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a. A dental x-ray machine has a 60 kV accelerating voltage and a tungsten target. A
typical exposure uses an 8.0 mA electron current for 18 s. What is the approximate
power of the x-ray emission? The conversion efficiency is not known precisely, so a
one-significant-figure answer is appropriate.


b. What is the x-ray intensity at the jaw, 15 cm from the source? Assume that the x rays
are emitted uniformly in all directions from a single point.

c. A molar tooth can be approximated as a 9-mm-diameter, 20-mm-long cylinder. X rays
impinge on a molar from the side, perpendicular to the axis of the cylinder. Approxi-
mately what x-ray energy enters a molar during the exposure?

4. X rays are generated by accelerating electrons through a large potential difference AV and
allowing them to strike a metal target. Most of the electron energy is dissipated as heat,
but the interaction of the high-speed electrons with the target atoms transforms some of the
energy into x rays. The efficiency of the conversion is approximately (Z x 10-9 V-¹)AV,
where Z is the atomic number of the target.
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Transcribed Image Text:4. X rays are generated by accelerating electrons through a large potential difference AV and allowing them to strike a metal target. Most of the electron energy is dissipated as heat, but the interaction of the high-speed electrons with the target atoms transforms some of the energy into x rays. The efficiency of the conversion is approximately (Z x 10-9 V-¹)AV, where Z is the atomic number of the target.
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Given:targetusedistungsten,henceitsatomicnumber,Z=74thepotentialdifference,ΔV=60kV=60×103Vexposurecurrent,I=8.0mA=8×103Aexposuretime,te=18sdistancebetweenthesourceandjaw,r=15cm=0.15massumedthatsourceisapointsource.dimensionofthemolartooth,modelledasacylinder,lengthofthecylinder,L​ =20mm=20×103mdiameterofthecylinder,D=9×103mAsked:a.PowerofXrayemmission,Pe=?b.Intensityoftheradiationsatthejaw,I=?c.Amountofenergythatentersthemolartoothduringtheexposuretime,E=?

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