Which of the hypothetic equations below is incorrectly balanced:   a. 2 X + 3 Y2Z4  → 1 X2 (Z4)3 + 6 Y2   b. 2 D2F4G + 5 G2 → 4 DG2 + 4 F2G   c. 2 KLMN3  → 1 K2MN3 + 1 MN2 + 1 L2N   d. 1 J12B22C11 → 12 J + 11 B2C   e. 1 ABC4 → 1 AB + 2 C

Rank the following groups in the order of decreasing priorities in nomenclature. OH OH 'H. 11 12 13 14 15 A. 11 > 12 > 13 > 14 > 15 В. 15 11 > 12 > 14 13 > С. 13 14 > 12 > 15 > 11 D. 13 14 > 12 > 11 > 15 E. 15 14 > 13 > 12 > 11 High priority Low priority of

O Reagents Available a. CH₂=CHCH₂CI, AICI 3 CH3 b. CH₂Br₂, OH™ C. CH3CH₂COCI, AICI 3 d. H₂, Pt e. NBS, CCI4 f. K* tBuO™ g. CO, HCI, CUCI/AICI3 h. CH3CH₂CH₂COCI, AICI 3 i. BrCH₂CH₂Br, OH- j. CH3CH₂CI, AICI 3 k. RCO3H I. H3O+ Using conditions from the table, show how you would synthesize this compound from catechol (1,2-benzenediol). Select reagents from the table in the order that you wish to use them, i.e. aced; do not include punctuation or spaces. If more than one route exists, choose the shorter one; in no case will a synthesis require more than 5 steps.

The following transformation can be accomplished by using the provided below (table) complete the statement regarding the reaction below. Write the letter in UPPERCASE corresponding to the reagents from the reagents pool below. 0901 A) H2SO4, H2O B) Br2, CCl4 set of reagents. Using the pool of reagents C) (0)Hg(OAc)2, H20 (1) NaBH4, NaOH D) i) 03 ) (CH3)2S H) HBr peroxide (1) BH3, THF ) H202, NaOH Ji) KMnO4, warm, conca. K) Br2, H2O LIOL

Write Ksp for Ca3 (PO4)2 salt ... a. [Ca2+]3 [PO4]² b. [Ca2+] [PO43-1² c. [Ca]³ [PO43-]? d. [Ca2+]² [PO43-13 e. [Ca2+]3 [PO43-1?

31 Show below is the change of glucose from the linear form to the ring form, which typically occurs in water. Which of the following statements is correct? н 17 НО CH₂OH ON H OH a Glucose OH H-C-OH HO-C-H H-C-OH H-C-OH H-C-OH H Н HO CH₂OH Н OH H OH 1 H Н ОН B Glucose The isotopes of glucose are modified in this reaction When the ring forms, two isomers can form, alpha and beta, each has a different shape When the ring forms, two isomers can form, alpha and beta, but the shapes are identical and there is no difference in these two forms. The resulting glucose isomers can not form polysaccardies.

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K²=32 2016 #H HE M = PENNS 00.5 = [14] (MOOS = [V] [MOLO FAVOROins nos 40241 23 enorpos 09 10 1011 3 MUNGHOUD? 1D 21 NT A 00091 907 559100 21 no inw 1/09 2000 200 DAD91 SNT 8 SNT.S (s) + 6C1₂ (9) = 4P(|3 (9) P₁ Express the equalibrium constant for this reaction

You are a forensic scientist. You are investigating a murder involving poison. The victim was poisoned with a compound called di-chlorobenzene, whose formula is C6H4Cl2. Autopsy results show that the victim’s body contained about 27.5 g of the poison, but the actual amount could have been slightly higher due to tissue absorption. The main suspect is his wife, Suzanne, who works as a chemistry professor. Records show that she purchased 15 g of benzene (C6H6) two days before the murder. Benzene is one of the compounds use to make the poison. She claims she was using it to make methyl benzene (C6H5CH3), an innocuous compound, for use in her lab. She shows you the bottle of methyl benzene she claims to have made. It contains 25 g of methyl benzene. To produce di-chlorobenzene, the reaction is:       Cl2(g)  +  C6H6(l) ⟶⟶ C6H4Cl2(l) + H2(g) To produce methyl benzene, the reaction is:          CH4(g) + C6H6(l) ⟶⟶ C6H5CH3(l) + H2(g)   Use stoichiometry to solve this case. Be sure to show all…