Which statement(s) are typically true for an SN1 reaction? Check all that apply. It occurs with inversion of stereochemistry b.t occurs with racemization The reaction rate is higher in a more polar solvent C. d. It proceeds via the most stable carbocation intermediate Using a bulky or hindered base will improve the yield of product е.

It takes three separate steps to convert the starting material shown here to the final product. In the answer box below, please tell me: a. The reagent(s) for the step marked 1 b. The NAME of the intermediate that goes in box A c. The reagent(s) for the step marked 2 d. The name of the new FUNCTIONAL GROUP that is present in the intermediate that goes in box B e. The reagent(s) for the step marked 3 OH A В 1 2 3 H.

Change the structure below to show the most stable form of this carbocation intermediate.

Curved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow the arrows to draw the intermediate and product in this reaction or mechanistic step(s). Include all lone pairs and charges as appropriate. Ignore stereochemistry. Ignore inorganic byproducts.

Figure 9-5 Alkenes Alkyl halides Br. 1 A рез Br В 3 Br Y с А Br

Show and label the mechanism for the SN1 reaction using the generic chemical species and electron movement. Notice that the reaction does not include a negative charge on the nucleophile.

Dehydration of alcohols is the reverse reaction of the hydration of an alkene. Typical reaction conditions include heating the alcohol in the presence of a strong acid, which will produce an alkene product. In this tutorial we will explore 1. the dehydration of secondary and tertiary alcohols 2. when mixture of products are expected and how to determine the major product 3. when rearrangements are expected and how to determine the major product 4. the dehydration of primary alcohols Put it all together. The alcohol shown can form several dehydration products. Draw the major dehydration product. If cis or trans alkene isomers are formed, clearly draw the major isomer. OH H₂SO4

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