Women athletes at a certain university have a long-term graduation rate of 67%. Over the past several years, a random sample of 38 women athletes at the school showed that 21 eventually graduated. Does this indicate that the population proportion of women athletes who graduate from the university is now less than 67%? Use a 1% level of significance.   State the null and alternate hypotheses. H0: p = 0.67; H1: p < 0.67 H0: p = 0.67; H1: p > 0.67     H0: p = 0.67; H1: p ≠ 0.67 H0: p < 0.67; H1: p = 0.67   What sampling distribution will you use? The standard normal, since np < 5 and nq < 5. The Student's t, since np > 5 and nq > 5.     The standard normal, since np > 5 and nq > 5. The Student's t, since np < 5 and nq < 5.     What is the value of the sample test statistic? (Round your answer to two decimal places.)   Find the P-value of the test statistic. (Round your answer to four decimal places.)     Based on your answers in parts (a) to (c), will you reject or fail to reject the null hypothesis? Are the data statistically significant at level ??   At the ? = 0.01 level, we reject the null hypothesis and conclude the data are statistically significant. At the ? = 0.01 level, we reject the null hypothesis and conclude the data are not statistically significant.     At the ? = 0.01 level, we fail to reject the null hypothesis and conclude the data are statistically significant. At the ? = 0.01 level, we fail to reject the null hypothesis and conclude the data are not statistically significant

USA Today reported that about 47% of the general consumer population in the United States is loyal to the automobile manufacturer of their choice. Suppose Chevrolet did a study of a random sample of 1002 Chevrolet owners and found that 490 said they would buy another Chevrolet. Does this indicate that the population proportion of consumers loyal to Chevrolet is more than 47%? Use a = 0.01. (a) What is the level of significance? State the null and alternate hypotheses. O Ho: p > 0.47; H,: p = 0.47 Ho: p- 0.47; H,:p- 0.47 O Ho:p = 0.47; H,:p > 0.47 O Ho:p = 0.47; H,:p 5 and ng > 5. The standard normal, since np 5 and ng > 5. What is the value of the sample test statistic? (Round your answer to two decimal places.) (c) Find the P-value of the test statistic. (Round your answer to four decimal places.) Sketch the sampling distribution and show the area corresponding to the P-value. -1 1 -2 -1 1 2 -1 0 0 1 -2 2 3 (d) Based on your answers in parts (a) to (c), will you reject or fail to…

part d dropdown: at least .55 or less than .55                             did not provide or provided                             should or should not

Getting enough sleep. 400 students were randomly sampled from a large university, and 289 said they did not get enough sleep. Conduct a hypothesis test to check whether this represents a statistically significant difference from 50%, and use a significance level of 0.01. NB: Use confidence interval

Determine the null and alternative hypotheses. Choose the correct choice below.     A. H0​: The expected frequencies are all equal to 5. Ha​: At least one expected frequency differs from 5.   B. H0​: The distribution of the variable is the same as the given distribution. Ha​: The distribution of the variable differs from the given distribution.   C. H0​: The distribution of the variable differs from the normal distribution. Ha​: The distribution of the variable is the normal distribution.   D. H0​: The distribution of the variable differs from the given distribution. Ha​: The distribution of the variable is the same as the given distribution.   Compute the value of the test​ statistic, χ2.   χ2= ​(Round to three decimal places as​ needed.)   Find the​ P-value.   P= ​(Round to three decimal places as​ needed.) Does the data provide sufficient evidence that the distribution of the variable differs from the given​ distribution?       A. No​,…

The Gallup Poll asked 1015 U.S. adults whether they believed that people should pay sales tax on items purchased over the internet. Of these, 477 said they supported such a tax. Does the survey provide convincing evidence that less than 42% of U.S. adults favor an internet sales tax? Use the 0.05 level of significance.    1. STATE THE NULL AND ALTERNATIVE HYPOTHESIS: 2. T STATISTIC/ P VALUE 3.REJECT OR FAIL THE NULL HYPOTHESIS 4. IS THE CLAIM SUPPORTED AT THE 0.05 LEVEL OF SIGNIFICANCE?

In the fictional city of Statisticsville, last year residents spent an average of $12 per month using grocery pickup services (where you purchase groceries online and then drive to the store to pick them up). A journalist wants to know if people today in the (fictional) city of Statisticsville are spending more per month on average compared to last year. Her hypotheses are: Hoi u =12 HA: H> 12 She selects a random sample of 89 people at a large public space in Statisticsville and finds their average spending per month on grocery pickup fees is $12.19 with a standard deviation of $4.15. All necessary assumptions and conditions have already been checked and were met. 1) What are the degrees of freedom (DF) for the t-distribution for performing this hypothesis test? 88 (Enter an integer answer.) 2) What is the value of the t-statistic for performing this hypothesis test? (Round your answer to 2 decimal places.) 3) Which of the following statements about the value is most appropriate? (You…

Historically, the proportion of students entering a university who finished in 4 years or less was 65%. To test whether this proportion has decreased, 150 students were examined and 58% had finished in 4 years or less. At the 5% level of significance, does it appear the proportion has decreased from its historical level? To determine whether the proportion of students who finish in 4 year or less has statistically significantly decreased, what is the null and alternative hypothesis?

-a system that takes  4.5 years, on average, to finish -suppose you believe that the mean time is longer. -you conduct a survey of 40 students -a sample mean of 5.1 w/ a sample standard deviation of 1.2. -claim at the 1% level? null hypothesis is : Ho: µ≤4.5 alternative hypothesis is: Ha: µ > 4.5 the test statist is: t = 3.175 But what does the p-value = ?

Test the claim that the proportion of people who own cats is smaller than 60% at the 0.025 significance level. The null and alternative hypothesis would be: Ho: p=0.6 Ho:μ ≥ 0.6 Ho: p 0.6 The test is: left-tailed right-tailed two-tailed Based on a sample of 600 people, 53% owned cats The test statistic is: The p-value is: Based on this we: Ho:p>0.6 Ho: 0.6 Ho: μ 0.6 Reject the null hypothesis O Fail to reject the null hypothesis (to 2 decimals) (to 2 decimals) =