With a plate count average of 297 and a final dilution on the plate of 1:1,000 ; what is the viable number of cells in original culture (CFU/ml)?

How much serum is needed to create 2μL of a 1:20 dilution?

why is the recommended incubation procedure for the API 20e system 18 to 24 hours ?

Human error is a factor in the Kirby-Bauer procedure that often contributes to variation in zone size. Circle the effect on the zone size if the following occurred: ● ● Overinoculating the agar with bacteria: Waiting too long to place disks after inoculation: Using a culture that is less than 0.5 MacFarland: False increase False increase False increase False decrease False decrease False decrease

So would it be 22kD after conversion? Option are in kD. 67, 52, 22, and 13kD

A culture of S. cerevisea has an overnight OD of 2.3 (1.0 OD is approx 1.0x107 cells/ml) You will be plating 100µl onto agar and want the final count of colonies on the plate to be around 300 colonies.  How much of the 2.3 OD culture must you use to get a 500µl subdilution (with sterile water), so that you have diluted enough to get approx 300 colonies per 100ul

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Helping tags: Biology, bacterial count, dilution, serial dilution WILL UPVOTE, just pls help me answer the following questions and explain them clearly. Pls show complete solutions also for the computation part. Thank you. 1. A bacterial culture was grown for 9 hours. At 3-hour interval, the culture was sampled to determine the population of the culture, by transferring 25 ml of the suspension to 225 ml 0.85% NaCl. Three consecutive dilutions were further made by using 1 ml aliquot in 9 ml of 0.85% NaCI. One ml from each dilution was plated in each of duplicate plates. The following table shows the results of the plating method. Sampling COUNTS 2nd dilution 3rd dilution 4th dilution 0,0 30: 35 250;245 1st dilution 1st 2nd 3rd 0; 0 240; 235 TNTC 55; 60 5; 6 TNTC TNCT TNTC TNTC a) Illustrate the dilution series used and label the final dilution of each dilution. b) Determine the bacterial count (CFU/ml) every 3 hours of incubation for 9 hours. Show all computations.

Why is a viable count more sensitive than a microscopic count?What major assumption is made in relating plate count resultsto cell number?

A phagehunter performs a full plate titer using standard techniques (100 ul of each dilution added to 250 ul of Gordonia terrae cells) of a lysate obtained from an optimum webbed plate experiment. The phagehunter counts 72 plaques on the 10-7 dilution plate. Which of the following scenarios is the best choice for the phagehunter to do next? a.) The phagehunter has not achieved a high enough titer lysate to move forward with characterization experiments, so they should adopt a phage from direct isolation. b.) The phagehunter has not achieved a high enough titer lysate to move forward with characterization experiments, so they should go back to the pick-a-plaque experiment. c.) The phagehunter has achieved a high enough titer lysate to move forward with characterization experiments. d.) The phagehunter has not achieved a high enough titer lysate to move forward with characterization experiments, so they should try to make more optimum webbed plates.