You are a genetic counselor and a couple has come to you for advice. They have a family history of cancer and are concerned that their unborn third child will also get cancer. They provide you with the following pedigrees for two different traits relating to defects in the enzymes separase and topoisomerase: A.O Separase 8.O Topoisomerase defect defect 10 5 6 (7) 10 1112 11 12 13 15 15 These two pedigrees represent the same family. Genetic testing shows that individual 4 has only nonmutant alleles of both genes and individual 12 has only mutant alleles of both genes. Individuals 6, 8, 9, 12, and 14 have cancer. The couple just recently learned that their daughter (individual 14) has cancer and has both mutations. In this lab activity, you will use Punnett squares to determine the probability that the couple's third unborn child will also inherit both mutations and be at risk for developing cancer. .Using Punnett squares, determine the phenotypes of offspring that the following parents could produce. For some situations, there could be more than one genotype for at least one of the parents. In these cases, be sure to include Punnett squares for all possibilities, and give the probablilty that their third unborn child may be at risk for developing cancer. 1. An autosomal recessive trait with an unaffected mother and an affected father. 2. An autosomal dominant trait with an affected mother and an unaffected father. 3. An X-linked recessive trait with an unaffected mother and an affected father. 4. An X-linked dominant trait with an unaffected mother and an affected father.

Human Heredity: Principles and Issues (MindTap Course List)
11th Edition
ISBN:9781305251052
Author:Michael Cummings
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Chapter16: Reproductive Technology, Genetic Testing, And Gene Therapy
Section: Chapter Questions
Problem 17QP: You are a genetic counselor, and your patient has asked to be tested to determine if she carries a...
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You are a genetic counselor and a couple has come to you for advice. They have a family history of
cancer and are concerned that their unborn third child will also get cancer. They provide you with
the following pedigrees for two different traits relating to defects in the enzymes separase and
topoisomerase:
А.
Separase
defect
В.
Topoisomerase
defect
2
3
4
1
3
4
7
8
9.
10
5
6.
7
8
9.
10
11
12
13
11
12
13
14
15
14
15
These two pedigrees represent the same family. Genetic testing shows that individual 4 has only
nonmutant alleles of both genes and individual 12 has only mutant alleles of both genes. Individuals
6, 8, 9, 12, and 14 have cancer. The couple just recently learned that their daughter (individual 14)
has cancer and has both mutations. In this lab activity, you will use Punnett squares to determine
the probability that the couple's third unborn child will also inherit both mutations and be at risk
for developing cancer.
.Using Punnett squares, determine the phenotypes of offspring that the following parents could
produce. For some situations, there could be more than one genotype for at least one of the parents.
In these cases, be sure to include Punnett squares for all possibilities, and give the probablilty that
their third unborn child may be at risk for developing cancer.
1. An autosomal recessive trait with an unaffected mother and an affected father.
2. An autosomal dominant trait with an affected mother and an unaffected father.
3. An X-linked recessive trait with an unaffected mother and an affected father.
4. An X-linked dominant trait with an unaffected mother and an affected father.
Transcribed Image Text:You are a genetic counselor and a couple has come to you for advice. They have a family history of cancer and are concerned that their unborn third child will also get cancer. They provide you with the following pedigrees for two different traits relating to defects in the enzymes separase and topoisomerase: А. Separase defect В. Topoisomerase defect 2 3 4 1 3 4 7 8 9. 10 5 6. 7 8 9. 10 11 12 13 11 12 13 14 15 14 15 These two pedigrees represent the same family. Genetic testing shows that individual 4 has only nonmutant alleles of both genes and individual 12 has only mutant alleles of both genes. Individuals 6, 8, 9, 12, and 14 have cancer. The couple just recently learned that their daughter (individual 14) has cancer and has both mutations. In this lab activity, you will use Punnett squares to determine the probability that the couple's third unborn child will also inherit both mutations and be at risk for developing cancer. .Using Punnett squares, determine the phenotypes of offspring that the following parents could produce. For some situations, there could be more than one genotype for at least one of the parents. In these cases, be sure to include Punnett squares for all possibilities, and give the probablilty that their third unborn child may be at risk for developing cancer. 1. An autosomal recessive trait with an unaffected mother and an affected father. 2. An autosomal dominant trait with an affected mother and an unaffected father. 3. An X-linked recessive trait with an unaffected mother and an affected father. 4. An X-linked dominant trait with an unaffected mother and an affected father.
Expert Solution
Step 1

An autosomal recessive inheritance is a type of inheritance in which the mutation occurs on one of the autosomes and is expressed only in homozygous condition that is mutation is expressed only when it occurs in two alleles of the gene.

An autosomal dominant inheritance is a type of inheritance that occurrs in oneof the alleles in autosomes that is mutation in only one allele is required to cause the disease.

X linked recessive inheritance occurs when mutation is on X chromosome. Males are usually affected by this type of condition because they have single X chromosome. Females are affected only when mutation is present on both the X chromosomes. 

X linked dominant inheritance occurs when mutation may occur on one of the X chromosome. This may occur in the females also.

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