Write a c++ program that accepts three non-negative integers from the user and print true if two or more of them (Integers) have the same rightmost digit. e.g. Input the first number: 5 Input the second number: 10 Input the third number: 15 The result is: true

Write code that iterates while userNum is less than 12. Each iteration: Put userNum to output. Then, put "/" to output. Then, assign userNum with userNum multiplied by 3.

*Modify the program so that the user will error trap for only 1 and 0 as an input.   *If the user enters an input other than 1 or 0 display an error message and request the user enter that input again.  *Do this for all inputs in the code.     # User defined function for logic OR# The function takes two parameters and returns a single intdef OR(a: int, b: int)->int:# If a is equal to 1 return 1if a == 1 :return 1# If b is equal to 1 return 1elif b == 1 :return 1# If a and b is equal to 0 return 0else :return 0 # User defined function for logic NOR# The function takes two parameters and returns a single intdef NOR(a: int, b: int)->int:# If a is equal to 0 and b is also equal to 0 return 1if a == 0 and b == 0 :return 1# If a is equal to 0 and b is equal to 1 return 0elif a == 0 and b == 1 :return 0# If a is equal to 1 and b is also equal to 0 return 0elif a == 1 and b == 0 :return 0# If a is equal to 1 and b is also equal to 1 return 0elif a == 1 and b == 1 :return 0 # User defined…

Write in c++ please