Write a Python loop that will start at 100 and count backwards by 2's (98, 96...) to 54. HOWEVER, I also want it to skip every third printout: 98, 96, , 92, 90, ,86.

Second Time I have submitted this. The first time was an incorrect answer.  I don't know what I did wrong with "Test digitCount(0) and how to fix it.

Which is more likely to be dropped at line end? Why is it gone?

you are missing the zero,running and stopped boolean expression. Please check the above solution.

what  is  If...Then...Else statement ?

A variable like userNum can store a value like an integer. Extend the given program as indicated. 1. Output the user's input. (2 pts) 2. Output the input squared and cubed. Hint: Compute squared as userNum * userNum. (2 pts) 3. Get a second user input into userNum2, and output the sum and product. (1 pt) Note: This zyLab outputs a newline after each user-input prompt. For convenience in the examples below, the user's input value is shown on the next line, but such values don't actually appear as output when the program runs. Enter integer: 4 You entered: 4 4 squared is 16 And 4 cubed is 64!! Enter another integer: 4 + 5 is 9 4 * 5 is 20 367012.2549490.qx3zgy7 LAB 2.13.1: LAB: Warm up: Basic output with variables 0/5 ACTIVITY OutputWithVars.java Load default template... 1 import java.util.Scanner; 2 3 public class OutputWithVars { public static void main(String[] args) { Scanner scnr = new Scanner(System.in); int userNum; 4 7 8 System.out.println("Enter integer:"); userNum =…