APPENDIXCTHERMODYNAMIC QUANTITIES TA390FOR SELECTED SUBSTANCESAT 298.15 K (25 °C)AH;(kj/mol)AGS°AG;(kj/mol)SubstanceAHi(kj/mol)(i/mol-K)Substance(kj/mol)(i/mol-K)AluminumC2H2(8)226.77209.2200.8Al(s)28.32C2H4(8)52.30To 68.11219.4AICI3(s)- 705.6-630.0109.3C2H6(8)-84.68-32.89229.5Al2O3(s)- 1669.8- 1576.551.00C3Hs(8)- 103.85-23.47269.9Barium- 15.71buborC4H10(8)- 124.73310.0Ba(s)0.0.C4H10(1) la0-147.6231.063.2BaCO3(s)-1216.3- 1137.6112.1C,H6(8)82.9129.7269.2BaO(s)-553.5-525.170.42C,H6(1)49.0124.5172.8BerylliumCH;OH(g)-201.2-161.9237.6Be(s)0.20CH3OH(!)-238.6- 166.23126.89.44BeO(s)-608.4C2H5OH(g) -235.1- 168.5282.7-579.113.77Be(OH)2(s)-905.8C2H5OH(I)-277.7- 174.76160.7-817.950.21C,H1206(s)- 1273.02-910.4212.1BromineCO()- 110.5 - 137.2197.9Br(g)111.882.38174.9CO2(8)-393.5-394.4213.6Br (aq)- 120.9- 102.880.71CH3COOH(I)-487.0-392.4159.8Br2(8)30.713.14245.3CesiumBr2(1)152.3HBr(g)-36.23Cs(g)76.5049.53175.6-53.22198.49Cs()082.09e 0.0392.07CalciumCs(s)85.15Ca(g)179.3145.58.801 154.8CSCI(s)-442.8101.2-414.4T18.Ca(s)41.4ChlorineCACO3(s, calcite)- 1207.1-1128.7692.88CaCl2(s)- 748.1Cl(g)121.7105.7 0.165.2-795.8GEFE 104.6CaF2(s)CI (aq)- 167.2- 131.256.5-1219.6- 1167.368.87Cl2(8)0.028EESCaO(s)-635.5-604.1739.75222.96Ca(OH)2(s)HCl(aq)- 167.2- 131.2-986.2-898.583.456.5HCI(g)-92.30-95.27CaSO4(s)-1434.0- 1321.8106.7186.69ChromiumCarbonCr(g)397.5352.6C(g)718.4672.9158.0174.2Cr(s)C(s, diamond)1.882.842.4323.6Cr2O3(s)- 1139.7- 1058.1C(s, graphite)5.6981.2CC4(8)-106.7-64.0309.4CobaltCCI,(1)- 139.3-68.6214.4Co(g)439393179CF4(8)-679.9-635.1262.3Co(s)28.4CH4(8)- 74.8-50.8186.3 Practice Exercise 2Write the equation corresponding to the standard enthalpy offormation of liquid carbon tetrachloride (CCI4) and look upAH for this compound in Appendix C.

The chemical reaction corresponding to formation of carbon tetrachloride is given as:C (s) + 2 Cl2…

Answered: Write the equation corresponding to the…

Write the equation corresponding to the standard enthalpy of formation of liquid carbon tetrachloride (CCI4) and look up AH for this compound in Appendix C.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Concept explainers

Thermochemistry

Thermochemistry can be considered as a branch of thermodynamics that deals with the connections between warmth, work, and various types of energy, formed because of different synthetic and actual cycles. Thermochemistry describes the energy changes that occur as a result of reactions or chemical changes in a substance.

Exergonic Reaction

The term exergonic is derived from the Greek word in which ‘ergon’ means work and exergonic means ‘work outside’. Exergonic reactions releases work energy. Exergonic reactions are different from exothermic reactions, the one that releases only heat energy during the course of the reaction. So, exothermic reaction is one type of exergonic reaction. Exergonic reaction releases work energy in different forms like heat, light or sound. For example, a glow stick releases light making that an exergonic reaction and not an exothermic reaction since no heat is released. Even endothermic reactions at very high temperature are exergonic.

