work, = mv; -mv; 13.1 1-2 where m is the mass of the object and V, and V, are the speed of the object at positions 1 and 2, respectively. To better demonstrate Equation (13.1), consider the following example. When you push on a lawn mower, which is initially at rest, you perform mechanical work on the lawn mower and move it, consequently changing its kinetic energy from a zero value to some nonzero value. (km ){ 1h }1000 m 90 h {3600 s jl 1 km V, = V 25 m initial V2 = V. = 0 tinal work, , = (force)(distance) = -mV? --mv? (force)(100 m) = 0 -;(1400 kg)|25 kel/25 force = -4375 N

Engineering Fundamentals: An Introduction to Engineering (MindTap Course List)
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ISBN:9781305084766
Author:Saeed Moaveni
Publisher:Saeed Moaveni
Chapter18: Mathematics In Engineering
Section: Chapter Questions
Problem 23P
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Determine the net force needed to bring a car that is traveling at 90 km/h to
a full stop in a distance of 100 m. The mass of the car is 1400 kg. We begin the analysis by first changing the units of speed to m/s and then
use as shown to analyze the problem.

work, = mv; -mv;
13.1
1-2
where m is the mass of the object and V, and V, are the speed of the object
at positions 1 and 2, respectively. To better demonstrate Equation (13.1),
consider the following example. When you push on a lawn mower, which is
initially at rest, you perform mechanical work on the lawn mower and move it,
consequently changing its kinetic energy from a zero value to some nonzero
value.
Transcribed Image Text:work, = mv; -mv; 13.1 1-2 where m is the mass of the object and V, and V, are the speed of the object at positions 1 and 2, respectively. To better demonstrate Equation (13.1), consider the following example. When you push on a lawn mower, which is initially at rest, you perform mechanical work on the lawn mower and move it, consequently changing its kinetic energy from a zero value to some nonzero value.
(km ){ 1h }1000 m
90
h {3600 s jl 1 km
V, = V
25 m
initial
V2
= V.
= 0
tinal
work, , = (force)(distance) = -mV? --mv?
(force)(100 m) = 0 -;(1400 kg)|25
kel/25
force = -4375 N
Transcribed Image Text:(km ){ 1h }1000 m 90 h {3600 s jl 1 km V, = V 25 m initial V2 = V. = 0 tinal work, , = (force)(distance) = -mV? --mv? (force)(100 m) = 0 -;(1400 kg)|25 kel/25 force = -4375 N
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