Structural Analysis
6th Edition
ISBN: 9781337630931
Author: KASSIMALI, Aslam.
Publisher: Cengage,
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- The two vertical steel [E = 200 GPa] rods that support rigid bar ABCD are initially free of stress. Rod (1) has an area of A₁ = 350 mm² and a length of L₁ = 2.1 m. Rod (2) has an area of A₂ = 375 mm² and a length of L₂ = 1.5 m. Assume dimensions of a = 3.2 m, b = 1.1 m, and c = 1.4 m. After a load of P = 130 kN is applied to the rigid bar at D, determine: (a) the normal stresses in rods (1) and (2) (b) the magnitude of the downward deflection of the rigid bar at D. y,v (2) a L2 Rigid bar L₁ Answer: (a) σ₁ = i 02= i (b) VD= i (1) B MPa MPa mm -X,U b C ↓ С D Parrow_forwardCalculate the forces in members AC, AD, and DE for the loaded truss. Restraining link BC is horizontal. Forces are positive if in tension, negative if in compression. B Answer: AC = 3' AD = i i DE = i C 3' 600 lb D 3' E lb lb lbarrow_forward1arrow_forward
- The truss structure shown below is subjected to the following loads F1= 437 lb F2= 726 lb and has the following geometry: w = 10 ft F2 F1 F1 W W -B D G. F -AC E Determine the support reactions at A and E. Determine the forces in members BC, CG, and FG and state whether they are in tension or compression. Determine the forces in members ED and EF and state whether they are in tension or compression.arrow_forwardPlease help on the 3 questions in the photoarrow_forwardI tried to solve the first problem by cutting a section at s and then taking the sum of moments with respect to point H (HJ, HI, DJ are now not relevant) which looks like it yields compression which seems right but I keep on getting the wrong answerarrow_forward
- Problem 2: Determine the force in ALL the members of the truss. State if the members are in tension or compression. Show all your work to receive full credit. (Hint: It is not needed to find the reaction forces at C and E if you use the Method of Joints). Note: P1= 1000 lb and P: = 500 lb B C30 45 999 4 ft E 550 D. -4 ft- - 4 ft- 999 299arrow_forwardPlease show complete solution. Thank you!arrow_forward
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