Question

APPENDIX
C
THERMODYNAMIC QUANTITIES TA390
FOR SELECTED SUBSTANCES
AT 298.15 K (25 °C)
AH;
(kj/mol)
AG
S°
AG;
(kj/mol)
Substance
AHi
(kj/mol)
(i/mol-K)
Substance
(kj/mol)
(i/mol-K)
Aluminum
C2H2(8)
226.77
209.2
200.8
Al(s)
28.32
C2H4(8)
52.30
To 68.11
219.4
AICI3(s)
- 705.6
-630.0
109.3
C2H6(8)
-84.68
-32.89
229.5
Al2O3(s)
- 1669.8
- 1576.5
51.00
C3Hs(8)
- 103.85
-23.47
269.9
Barium
- 15.71
bubor
C4H10(8)
- 124.73
310.0
Ba(s)
0.
0.
C4H10(1) la0-147.6
231.0
63.2
BaCO3(s)
-1216.3
- 1137.6
112.1
C,H6(8)
82.9
129.7
269.2
BaO(s)
-553.5
-525.1
70.42
C,H6(1)
49.0
124.5
172.8
Beryllium
CH;OH(g)
-201.2
-161.9
237.6
Be(s)
0.20
CH3OH(!)
-238.6
- 166.23
126.8
9.44
BeO(s)
-608.4
C2H5OH(g) -235.1
- 168.5
282.7
-579.1
13.77
Be(OH)2(s)
-905.8
C2H5OH(I)
-277.7
- 174.76
160.7
-817.9
50.21
C,H1206(s)
- 1273.02
-910.4
212.1
Bromine
CO()
- 110.5 - 137.2
197.9
Br(g)
111.8
82.38
174.9
CO2(8)
-393.5
-394.4
213.6
Br (aq)
- 120.9
- 102.8
80.71
CH3COOH(I)
-487.0
-392.4
159.8
Br2(8)
30.71
3.14
245.3
Cesium
Br2(1)
152.3
HBr(g)
-36.23
Cs(g)
76.50
49.53
175.6
-53.22
198.49
Cs()
08
2.09
e 0.03
92.07
Calcium
Cs(s)
85.15
Ca(g)
179.3
145.5
8.801 154.8
CSCI(s)
-442.8
101.2
-414.4
T18.
Ca(s)
41.4
Chlorine
CACO3(s, calcite)
- 1207.1
-1128.76
92.88
CaCl2(s)
- 748.1
Cl(g)
121.7
105.7 0.
165.2
-795.8
GEFE 104.6
CaF2(s)
CI (aq)
- 167.2
- 131.2
56.5
-1219.6
- 1167.3
68.87
Cl2(8)
0.
02
8EES
CaO(s)
-635.5
-604.17
39.75
222.96
Ca(OH)2(s)
HCl(aq)
- 167.2
- 131.2
-986.2
-898.5
83.4
56.5
HCI(g)
-92.30
-95.27
CaSO4(s)
-1434.0
- 1321.8
106.7
186.69
Chromium
Carbon
Cr(g)
397.5
352.6
C(g)
718.4
672.9
158.0
174.2
Cr(s)
C(s, diamond)
1.88
2.84
2.43
23.6
Cr2O3(s)
- 1139.7
- 1058.1
C(s, graphite)
5.69
81.2
CC4(8)
-106.7
-64.0
309.4
Cobalt
CCI,(1)
- 139.3
-68.6
214.4
Co(g)
439
393
179
CF4(8)
-679.9
-635.1
262.3
Co(s)
28.4
CH4(8)
- 74.8
-50.8
186.3

Practice Exercise 2
Write the equation corresponding to the standard enthalpy of
formation of liquid carbon tetrachloride (CCI4) and look up
AH for this compound in Appendix C.

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