## Item 18**Scenario:**You apply a force of magnitude \( F_1 \) to one end of a wire and another force \( F_1 \) in the opposite direction to the other end of the wire. The cross-sectional area of the wire is \( 8.00 \, \text{mm}^2 \). You measure the fractional change in the length of the wire, \( \Delta l / l_0 \), for several values of \( F_1 \). When you plot your data with \( \Delta l / l_0 \) (in units of N) on the vertical axis and \( F_1 \) (in units of N) on the horizontal axis, the data lie close to a line that has a slope \( 8.0 \times 10^{-7} \, \text{N}^{-1} \).### Part A**Question:**What is the value of Young's modulus for this wire?**Instructions:**Express your answer with the appropriate units.### Input Field- **Value:** Text box to enter the numerical value of Young's modulus.- **Units:** Drop-down menu to select the appropriate units.### Submit Button:- **Submit:** Button to submit the answer.- **Request Answer:** Button to request the correct answer if unsure.### Additional Options:There are various tools and icons designed to help the user format their answer, including equation editors and help functions.### Feedback:A link to provide feedback on the problem is available at the bottom of the interface.**Graphical Interpretation:**- The question implies a linear relationship between \( \Delta l / l_0 \) and \( F_1 \), with the given slope \( 8.0 \times 10^{-7} \, \text{N}^{-1} \).### Calculation Tip:To find Young's modulus (\( Y \)), use the formula:\[ Y = \frac{F/A}{\Delta l / l_0} \]Given the problem's slope as \( 8.0 \times 10^{-7} \, \text{N}^{-1} \) and the cross-sectional area \( A = 8.00 \, \text{mm}^2 \).Ensure proper conversion of units as needed and input the value accordingly in the fields provided.

Newton's second law of motion relates the net force acting on the object to the acceleration…

You apply a force of magnitude F1 to one end of a wire and another force F in the opposite direction to the other end of the wire. The cross-sectional area of the wire is 8.00 mm2. You measure the fractional change in the length of the wire, Al/lo. for several values of F. When you plot your data with Al/lo on the vertical axis and F (in units of N) on the horizontal axis, the Part A What is the value of Young's modulus for this wire? data lie close to a line that has slope 8.0 x 10-7N-1 Express your answer with the appropriate units. Y = Value Units Submit Request Answer

You apply a force of magnitude F1 to one end of a wire and another force F in the opposite direction to the other end of the wire. The cross-sectional area of the wire is 8.00 mm2. You measure the fractional change in the length of the wire, Al/lo. for several values of F. When you plot your data with Al/lo on the vertical axis and F (in units of N) on the horizontal axis, the Part A What is the value of Young's modulus for this wire? data lie close to a line that has slope 8.0 x 10-7N-1 Express your answer with the appropriate units. Y = Value Units Submit Request Answer

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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