You are asked to prove that 12 + 22 + 32 +...+n? n(n+1)(2n+1) using the Principle of Mathematical Induction. What is the correct basis step? 1(1+1)(2-1+1) O 12 = 1 = 123 || 6. O 12 + 22 = 1 + 4 = 5 = 2-3-5 6 2(2+1)(2-2+1) 6. O 12 + 22 + 3? +...+ k² = k(k+1)(2k+1) O 12 + 22 + 3² = 1+4+9 = 14 = 3(3+1)(2-3+1) 3-4-7 |3D 6 6.
You are asked to prove that 12 + 22 + 32 +...+n? n(n+1)(2n+1) using the Principle of Mathematical Induction. What is the correct basis step? 1(1+1)(2-1+1) O 12 = 1 = 123 || 6. O 12 + 22 = 1 + 4 = 5 = 2-3-5 6 2(2+1)(2-2+1) 6. O 12 + 22 + 3? +...+ k² = k(k+1)(2k+1) O 12 + 22 + 3² = 1+4+9 = 14 = 3(3+1)(2-3+1) 3-4-7 |3D 6 6.
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
ChapterP: Preliminary Concepts
SectionP.CT: Test
Problem 1CT
Related questions
Question
![You are asked to prove that
12 + 22 + 32 +...+ n²
n(n+1)(2n+1)
6
using the Principle of Mathematical Induction. What is the correct basis step?
O 12 = 1 = 123
1(1+1)(2-1+1)
%3D
6.
2(2+1)(2-2+1)
O 12 + 22 = 1 +4 = 5 =
2-3-5
6.
O 12 + 22 + 3² +...+ k²
k(k+1)(2k+1)
%3D
6.
3(3+1)(2-3+1)
O 12 + 22 + 3² = 1+4+9 = 14 = 3:4:7
6
%3D
6](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F20d67e85-f281-4591-961d-b8ab5ff59b24%2F2894ca9c-6fb8-424c-938f-c6a158f77ba3%2F83qjl96_processed.jpeg&w=3840&q=75)
Transcribed Image Text:You are asked to prove that
12 + 22 + 32 +...+ n²
n(n+1)(2n+1)
6
using the Principle of Mathematical Induction. What is the correct basis step?
O 12 = 1 = 123
1(1+1)(2-1+1)
%3D
6.
2(2+1)(2-2+1)
O 12 + 22 = 1 +4 = 5 =
2-3-5
6.
O 12 + 22 + 3² +...+ k²
k(k+1)(2k+1)
%3D
6.
3(3+1)(2-3+1)
O 12 + 22 + 3² = 1+4+9 = 14 = 3:4:7
6
%3D
6
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