You are helping your friend unload their moving truck. You are starting to get lazy, so you just set the boxes on the ramp down to the ground to let them slide down. You try to do the same with a small chair, but notice that it slides down the ramp much more slowly. Being a budding physicist, you reason that this is because the chair/ramp combination has a larger coefficient of kinetic friction than the boxes/ramp combination. The chair accelerates down the ramp at 0.72 ? ? 2 . The ramp is at an angle of 31° below the horizontal and the chair has a mass of 13 ??. Find the coefficient of friction between the chair and the ramp.
Draw a free body diagram 2. Set up a coordinate system. You must correctly follow our rule to align the net acceleration for the system to be along a single axis (it cannot have an x- and a y-component). Correctly set up Newton’s Second Law (sum of the forces) in both the x- and y- direction. Correctly use either sinθ or cosθ as appropriate.
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- A driver in a 1000.0kg car traveling at 28 m/s slams on the brakes and skids to a stop. If the coefficient of friction between the tires and the road is 0.80, how long will the skid marks be? O 50 m 63 m 40 m O 47 marrow_forwardIt's a snowy day and you're pulling a friend along a level road on a sled. You've both been taking physics, so she asks what you think the coefficient of friction between the sled and the snow is. You've been walking at a steady 1.5 m/s, and the rope pulls up on the sled at a 44° angle. You estimate that the mass of the sled, with your friend on it, is 70 kg and that you're pulling with a force of 71 N. Part A What answer will you give? ΠΙ ΑΣΦ Submit Request Answer ?arrow_forwardA 40 N box is resting on a table when a 20 N force is applied to it horizontally. The coefficients of static and kinetic friction are 0.3 and 0.1, respectively. Which of the following best describes the resulting motion of the box? The motion of the box cannot be determined with the given information. The box accelerates in the direction of the applied force. The box remains at rest. The box moves with a constant velocity in the direction of the applied force.arrow_forward
- Consider a box sitting on a table. It takes a large force to move it at constant speed. List at least two ways you could reduce the force needed to move the box at constant speed.arrow_forwardAn ice hockey puck is sliding over a frictionless horizontal surface with a constant velocity of vo = 10.2 m/s. Find the velocity of the puck after it passes a rough area of length L 6 m and with the kinetic friction coefficient u = 0.33 as shown below. Hint: the mass of the puck is not needed, you can either calculate everything per unit of mass or, if it helps, take m 160 grams. %3D %3D %3D %3D m Vo L The steps to follow: (1) find the initial KE of the puck; (2) find the work done by the friction force (should be negative); (3) find the final kinetic energy as KE; = KE; + W, meaning that some of the initial kinetic energy is lost due to the work done by friction; (4) from the final KE find the final speed. The final speed of the puck, Vf =7.28 X Units m/s %3D If the initial speed of the puck is not high enough the puck will get stuck in the rough area. At what minimal initial speed should the puck move to barely make it through the rough area? The minimal initial velocity, Vmin =…arrow_forwardAt Ted's request, Bill pushes the pizza box across the granite countertop towards Ted. When the box leaves Bill's hand it is sliding at 2.60 m/s. The box comes to rest over a distance of 110 cm. What is the coefficient of kinetic friction, uk, between the pizza box and the countertop? (Ignore air drag.)arrow_forward