Writen in Java. Please give a step by step explanation of the ouput for the following code. public class TestTwo { public static void main(String[] args) { int[] list = {1,2,3,4,5,6}; for(int i = 1; i < list.length; i++) { list[i] = list[i - 1] * 2; } for(int i = 0; i < list.length; i++) { System.out.print(list[i] + " "); } } }

Writen in Java. Please give a step by step explanation of the ouput for the following code. public class TestTwo { public static void main(String[] args) { int[] list = {1,2,3,4,5,6}; for(int i = 1; i < list.length; i++) { list[i] = list[i - 1] * 2; } for(int i = 0; i < list.length; i++) { System.out.print(list[i] + " "); } } }

C++ Programming: From Problem Analysis to Program Design

8th Edition

ISBN:9781337102087

Author:D. S. Malik

Publisher:D. S. Malik

Chapter18: Stacks And Queues

Section: Chapter Questions

Problem 16PE: The implementation of a queue in an array, as given in this chapter, uses the variable count to...

See similar textbooks

Similar questions

;import java.util.Scanner } public class Task1 ;static Scanner cin=new Scanner(System.in) ;int n } ;System.out.printlIn("Enter n : ") :On=cin.nextInt { ;int list]=new int[n] }0void readData }for(int i=0;i
import java.util.*; public class Main{ public static void main(String[] args) { Main m = new Main(); m.go(); } private void go() { List<Stadium> parks = new ArrayList<Stadium>(); parks.add(new Stadium("PNC Park", "Pittsburgh", 38362, true)); parks.add(new Stadium("Dodgers Stadium", "Los Angeles", 56000, true)); parks.add(new Stadium("Citizens Bank Park", "Philadelphia", 43035, false)); parks.add(new Stadium("Coors Field", "Denver", 50398, true)); parks.add(new Stadium("Yankee Stadium", "New York", 54251, false)); parks.add(new Stadium("AT&T Park", "San Francisco", 41915, true)); parks.add(new Stadium("Citi Field", "New York", 41922, false)); parks.add(new Stadium("Angels Stadium", "Los Angeles", 45050, true)); Collections.sort(parks, Stadium.ByKidZoneCityName.getInstance()); for (Stadium s : parks) System.out.println(s); }}…
Main.java 1 class DictionaryEntry 2 - { 3 4 5 6 7 8 9- 10 11 12 13 14 15 String word; String definition; Dictionary Entry(String w, String def) {this word=new String (w); // Clone the strings this definition = new String(def); } class TestMyDictionary public static void main(String[] args) { } DictionaryEntry [] Dico = new DictionaryEntry [10]; Dico [0]=new Dictionary Entry("Java" "A modern object-oriented Type here to search programming language"); Dico [1]=new DictionaryEntry ("C++" "An effective object oriented programming language"); Dico [2] = new DictionaryEntry("FORTRAN, "FORTRAN stands for FORmula TRANSIation. Often used for simulation."); O JL I S Et Run O $ Output
main.cpp:4:17: error: 'string' has not been declared 4 | void KMPSearch(string pat, string txt) main.cpp:4:29: error: string' has not been declared 4 | void KMPSearch(string pat, string txt) Aununun main.cpp:31:25: error: string' has not been declared 31 | void computelPSArray(string pat, int M, int[] lps) main.cpp:31:50: error: expected or . before lps' 31 | void computeLlPSArray(string pat, int M, int[] lps) main.cpp:55:8: error: expected :' before 'static' 55 | public static void Main() main.cpp:61:2: error: expected ;' after class definition 61 | } | main.cpp: In member function 'void GFG::KMPSearch(int, int)': main.cpp:6:15: error: request for member Length' in 'pat', which is of non-class type 'int' 6 | int M = pat.Length; main.cpp:7:15: error: request for member Length' in txt’, which is of non-class type 'int' int N = txt.Length; main.cpp:8:6: warning: structured bindings only available with -std3c++17' or (-std=gnu++17' 8 | int[] lps new int[M];
In Java what is stored in the array list after the following Java code executes? list[0] = 5; for (int i = 1; i < 6; i++) { list[i] = i * i + 5; if ( i > 2) list[i] = 2 * list[i] – list[i– 1]; }
In Java list all the values of the array after the function is called A. static void Fun(int[][]list){ int temp=list[1][2]; list[1][2]=list[0][2]; list[0][2]=temp; } public static void main(String[] args) { int [][]arr={{10,20,30},{100,200,300}}; Fun(arr); } 10,20,30,300 B. static void Fun(int[]list) { list[3]=5;} public static void main(String[] args) { int []arr={5,6,7,9}; Fun(arr); } C. static void Fun(int[][]list){ list[1][0]=0;} public static void main(String[] args) { int [][]arr={{-2,-3,-4},{5,6,7,9}}; Fun(arr); }
