You are given a result of the gradation test of aggregate, calculate and plot the gradation curve on the given semilog graph shee Result Sieve analysis AggregatesFine AggregatesTotal weight =200gWeightretainedSieve size(mm)(g)52.36311.18420.6400.3480.1533Pan6Coarse AggregatesTotal weight =2000gMassSieve sizeretained(mm)(g)37.51469720250104135428Pan212 GRADATION FOR COARSE AGGREGATE 20mm100908070605040302010110100sieve sizeGRADATION FOR FINE AGGREGATE1009080706050403020100.010.110100sieve sizeCumulative Peroent Passing (%)Cumulative Percent Passing (%)

Weight % weight cumulative % cumu % sieve size retained retained retained passing 5 0 0…

Answered: You are given a result of the gradation…

You are given a result of the gradation test of aggregate, calculate and plot the gradation curve on the given semilog graph shee

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: Coarse aggregate placed igid buc its unit weight. The following data were obtained: Volume of bucket…

A: According to given data Coarse aggregate is placed in a rigid bucket (mold) and rodded with a…

Q: Laboratory specific gravity and absorption tests are run on two coarse aggregate sizes, which have…

A: awe know that Specific gravity of mixure isGmix=WA+WBWAGA+WBGBWA=40% and WB=60%

Q: Complete the table and show complete computations. Draw the aggregate gradation chart. Calculate the…

A: Solution: Sieve Size Sieve Size mm Amount Retained g, a Cumulative Amount Retained g, b Amount…

Q: Sieve analysis test for fine aggregates was performed on a sample of fine aggregates and produced…

Q: While measuring the abrasion value of sub-base aggregates category E sample was taken having dry…

A: Abrasion value is given by: AV=W2W1×100 Where, W2 = Weight of aggregate passing 1.7 mm sieve W1 =…

Q: Aggregates from three sources having the properties shown in the table below where blended at a…

A: To find -The properties of aggregate blend Explanation :

Q: From a Coarse Aggregate sample, the ff data are given below to determine the sample's specific…

A: Given data, Oven dry mass A = 3625.5 g SSD mass B = 3650.3 g Mass under water C = 2293.0 g

Q: is the grade size used to identified the practical grading of the aggregate O 4.75 mm O 600 micron O…

Q: TEST PROCEDURE: 1. Dry the aggregate test sample to a constant weight at a temperature of 110 ±…

A: Note: Hi! Thank you for the question, As per the honour code, we are allowed to answer three…

Q: the Nominal Maximum aggregate Size (N.M.S) for the aggregate gradation shown below is equal to *…

A: Given- To find- Nominal Maximum Aggregate Size.

Q: Calculate the percent voids between aggregate particles that have been com-pacted by rodding, if the…

A: Given: Dry unit weight yd = 1161 kg/m3 Specific gravity G = 2.639 To find: Percentage voids e = ?…

Q: Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit…

A: Given: Volume of bucket, V = 1/3 ft3 Weight of empty bucket, W1 = 18.5 lb Weight of bucket filled…

Q: 46.5 kg (102.3 lb) of fine aggregate is mixed with 72.3 kg (159.1 lb) of coarse aggregate. The fine…

A: The given data is shown below:

Q: 1. In the bulk unit weight experiment why should the aggregate be placed in layers and then rodded…

A: 1)Bulk unit weight : While doing Experiment the aggregates are filled in layers and compacted for…

Q: The mass of aggregate B has been reduced and weighed to conduct an aggregate test shown in Table 2.…

A: Solution: Given: Mass of Aggregate: 500.8g SSD Mass of Aggregate: 500.2g Mass of pycnometer with…

Q: Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit…

A: Given that, The volume of rigid bucket= 0.2 ft3 Weight of empty bucket= 18.2 lb Weight of…

Q: . For an aggregate sample, if you know that the apparent relative density is 2.72 and the water…

A: The apparent relative density is 2.72. Water absorption is w=1.2%. The dry mass of aggregates is…

