Database System Concepts
Database System Concepts
7th Edition
ISBN: 9780078022159
Author: Abraham Silberschatz Professor, Henry F. Korth, S. Sudarshan
Publisher: McGraw-Hill Education
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Question
Write a program that determines the number of years it will take a home to double in value given the current value of the home and the
predicted appreciation rate.
Example A
interleaved input and output with inputs 100000 and 0.042
Enter home value: 100000
Enter appreciation rate (3.8% enter as 0.038):0.042
It will take about 17 years to double in value.
Example B
interleaved input and output with an invalid input value:
Enter home value: 10000000
Enter appreciation rate (3.84 enter as 0.038) : unknown
Unexpected value: unknown
Algorithm
For example, for a home valued at $100,000 and a predicted appreciation rate of 3.8%, we could start writing the code as:
home Value - 100000.0;
years = 0;
//after one year
home value homeValue+ homeValue 0.038;
years++;
//after two years
home value homeValue+ homeValue 0.038;
years++;
//after three years
homeValue homeValue+ homeValue 0.038;
years++;
//... keep going until the home value doubles the initial value. What kind of loop would be
most appropriate here?
after 19 years the value is anticipated to be about $203,118, so it takes 19 years to double.
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Transcribed Image Text:Write a program that determines the number of years it will take a home to double in value given the current value of the home and the predicted appreciation rate. Example A interleaved input and output with inputs 100000 and 0.042 Enter home value: 100000 Enter appreciation rate (3.8% enter as 0.038):0.042 It will take about 17 years to double in value. Example B interleaved input and output with an invalid input value: Enter home value: 10000000 Enter appreciation rate (3.84 enter as 0.038) : unknown Unexpected value: unknown Algorithm For example, for a home valued at $100,000 and a predicted appreciation rate of 3.8%, we could start writing the code as: home Value - 100000.0; years = 0; //after one year home value homeValue+ homeValue 0.038; years++; //after two years home value homeValue+ homeValue 0.038; years++; //after three years homeValue homeValue+ homeValue 0.038; years++; //... keep going until the home value doubles the initial value. What kind of loop would be most appropriate here? after 19 years the value is anticipated to be about $203,118, so it takes 19 years to double.
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