import java.util.* ; public class Averager {     public static void main(String[] args)     {     //a two dimensional array     int[][] a = {{5, 9, 3, 2, 14}, {77, 44, 22, 15, 99},                  {14, 2, 3, 9, 5}, {88, 15, 17, 121, 33}} ;     System.out.printf("Average = %.2f\n", average(a)) ;     System.out.println("EXPECTED:") ;     System.out.println("Average = 29.85") ;     System.out.printf("Average of evens = %.2f\n", averageEvens(a)) ;     System.out.println("EXPECTED:") ;     System.out.println("Average of evens = 26.57") ;     Random random = new Random(1) ;     a = new int[100][1] ;     for (int i = 0 ; i < 100 ; i++)         a[i][0] = random.nextInt(1000) ;     System.out.println("For an array of random values in range 0 to 999:") ;     System.out.printf("Average = %.2f\n", average(a)) ;     System.out.printf("Average of evens = %.2f\n", averageEvens(a)) ;     }     /**        Find the average of all elements of a two-dimensional array        @param aa the two…
public class ArrayMerge {     static void arrayMerge(int a[], int b[]){ int c[] = new int[50]; int k = 0;     for(int i = 0; i < a.length; i++) { c[k++] = a[i]; }     for(int i = 0; i < b.length; i++) { c[k++] = b[i]; }     for(int i = 0; i < k; i++) { System.out.println(c[i]); } }     public static void main(String[] args) { int a[] = { 18, 36, 41, 78, 56 }; int b[] = { 10, 37, 44 };     arrayMerge(a,b); }   } Calculate the algorithm step number and algorithm time complexity of the above program?
Java // Complete the missing code in the main function in the Main class below import java.util.ArrayList; import java.util.Iterator; import java.util.List; class Student  {     private int studentId;     private String studentName;     private String course;          public Student(int studentId, String studentName, String course) {         super();         this.studentId = studentId;         this.studentName = studentName;         this.course = course;     }     @Override     public String toString() {         return "Student Details:\n" + "studentId:"+studentId + "\nstudentName:" + studentName + "\ncourse:" + course;     }      } public class Main {     public static void main(String[] args) {                  List<Student> studentList =new ArrayList<>();                  studentList.add(new Student(1,"Alex","Java with DS"));         studentList.add(new Student(2,"Albert","Java with DS"));         studentList.add(new Student(3,"Samson","Spring Api"));…
import java.util.*;public class Print { public static void main(String args[]) { List<Integer> myList = Answer; myList.add(100); myList.add(new Integer(1)); myList.add(1); myList.add(new Integer(200)); myList.add(2); Answer{ System.out.println(i); } System.out.println("sorting..."); Answer; //sorts the elements for (Integer i: myList){ System.out.println(i); } }}
The implementation of a queue in an array, as given in this chapter, uses the variable count to determine whether the queue is empty or full. You can also use the variable count to return the number of elements in the queue. On the other hand, class linkedQueueType does not use such a variable to keep track of the number of elements in the queue. Redefine the class linkedQueueType by adding the variable count to keep track of the number of elements in the queue. Modify the definitions of the functions addQueue and deleteQueue as necessary. Add the function queueCount to return the number of elements in the queue. Also, write a program to test various operations of the class you defined.
import java.util.ArrayList;import java.util.Arrays;public class PS{/*** Write the method named mesh.** Start with two ArrayLists of String, A and B, each with* its elements in alphabetical order and without any duplicates.* Return a new list containing the first N elements from the two* lists. The result list should be in alphabetical order and without* duplicates. A and B will both have a size which is N or more.* Your solution should make a single pass over A and B, taking* advantage of the fact that they are in alphabetical order,* copying elements directly to the new list.** Remember, to see if one String is "greater than" or "less than"* another, you need to use the compareTo() method, not the < or >* operators.** Examples:* mesh(["a","c","z"], ["b","f","z"], 3) returns ["a","b","c"]* mesh(["a","c","z"], ["c","f","z"], 3) returns ["a","c","f"]* mesh(["f","g","z"], ["c","f","g"], 3) returns ["c","f","g"]** @param a an ArrayList of String in alphabetical order.* @param b an…