Q: the nominal Maximum aggregate Size for the aggregate gradation shown below is equal to Sieve size…

A: Maximum Aggregate Size: Maximum Aggregate Size is the smallest size size which requires 100%…

Q: Sieve analysis test for fine aggregates was performed on a sample of fine aggregates and produced…

A: Given, Sieve analysis data

Q: The percentage of aggregates of fine-ness modulus 2.7 is to be mixed with coarse aggregate of…

A: Given data: The percentage of aggregates of fine-ness modulus (FM) = 2.7 be x It is to be mixed with…

Q: What are the main purposes of Sieve Analysis of aggregates?

A: purpose of sieve analysis Main purpose of sieve analysis is to determine the distribution of…

Q: Calculate the bulk specific gravity of combined aggregate if you know the specific gravities of…

Q: Sieve analysis test for fine aggregates was performed on a sample of fine aggregates and produced…

A: Given, Sieve analysis diagram

Q: The mass of aggregate B has been reduced and weighed to conduct an aggregate test shown in Table 2.…

Q: What should be the observation and analysis for sieve analysis of fine aggregate if the value of…

A: Fineness Modulus 3.7 Cu= 4.1 Cc= 1.1 % error = 1.8% Cu= 4.1 between 4-6 Hence well graded sand Cc=…

Q: Thoroughly mix the aggregate sample and reduce it to an amount suitable for testing, using a sample…

A: Sample Splitters: Sample splitters work by reducing the sample size by leading the flow of the…

Q: choose true or false If you know that weights of coarse aggregate as follow :Weight of aggregate…

A: Given data : A= Weight of aggregate stock = 5350 gm, B= weight of aggregate in oven dry= 5200 gm, C=…

Q: The following table shows the results obtained from laboratory tests done on samples of aggregates.…

A: Answer We are given Bulk specific gravity of SSD = 2.67 Weight of aggregates+metal container ( Wam…

Q: From a Fine Aggregate sample, the ff data are given below to determine only the SPECIFIC GRAVITIES…

A: Given data MASS of oven dried aggregate (W1)=428.3g MASS of PYC filled with water (W2)=652.5g MASS…

Q: The wet mass of an aggregate sample is 583g and its dry mass is 575g. The test shows the absorption…

A: Finding out the type of moisture condition.

Q: the Nominal Maximum aggregate Size (N.M.S) for the aggregate gradation shown below is equal to…

A: Nominal maximum size of aggregate corresponds to a sieve which is the second largest and do not…

Q: Laboratory specific gravity and absorption tests are run on two coarse aggregate sizes, which have…

A: Given data:Bulk specific gravity of aggregate A (GA) = 2.491 Bulk specific gravity of aggregate B…

Q: if my Fineness modulus for fine aggregates is 1.88, does it meet the standards fineness modulus for…

A: Fineness modulus is defined as summation of aggregate of cumulative percentage of particles retained…

Q: Laboratory specific gravity and absorption tests are run on two coarse aggregate sizes, which have…

Q: plot the gradations of aggregate A, aggregate B, the se cification limits.

Q: Sieve analysis for fine and coarse aggregate is done, how can we say that those samples are good and…

A: The fineness modulus is the total of the cumulative percentage that stayed on the each sieve from…

Q: Aggregates 1 Aggregates Aggregates 3 Properties Coarse aggregate Angularity, percent crushed faces…

Q: The mass of a bulk density bucket is measured as 2115 g when it is empty. The mass of the bucket…

A: Given, Mass of empty bulk density bucket (M1) = 2115 g Mass of bucket filled with water(M2) = 5148…

Q: Complete the table and show complete computations. Draw the aggregate gradation chart. Calculate the…

A: Introduction: The fineness modulus of fine aggregate is an index number which represents the mean…

Q: Distinguish porosity from voids content for aggregate with the help of schematic diagrams.

