Which of the following would NOT be characteristic of a single-source non-compromised STR profile? Group of answer choices A. No more than two (2) allelic peaks at any locus. B. Well-balanced heterozygote peaks. C. Sharply pointed peaks with even spectral distribution D. Well-defined smooth peaks with a bell-shaped distribution.
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Which of the following would NOT be characteristic of a single-source non-compromised STR profile?
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- Astigmatism and polydactyly are dominant over normal vision and finger traits. Sickle-cell anemia onthe other hand, is an overdominant lethal trait due to its recessive genes (ss). Individuals with this traitdie prematurely. Heterozygotes (Ss), however, have some RBCs that sickle while others remainnormal, thus, not lethal. They are referred to as sickle-trait carriers. A polydactylous, normal-visioned, brown-eyed man with wavy hair has a nonpolydactylous, blue-eyed mother. He proposed marriage to a nonpolydactylous, astigmatic, blue-eyed, and curly-hairedlady whose mother has normal vision. However, the lady is worried about the proposal since sickle-cell anemia has been known to run in both their families. a. Is there a genetic basis for her worry? Explain. b. If it turned out that the lady is a carrier and the man has normal RBC, what would be their COMPLETE genotypes? Male genotype:_________________________________Female genotype: ______________________________ c. Based on their…Use the scoring system described to calculate the alignment score for IPNI AAIG DV VAGP VKGIYA VG DV C-GK Scoring system: • Each identity results in +10 points. • Each gap has a penalty of -25 points. score = What is the percent identity (also called percent identity match)? percent identity: %Astigmatism and polydactyly are dominant over normal vision and finger traits. Sickle-cell anemia onthe other hand, is an overdominant lethal trait due to its recessive genes (ss). Individuals with this traitdie prematurely. Heterozygotes (Ss), however, have some RBCs that sickle while others remainnormal, thus, not lethal. They are referred to as sickle-trait carriers. A polydactylous, normal-visioned, brown-eyed man with wavy hair has a nonpolydactylous, blue-eyed mother. He proposed marriage to a nonpolydactylous, astigmatic, blue-eyed, and curly-hairedlady whose mother has normal vision. However, the lady is worried about the proposal since sickle-cell anemia has been known to run in both their families. a. Is there a genetic basis for her worry? Explain. b. If it turned out that the lady is a carrier and the man has normal RBC, what would be their COMPLETE genotypes? Male genotype:_________________________________Female genotype: ______________________________ c. Based on their…
- A couple consulted a genetic counselor and they found out the following: Basha: A blood type, blue eye color, normal skin condition, carrier of cystic fibrosis gene, and carrier of hemophilia gene Popoy: B blood type, has brown eye color, normal skin condition, carrier of cystic fibrosis gene and negative to hemophilia. Clues for the table: • Blood Type: The probability that they’ll have an offspring with blood type the same as Popoy is 25% only • Eye Color: The probability that they’ll have an offspring with brown eye color is 75%. • Skin condition: The probability that their offspring will be an albino is 25% What is the probability that the offspring will have/ be: A. a girl with all the same phenotype as her mother. B. 2 girls with neither the blood type of the parents. C. 2 boys with normal skin color and carrier of cystic fibrosis gene; 1 girl with normal skin color and negative to cystic fibrosis. D. 2 girls carrier of both cystic fibrosis gene and hemophilia, a boy † positive…For Cross 1 F1: Do the observed data match prediction? Conduct a chi-square goodness-of-fit test; a. State the hypothesis you are testing clearly b. Report the chi-square statistic valueSwitch Background P Immersive Reader 100% Page Width d. What percent of the offspring will be carriers of the white eye trait? 2. Using the same information as for question #1, cross a heterozygous red-eyed female with a red-eyed male. a. What are the genotypes of each parent? ic b. What fraction of the children will have red eyes? c. What fraction of the children will have white eyes? Pra d. What fraction of the female children will carry the white eyed trait?
- An individual has the following genotype. Gene loci (A) and (B) are 15 m.u. apart. What are the correct frequencies of some of the gametes that car be made by this individual? Bl a O A. Ab = 7.5%; AB = 42.5% B. ab = 25%; aB = 50% O C. AB = 7.5%; aB = 42.5% O D. aB = 15%; Ab = F0% E. aB = 70%; Ab = 15% Reset Selection OMark for Review What's This?The S-s antigen system in humans is controlled by two codominant alleles S and s. In a group of 3146 individuals the following genotypic frequencies were found:188 SS, 717 Ss, and 2241 ss. The chi-square value of this test is?The degrees is freedom value is ?Using a significance level of 0.5 the chi-critical value is? from this chi- squar chi-square test is it significant or non significant is the nul hypothesis of HWE accepted or rejectedA group of people are studiedd with made up blood types AZ blood group which is a blood type controlled by a single gene with two loci. Indivuals in this group may be “D” ( = that their homozygous for the “D” allele) “Z” = homozygous for the “z” allele. *DZ= Heterzygous ** Total Number of people with each type 102 people have D type blood 96 have blood type DZ 31 people in this group have type “Z” QUESTION Now please calculate the allele frequencies of “D”and “Z” In doing so use variable “P”= to represent “D” allele And “q”= to represent “Z” allele Calculate the genotype frequencies expected in the population based of the q and p frequencies you calculate. A)frequency of the “Z” allele in the population ________ B)Frequency of the “D” allele in the populations__________ C)A number of expected individuals with the “DD” genotype in the population? __________ D) NUMBER OF EXPECTED INDIVIDUALS WITH THE “ZZ” GENOTYPE IN THE POPULATION?_______ E) A NUMBER OF EXPECTED…
- Genotypic %: Phenotypic %: 3. Cross a man with type B heterozygous blood with a woman with type O blood, What are the possible genotypes and phenotypes of their offspring? Genotypes: Phenotypes: 4. Klariz, a 28-year-old woman with type O blood and Ricci, a 30-year-old man with type AB blood are expecting a child. What are the possible blood types of the kid? Show your solution using Punnett Square. Phenotypes: 5. Mrs. Lopez has type B blood. Mr. Lopez has type O blood. Their son Michael has type O blood. Make a Punnett square to show what Mrs. Lopez's genotype must be to have a child with type O blood. Mrs. Lopez's genotype:Please ASAP. Thank you. The following diagram represents the results of hemoglobin samples of 5 patients (1-5) that were run on an electrophoresis gel at pH 9.2. The first 3 lanes show the control samples, for comparison. Consider Patient 4 and Patient 5. If patient 2 is female and patient 5 is a male, and they conceive a child together, what is the chance that the child will have sickle cell anemia (the disease)? Give your answer as a percentage (%)Assuming both hemophilia and red-green colorblindness are rare traits, who is doubly heterozygous for sure? (Select all that apply.) Male Female O Hemophilia A O Hemophili t 申? Color-blind IV HA Hemophili and color-blind None O II-2 fermale O III-4 female O Il-1 female O 1-2 female 由一