You are given an array A[1, ., n] in which the elements A[2] to A[n] are already sorted, i.e., A[2, .., n] is a sorted array. Write down an efficient algorithm with proper pseudocode for moving A[1] in the correct place, so that the full array A[1, .. n] is sorted.

D3 no. D4.  Coding. The

9.). integer array nums and an integer k, return the length of the shortest non-empty subarray of nums with a sum of at least k. If there is no such subarray, return -1. A subarray is a contiguous part of an array.   Example 1: Input: nums = [1], k = 1 Output: 1 Example 2: Input: nums = [1,2], k = 4 Output: -1 Example 3: Input: nums = [2,-1,2], k = 3 Output: 3.

You're given an array arr. Apply the following algorithm to it:   find intervals of consecutive prime numbers and consecutive non-prime numbers; replace each such interval with the sum of numbers in it; if the resulting array is different from the initial one, return to step 1, otherwise return the result. Input A non-empty integer array such that:   -10000 ≤ arr[i] ≤ 10000 1 ≤ arr.length ≤ 1000 Output An integer array.   Examples For arr = [1, 2, 3, 5, 6, 4, 2, 3] the result should be [21, 5]:   [1, 2, 3, 5, 6, 4, 2, 3] --> [(1), (2 + 3 + 5), (6 + 4), (2 + 3)] --> [1, 10, 10, 5] [1, 10, 10, 5] --> [(1 + 10 + 10), (5)] --> [21, 5] For arr = [-3, 4, 5, 2, 0, -10] the result should be [1, 7, -10]:   [-3, 4, 5, 2, 0, -10] --> [(-3 + 4), (5 + 2), (0 + -10)] --> [1, 7, -10] Solve it in C# please

Java

Select the for-loop which iterates through all even index values of an array.A. for(int idx = 0; idx < length; idx++)B. for(int idx = 0; idx < length; idx%2)C. for(int idx = 0; idx < length; idx+2)D. for(int idx = 0; idx < length; idx=idx+2)

Consider sorting n numbers stored in array A[1:n] by first finding the smallestelement of A[1:n] and exchanging it with the element in A[1]. Then find thesmallest element of A[2:n], and exchange it with A[2]. Then find the smallestelement of A[3:n], and exchange it with A[3]. Continue in this manner for thefirst n-1 elements of A. Write pseudocode for this algorithm, which is knownas selection sort. What loop invariant does this algorithm maintain? Why does itneed to run for only the first n-1 elements, rather than for all n elements? Give theworst-case running time of selection sort in big theta notation. Is the best-case runningtime any better?

Given a sorted array arr[] of distinct integers. Sort the array into a wave-like array and return it In other words, arrange the elements into a sequence such that arr[1] >= arr[2] = arr[4] <= arr[5].. Example 1: Input: n = 5 arr[] {1,2,3,4,5} Output: 2 1 4 3 5 Explanation: Array elements after sorting it in wave form are 2 1 4 3 5.

it's not a programming question.

PYTHON: Please provide a screenshot of your code in Python. Thank you!