Q: Laboratory specific gravity and absorption tests are run on two coarse aggregate sizes, which have…

Q: You have data on an aggregate source. The OD specific gravity is 2.37 and the SSD specific gravity…

A: Given data- OD specific gravity = 2.37 SSD specific gravity = 2.44 To Find- Apparent Specific…

Q: Calculate the dry rodded unit weight (density), apparent specific gravity, bulk specific gravity…

Q: 2 Compare the advantages and disadvantages of fine and coarse aggregates.

Q: From the given data shown in the table below, determine the effective specific gravity of…

Q: According to fuller equation, to draw the maximum density line for aggregate gradation shown below,…

Q: (b) Answer the following situations: i. ii. Explain why smaller siz is usually used for high…

A: To find: Effect of size of aggregates on strength of concrete

Q: Calculate the percent voids between aggregate particles that have been compacted by rodding, if the…

A: Percentage of voids is the volume of voids occupied by either air or water or combinedly both in the…

Concept explainers

Unit Conversion

Standard units are also called SI units. SI units are used for measuring a physical quantity satisfying certain conditions. There are two types of units: fundamental units and derived units. Fundamental units are physical quantities that are independent, that is, they do not depend on other quantities like mass, length, or time. There are plenty of quantities in our lives which need to be measured and compared. Measuring is the comparison of a particular physical quantity with its reference value. A unit is a measure of a fixed physical quantity. A physical quantity is the product of a unit and the numerical value we need to compare with.

Question

You are given a result of the gradation test of aggregate, calculate and plot the gradation curve on the given semilog graph shee

Result Sieve analysis Aggregates
Fine Aggregates
Total weight =
200g
Weight
retained
Sieve size
(mm)
(g)
5
2.36
31
1.18
42
0.6
40
0.3
48
0.15
33
Pan
6
Coarse Aggregates
Total weight =
2000g
Mass
Sieve size
retained
(mm)
(g)
37.5
14
697
20
250
10
413
5
428
Pan
212

GRADATION FOR COARSE AGGREGATE 20mm
100
90
80
70
60
50
40
30
20
10
1
10
100
sieve size
GRADATION FOR FINE AGGREGATE
100
90
80
70
60
50
40
30
20
10
0.01
0.1
10
100
sieve size
Cumulative Peroent Passing (%)
Cumulative Percent Passing (%)

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

Step 2

Step 3

Step 4

Trending now

This is a popular solution!

