively. The sample size is denoted by ?. Use this ?‑table to determine which two ?-values bracket the ?-value of the test. Report your answer as listed in the given ?‑table.arrow_forward
- questions : "determine the null and alternative hypotheses" and the pnes below it.arrow_forwardSuppose that in a random selection of 100 colored candies, 20% of them are blue. The candy company claims that the percentage of blue candies is equal to 26%. Use a 0.01 significance level to test that claim. Identify the null and alternative hypotheses for this test. Choose the correct answer below. O A. Ho: p +0.26 H₁: p=0.26 O B. Ho: p=0.26 H₁: p=0.26 O C. Ho: p = 0.26 H₁: p>0.26 O D. Ho: p=0.26 H₁: p<0.26arrow_forwardThe p-value for a hypothesis test turns out to be 0.00694. At a 9% level of significance, what is the proper decision? Reject H0H0 Fail to reject H0arrow_forward
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