Step by step

Solved in 4 steps with 2 images

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

(C).Workout flakiness & elongation index from the following Flakiness Index Weights of aggregates passing through corresponding slot=w2=200 grams Weight of aggregates retained on a particular sieve =w1=700 grams Workout flakiness index? Elongation Index Weights of aggregates Retained on gauge length =w2=190 grams Weight of aggregates retained on a particular sieve =w1=540 grams Workout elongation index? Are these flakiness & elongation index within permissible range? Also mention bad effects of greater amount of flaky & elongated particles.
The sieve analysis results for fine aggregate (1000 g) are shown below, complete the following table and calculate the fineness modulus (F.M.): Sieve Size Weight Retained Individual Retained Cumulative Passing Cumulative Retained (mm) (g) (%) (%) (%) 9.5 4.75 15 2.36 100 1.18 250 0.6 0.3 200 0.15 100 0.075 Pan 4 Total 1000
A sample of a dry course-grained material of 500 grams was shaken through a nest of sieves and the following results are obtained: Sieve No. Opening (mm) 4.75 Mas Retained (grams) 0.0 14.8 4 10 2.00 20 0.85 98.0 40 0.425 90.1 100 0.15 181.9 200 0.075 108.8 Pan 6.4 1. Determine the effective size (mm). 2. Determine the uniformity coefficient. 3. Determine the coefficient of curvature.
Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained:Volume of bucket = 14 LWeight of empty bucket = 9.21 kgWeight of bucket filled with dry rodded coarse aggregate:Trial 1 = 34.75 kgTrial 2 = 34.06 kgMeasureSampleA B CWet Mass (g) 521.0 522.4 523.4Dry Mass (g) 491.6 491.7 492.1Absorption (%) 2.5 2.4 2.3Table P 5 . 9 determine the amount of water required to increase the moisture content of aggregate to reach absorption?5.9 Three samples of fine aggregate have the properties shown in Table Trial 3 = 35.74 kga. Calculate the average dry-rodded unit weightb. If the bulk dry specific gravity of the aggregate is 2.620, calculate thepercent voids between aggregate particles for each trial.
Q5/ Find job mix formula by using mathematical method. Aggregate Specification Sieve Size A B Limits 25 mm 100 100 100 100 12.5 mm 100 100 97 90-100 4.75 mm 100 100 55 60-90 1.18 mm 98 79 38 28-58 0.3 mm 98 39 28 6-38 0.15 mm 11 16.5 7 10-23 0.075 mm 4.1 8 2.15 4-10
A sieve analysis test was performed on a sample of fine aggregate and produced the following results:Sieve, mm 4.75 2.36 2.00 1.18 0.60 0.30 0.15 0.075 panAmount retained, g 0 33.2 56.9 83.1 151.4 40.4 72.0 58.3 15.6Calculate the percent passing each sieve, and draw a 0.45 power gradation chart with the use of a spreadsheet program. The specific steps or functions selected in the following description can vary somewhat depending on the version of the spreadsheet program being used.
Q5/ Find job mix formula by using mathematical method. Aggregate Specification Sieve Size A B C Limits 25 mm 100 100 100 100 12.5 mm 100 100 97 90-100 4.75 mm 100 100 55 60-90 1.18 mm 98 79 38 28-58 0.3 mm 98 39 28 6-38 0.15 mm 11 16.5 7 10-23 0.075 mm 4.1 8 2.15 4-10
Q1: C: A sieve analysis test was performed on a sample of aggregate and produced the results shown in the Table below, Calculate the percent passing through each sieve. Plot the percent passing versus sieve size. Sieve size, mm Amount Retained, g 25 19 376.7 12.5 888.4 9.5 506.2 4.75 1038.4 2.35 900.1 1.18 891.5 0.6 712.6 0.3 625.2 0.15 581.5 0.075 242.9 Pan 44.9
The sieve analysis results for fine aggregate (1000 g) are shown below, complete the following table and calculate the fineness modulus (F.M.): Weight Retained Cumulative Passing Cumulative Retained Sieve Size Individual Retained (mm) (g) (%) (%) (%) 9.5 4.75 15 2.36 100 1.18 250 0.6 0.3 200 0.15 100 0.075 2. Pan 4 Total 1000
A sieve analysis was conducted on a graded aggregate with a nominal maximum aggregate size of 20 mm. Th following data was obtained: Sieve size (mm) Mass retained (g) 37.5 0 26.5 19.0 9.5 4.75 2.36 Pan 80 120 800 1450 130 80 a) Find the mass passing and percentage passing on each sieve and fill in the table provided in the answer sheet. b) Fill in the upper and lower limits of the Australian Standard (AS2758) for this aggregate type. c) As per the AS2758, is the aggregate well-graded? Explain your answer. d) What should be done if the aggregate is poorly graded?
if total sample mass of aggregate is 164.9 grams, then the percent passing from sieve size #30 only is equal to ………………
"A sieve analysis test was performed on a sample of fine aggregate and produced the following results:Sieve, mm 4.75 2.36 2.00 1.18 0.60 0.30 0.15 0.075 pan.Amount retained, g 0 33.2 56.9 83.1 151.4 40.4 72.0 58.3 15.6 .Calculate the percent passing each sieve, and draw a 0.45 power gradation chart with the use of a spreadsheet program. The specific steps or functions selected in the following description can vary somewhat depending on the version of the spreadsheet program being used.Calculate the fineness modulus of the sieve analysis results of Sample Problem